Concept explainers
(a)
Interpretation:
pH corresponding to [OH]−= 8.63 ×10−3M is to be calculated and whether the solution is acidic, basic or neutral is to be indicated.
Concept Introduction:
- pH is a logarithmic scale which specify the acidity or basicity of the solution.
- Neutral solution- A solution is neutral if pH=7
- Acidic solution- A solution is acidic if pH<7
- Basic solution- A solution is basic if pH>7
pH=−log[H+]
pOH = −log [OH]−pH + pOH = 14
Answer to Problem 44QAP
pH = 11.94 so, the solution is basic in nature.
Explanation of Solution
As [OH]−= 8.63 ×10−3M
pH + pOH = 14pH = 14 − (−log [OH]−)pH = 14 – (−log 8.63 × 10−3M)pH = 14 – 2.06pH = 11.94
Thus, pH is greater than 7 which implies that the given solution is basic in nature.
(b)
Interpretation:
pH corresponding to [OH]−= 7.44 ×10−6M is to be calculated and whether the solution is acidic, basic or neutral is to be indicated.
Concept Introduction:
- pH is a logarithmic scale which specify the acidity or basicity of the solution.
- Neutral solution- A solution is neutral if pH=7
- Acidic solution- A solution is acidic if pH<7
- Basic solution- A solution is basic if pH>7
pH=−log[H+]
pOH = −log [OH]−pH + pOH = 14
Answer to Problem 44QAP
pH = 8.87 so, the solution is basic in nature.
Explanation of Solution
As [OH]−= 7.44 ×10−6M
pH + pOH = 14pH = 14 − (−log [OH]−)pH = 14 – (−log 7.44 × 10−6M)pH = 14 – 5.13pH = 8.87
Thus, pH is greater than 7 which implies that the given solution is basic in nature.
(c)
Interpretation:
pH corresponding to [OH]−= 9.35 × 10−9M is to be calculated and whether the solution is acidic, basic or neutral is to be indicated.
Concept Introduction:
- pH is a logarithmic scale which specify the acidity or basicity of the solution.
- Neutral solution- A solution is neutral if pH=7
- Acidic solution- A solution is acidic if pH<7
- Basic solution- A solution is basic if pH>7
pH=−log[H+]
pOH = −log [OH]−pH + pOH = 14
Answer to Problem 44QAP
pH = 5.97 so, the solution is acidic in nature.
Explanation of Solution
As [OH]−= 9.35 × 10−9M
pH + pOH = 14pH = 14 − (−log [OH]−)pH = 14 – (−log 9.35 ×10−9M)pH = 14 – 8.03pH = 5.97
Thus, pH is less than 7 which implies that the given solution is acidic in nature.
(d)
Interpretation:
pH corresponding to [OH]−= 1.21 × 10−11M is to be calculated and whether the solution is acidic, basic or neutral is to be indicated.
Concept Introduction:
- pH is a logarithmic scale which specify the acidity or basicity of the solution.
- Neutral solution- A solution is neutral if pH=7
- Acidic solution- A solution is acidic if pH<7
- Basic solution- A solution is basic if pH>7
pH=−log[H+]
pOH = −log [OH]−pH + pOH = 14
Answer to Problem 44QAP
pH = 3.08 so, the solution is acidic in nature.
Explanation of Solution
As [OH]−= 1.21 × 10−11M
pH + pOH = 14pH = 14 − (−log [OH]−)pH = 14 – (−log 1.21 × 10−11M)pH = 14 – 10.92pH = 3.08
Thus, pH is less than 7 which implies that the given solution is acidic in nature.
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