Explanation Given: x 0 = 0.5 And c = 3.7 Consider the logistic difference equation x t + 1 = c x t ( 1 − x t ) with x 0 = 0.5 and c = 1.5 . Substitute t = 1 , 2 , ... , 10 to find the corresponding value of x t . x 1 = x 0 + 1 = 3.7 x 0 ( 1 − x 0 ) = ( 3.7 ) ( 0.5 ) ( 1 − 0.5 ) = 0.9250 x 2 = x 1 + 1 = c x 1 ( 1 − x 1 ) = ( 3.7 ) ( 0.925 ) ( 1 − 0.925 ) ≈ 0.2567 x 3 = x 2 + 1 = c x 2 ( 1 − x 2 ) = ( 3.7 ) ( 0.2567 ) ( 1 − 0.2567 ) ≈ 0.7060 x 4 = x 3 + 1 = c x 3 ( 1 − x 3 ) = ( 3.7 ) ( 0.7060 ) ( 1 − 0.7060 ) ≈ 0.7681 x 5 = x 4 + 1 = c x 4 ( 1 − x 4 ) = ( 3.7 ) ( 0

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Chapter 1.6, Problem 31E

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To find:the value of xt for t=1,2,...,10 , for the logistic difference equation xt+1=cxt(1−xt) and also graph xt

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Chapter 1.6, Problem 30E

Chapter 1.6, Problem 32E

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Biocalculus: Calculus For Life Sciences

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the value of x t for t = 1 , 2 , ... , 10 , for the logistic difference equation x t + 1 = c x t ( 1 − x t ) and also graph x t

Solution Summary: The author explains how to find the value of x_t for t=1,2,mathrm...,10, for the logistic difference equation, and graphs.

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To find:the value of xt for t=1,2,...,10 , for the logistic difference equation xt+1=cxt(1−xt) and also graph xt

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Chapter 1 Solutions