a. Explanation Given : It is given in the question that the logistics difference equation the factor ( 1 − x t ) decreases linearly from 1 t o 0 as x t increases from 0 t o 1 .We have an decreased exponential factor e − x t and the equation is : x t + 1 = c x t e − x t and it is also given that x 0 = 0.5 , c = 2.5 . Concept Used: In this we have to know about the concept of difference equation. We have to use the equation of x t + 1 = c x t e − x t b. To determine Compare the value of the equation with the mentioned exercise.

15th Edition

ISBN: 9781305420878

Author: Stewart

Publisher: CENGAGE L

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Differential Equations

Have you ever observed the movement of the satellites and rockets or how the planets go around the sun in their orbits? How will you determine their motion? Definitely they follow some scientific laws and these kinds of problems are framed as differentia…

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Chapter 1.6, Problem 32E

To determine

Calculate the first ten terms of the equation to four decimal places and graph them.

To determine

Compare the value of the equation with the mentioned exercise.

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Chapter 1.6, Problem 31E

Chapter 1.6, Problem 33E

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Chapter 1 Solutions

BIOCALCULUS:CALCULUS F/LIFE...-W/ACCESS

Ch. 1.1 - Prob. 1E Ch. 1.1 - Prob. 2E Ch. 1.1 - Prob. 3E Ch. 1.1 - Prob. 4E Ch. 1.1 - Prob. 5E Ch. 1.1 - Prob. 6E Ch. 1.1 - Prob. 7E Ch. 1.1 - Prob. 8E Ch. 1.1 - Prob. 9E Ch. 1.1 - Prob. 10E

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Calculate the first ten terms of the equation to four decimal places and graph them.

Solution Summary: The author explains how to calculate the first ten terms of the equation to four decimal places and graph them.

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Calculate the first ten terms of the equation to four decimal places and graph them.

Compare the value of the equation with the mentioned exercise.

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Chapter 1 Solutions