Explanation Given information: The system of equations is as follows. 6 x + 6 y − 3 z = 24 x + 4 y + 2 z = 5 3 x − 2 y + z = 17 Calculation: The system of equations in the form of A X = C . Provide the matrix A and C for the system of equations as shown below. A = [ 6 6 − 3 1 4 2 3 − 2 1 ] C = [ 24 5 17 ] Calculate the inverse of matrix A ( A − 1 ) using Gauss-Jordan elimination method as shown below. Transform [ A | I ] into [ I | A − 1 ] . Substitute [ 6 6 − 3 1 4 2 3 − 2 1 ] for A , [ 1 0 0 0 1 0 0 0 1 ] for I , and apply the row operations as follows. [ 6 6 − 3 1 4 2 3 − 2 1 | 1 0 0 0 1 0 0 0 1 ] = [ 1 1 − 1 2 1 4 2 3 − 2 1 | 1 6 0 0 0 1 0 0 0 1 ] R 1 → 1 6 R 1 = [ 1 1 − 1 2 0 3 5 2 0 − 5 5 2 | 1 6 0 0 − 1 6 1 0 − 1 2 0 1 ] R 2 → R 2 − R 1 R 3 → R 3 − 3 R 1 = [ 1 1 − 1 2 0 1 5 6 0 − 5 5 2 | 1 6 0 0 − 1 18 1 3 0 − 1 2 0 1 ] R 2 → R 2 3 = [ 1 0 − 4 3 0 1 5 6 0 0 20 3 | 2 9 − 1 3 0 − 1 18 1 3 0 − 7 9 5 3 1 ] R 1 → R 1 − R 2 R 3 →

Basic Technical Mathematics with Calculus (11th Edition)

11th Edition

ISBN: 9780134437736

Author: Allyn J. Washington, Richard Evans

Publisher: PEARSON

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Chapter 16, Problem 36RE

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Solve the system of equations using inverse of the coefficient matrix.

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Chapter 16, Problem 35RE

Chapter 16, Problem 37RE

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Chapter 16 Solutions

Basic Technical Mathematics with Calculus (11th Edition)

Ch. 16.1 - For matrices A and B, find A + B. Ch. 16.1 - Prob. 2PE Ch. 16.1 - Prob. 3PE Ch. 16.1 - Prob. 1E Ch. 16.1 - Prob. 2E Ch. 16.1 - Prob. 3E Ch. 16.1 - Prob. 4E Ch. 16.1 - In Exercises 3–10, determine the value of the...Ch. 16.1 - Prob. 6E Ch. 16.1 - Prob. 7E

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