Explain the meaning of p ^ = 0.49 in this situation.

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 16, Problem 1E

a.

To determine

Explain the meaning of p^=0.49 in this situation.

a.

Expert Solution

Explanation of Solution

In Pew research, the random sample of 799 U.S. teens about the internet usage reports that 49% teens misrepresented their age online to access websites and online services.

Let p be the population proportion of the U.S teens who misrepresented their age and p^ acts as the best estimate of p.

Here, p^ be the sample proportion and it denotes the proportion of the U.S teens who said they have misrepresented their age online to gain access to websites and online services.

The p^=0.49 means that, 49% out of 799 U.S. teens in the sample stated that they misrepresented their age online to gain access to websites and online services. The proportion of the U.S teens who said they have misrepresented their age online to gain access to websites and online services is the best estimate of p.

b.

To determine

Find the standard error of p^.

b.

Expert Solution

Answer to Problem 1E

The standard error of p^ is 0.018.

Explanation of Solution

Calculation:

Standard error:

If the standard deviation of a sampling distribution is estimated by using statistics of the data, the estimate is termed as standard error.

SE(p^)=p^q^n

Where, n be the number of samples, p^ be the sample proportion and q^=1−p^.

Substitute p^ as 0.49, q^ as 0.51(=1−0.49) and n as 799 in the formula,

SE(p^)=0.49(0.51)799=0.2499799=0.0003128≈0.018

Thus, the standard error of p^ is 0.018.

c.

To determine

Explain what the standard error in this context.

c.

Expert Solution

Explanation of Solution

Interpretation:

Here the value of p is not known. Therefore p^ is used to estimate the standard deviation of the sampling distribution.

When 799 teens are asked whether they misrepresented their age online to gain access to websites and online services, the standard error is the estimate that helps to know the amount of variation in the sample proportion between one sample to another sample.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

ce- 216 Answer the following, using the figures and tables from the age versus bone loss data in 2010 Questions 2 and 12: a. For what ages is it reasonable to use the regression line to predict bone loss? b. Interpret the slope in the context of this wolf X problem. y min ball bas oft c. Using the data from the study, can you say that age causes bone loss? srls to sqota bri vo X 1931s aqsini-Y ST.0 0 Isups Iq nsalst ever tom vam noboslios tsb a ti segood insvla villemari aixs-Yedi

120 110 110 100 90 80 Total Score Scatterplot of Total Score vs. Putts grit bas 70- 20 25 30 35 40 45 50 Putts

10 15 Answer the following, using the figures and tables from the temperature versus coffee sales data from Questions 1 and 11: a. How many coffees should the manager prepare to make if the temperature is 32°F? b. As the temperature drops, how much more coffee will consumers purchase?ov (Hint: Use the slope.) 21 bru sug c. For what temperature values does the voy marw regression line make the best predictions? al X al 1090391-Yrit,vewolf 30-X Inlog arts bauoxs 268 PART 4 Statistical Studies and the Hunt for

Answer 2

Question

Chapter 16, Problem 1E

a.

To determine

Explain the meaning of p^=0.49 in this situation.

a.

Expert Solution

Explanation of Solution

In Pew research, the random sample of 799 U.S. teens about the internet usage reports that 49% teens misrepresented their age online to access websites and online services.

Let p be the population proportion of the U.S teens who misrepresented their age and p^ acts as the best estimate of p.

Here, p^ be the sample proportion and it denotes the proportion of the U.S teens who said they have misrepresented their age online to gain access to websites and online services.

The p^=0.49 means that, 49% out of 799 U.S. teens in the sample stated that they misrepresented their age online to gain access to websites and online services. The proportion of the U.S teens who said they have misrepresented their age online to gain access to websites and online services is the best estimate of p.

b.

To determine

Find the standard error of p^.

b.

Expert Solution

Answer to Problem 1E

The standard error of p^ is 0.018.

Explanation of Solution

Calculation:

Standard error:

If the standard deviation of a sampling distribution is estimated by using statistics of the data, the estimate is termed as standard error.

SE(p^)=p^q^n

Where, n be the number of samples, p^ be the sample proportion and q^=1−p^.

Substitute p^ as 0.49, q^ as 0.51(=1−0.49) and n as 799 in the formula,

SE(p^)=0.49(0.51)799=0.2499799=0.0003128≈0.018

Thus, the standard error of p^ is 0.018.

c.

To determine

Explain what the standard error in this context.

c.

Expert Solution

Explanation of Solution

Interpretation:

Here the value of p is not known. Therefore p^ is used to estimate the standard deviation of the sampling distribution.

When 799 teens are asked whether they misrepresented their age online to gain access to websites and online services, the standard error is the estimate that helps to know the amount of variation in the sample proportion between one sample to another sample.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 16, Problem 1E

a.

To determine

Explain the meaning of p^=0.49 in this situation.

a.

Expert Solution

Explanation of Solution

In Pew research, the random sample of 799 U.S. teens about the internet usage reports that 49% teens misrepresented their age online to access websites and online services.

Let p be the population proportion of the U.S teens who misrepresented their age and p^ acts as the best estimate of p.

Here, p^ be the sample proportion and it denotes the proportion of the U.S teens who said they have misrepresented their age online to gain access to websites and online services.

The p^=0.49 means that, 49% out of 799 U.S. teens in the sample stated that they misrepresented their age online to gain access to websites and online services. The proportion of the U.S teens who said they have misrepresented their age online to gain access to websites and online services is the best estimate of p.

b.

To determine

Find the standard error of p^.

b.

Expert Solution

Answer to Problem 1E

The standard error of p^ is 0.018.

Explanation of Solution

Calculation:

Standard error:

If the standard deviation of a sampling distribution is estimated by using statistics of the data, the estimate is termed as standard error.

SE(p^)=p^q^n

Where, n be the number of samples, p^ be the sample proportion and q^=1−p^.

Substitute p^ as 0.49, q^ as 0.51(=1−0.49) and n as 799 in the formula,

SE(p^)=0.49(0.51)799=0.2499799=0.0003128≈0.018

Thus, the standard error of p^ is 0.018.

c.

To determine

Explain what the standard error in this context.

c.

Expert Solution

Explanation of Solution

Interpretation:

Here the value of p is not known. Therefore p^ is used to estimate the standard deviation of the sampling distribution.

When 799 teens are asked whether they misrepresented their age online to gain access to websites and online services, the standard error is the estimate that helps to know the amount of variation in the sample proportion between one sample to another sample.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 16, Problem 1E

a.

To determine

Explain the meaning of p^=0.49 in this situation.

a.

Expert Solution

Explanation of Solution

In Pew research, the random sample of 799 U.S. teens about the internet usage reports that 49% teens misrepresented their age online to access websites and online services.

Let p be the population proportion of the U.S teens who misrepresented their age and p^ acts as the best estimate of p.

Here, p^ be the sample proportion and it denotes the proportion of the U.S teens who said they have misrepresented their age online to gain access to websites and online services.

The p^=0.49 means that, 49% out of 799 U.S. teens in the sample stated that they misrepresented their age online to gain access to websites and online services. The proportion of the U.S teens who said they have misrepresented their age online to gain access to websites and online services is the best estimate of p.

b.

To determine

Find the standard error of p^.

b.

Expert Solution

Answer to Problem 1E

The standard error of p^ is 0.018.

Explanation of Solution

Calculation:

Standard error:

If the standard deviation of a sampling distribution is estimated by using statistics of the data, the estimate is termed as standard error.

SE(p^)=p^q^n

Where, n be the number of samples, p^ be the sample proportion and q^=1−p^.

Substitute p^ as 0.49, q^ as 0.51(=1−0.49) and n as 799 in the formula,

SE(p^)=0.49(0.51)799=0.2499799=0.0003128≈0.018

Thus, the standard error of p^ is 0.018.

c.

To determine

Explain what the standard error in this context.

c.

Expert Solution

Explanation of Solution

Interpretation:

Here the value of p is not known. Therefore p^ is used to estimate the standard deviation of the sampling distribution.

When 799 teens are asked whether they misrepresented their age online to gain access to websites and online services, the standard error is the estimate that helps to know the amount of variation in the sample proportion between one sample to another sample.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 16, Problem 1E

a.

To determine

Explain the meaning of p^=0.49 in this situation.

a.

Expert Solution

Explanation of Solution

In Pew research, the random sample of 799 U.S. teens about the internet usage reports that 49% teens misrepresented their age online to access websites and online services.

Let p be the population proportion of the U.S teens who misrepresented their age and p^ acts as the best estimate of p.

Here, p^ be the sample proportion and it denotes the proportion of the U.S teens who said they have misrepresented their age online to gain access to websites and online services.

The p^=0.49 means that, 49% out of 799 U.S. teens in the sample stated that they misrepresented their age online to gain access to websites and online services. The proportion of the U.S teens who said they have misrepresented their age online to gain access to websites and online services is the best estimate of p.

b.

To determine

Find the standard error of p^.

b.

Expert Solution

Answer to Problem 1E

The standard error of p^ is 0.018.

Explanation of Solution

Calculation:

Standard error:

If the standard deviation of a sampling distribution is estimated by using statistics of the data, the estimate is termed as standard error.

SE(p^)=p^q^n

Where, n be the number of samples, p^ be the sample proportion and q^=1−p^.

Substitute p^ as 0.49, q^ as 0.51(=1−0.49) and n as 799 in the formula,

SE(p^)=0.49(0.51)799=0.2499799=0.0003128≈0.018

Thus, the standard error of p^ is 0.018.

c.

To determine

Explain what the standard error in this context.

c.

Expert Solution

Explanation of Solution

Interpretation:

Here the value of p is not known. Therefore p^ is used to estimate the standard deviation of the sampling distribution.

When 799 teens are asked whether they misrepresented their age online to gain access to websites and online services, the standard error is the estimate that helps to know the amount of variation in the sample proportion between one sample to another sample.

Answer 6

Chapter 16, Problem 1E

a.

To determine

Explain the meaning of p^=0.49 in this situation.

a.

Expert Solution

Explanation of Solution

In Pew research, the random sample of 799 U.S. teens about the internet usage reports that 49% teens misrepresented their age online to access websites and online services.

Let p be the population proportion of the U.S teens who misrepresented their age and p^ acts as the best estimate of p.

Here, p^ be the sample proportion and it denotes the proportion of the U.S teens who said they have misrepresented their age online to gain access to websites and online services.

The p^=0.49 means that, 49% out of 799 U.S. teens in the sample stated that they misrepresented their age online to gain access to websites and online services. The proportion of the U.S teens who said they have misrepresented their age online to gain access to websites and online services is the best estimate of p.

Answer 7

Chapter 16, Problem 1E

a.

To determine

Explain the meaning of p^=0.49 in this situation.

Answer 8

a.

Expert Solution

Explanation of Solution

In Pew research, the random sample of 799 U.S. teens about the internet usage reports that 49% teens misrepresented their age online to access websites and online services.

Let p be the population proportion of the U.S teens who misrepresented their age and p^ acts as the best estimate of p.

Here, p^ be the sample proportion and it denotes the proportion of the U.S teens who said they have misrepresented their age online to gain access to websites and online services.

The p^=0.49 means that, 49% out of 799 U.S. teens in the sample stated that they misrepresented their age online to gain access to websites and online services. The proportion of the U.S teens who said they have misrepresented their age online to gain access to websites and online services is the best estimate of p.

Answer 9

a.

Expert Solution

Answer 10

a.

Expert Solution

Answer 11

Expert Solution

Answer 12

b.

To determine

Find the standard error of p^.

b.

Expert Solution

Answer to Problem 1E

The standard error of p^ is 0.018.

Explanation of Solution

Calculation:

Standard error:

If the standard deviation of a sampling distribution is estimated by using statistics of the data, the estimate is termed as standard error.

SE(p^)=p^q^n

Where, n be the number of samples, p^ be the sample proportion and q^=1−p^.

Substitute p^ as 0.49, q^ as 0.51(=1−0.49) and n as 799 in the formula,

SE(p^)=0.49(0.51)799=0.2499799=0.0003128≈0.018

Thus, the standard error of p^ is 0.018.

Answer 13

b.

To determine

Find the standard error of p^.

Answer 14

b.

Expert Solution

Answer to Problem 1E

The standard error of p^ is 0.018.

Answer 15

b.

Expert Solution

Answer 16

b.

Expert Solution

Answer 17

Expert Solution

Answer 18

Explanation of Solution

Calculation:

Standard error:

If the standard deviation of a sampling distribution is estimated by using statistics of the data, the estimate is termed as standard error.

SE(p^)=p^q^n

Where, n be the number of samples, p^ be the sample proportion and q^=1−p^.

Substitute p^ as 0.49, q^ as 0.51(=1−0.49) and n as 799 in the formula,

SE(p^)=0.49(0.51)799=0.2499799=0.0003128≈0.018

Thus, the standard error of p^ is 0.018.

Answer 19

c.

To determine

Explain what the standard error in this context.

c.

Expert Solution

Explanation of Solution

Interpretation:

Here the value of p is not known. Therefore p^ is used to estimate the standard deviation of the sampling distribution.

When 799 teens are asked whether they misrepresented their age online to gain access to websites and online services, the standard error is the estimate that helps to know the amount of variation in the sample proportion between one sample to another sample.

Answer 20

c.

To determine

Explain what the standard error in this context.

Answer 21

c.

Expert Solution

Explanation of Solution

Interpretation:

Here the value of p is not known. Therefore p^ is used to estimate the standard deviation of the sampling distribution.

When 799 teens are asked whether they misrepresented their age online to gain access to websites and online services, the standard error is the estimate that helps to know the amount of variation in the sample proportion between one sample to another sample.