(a) The vector assigned to the given point by the given vector field.

Question

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Answer 1

Question

Chapter 16, Problem 1CRE

To determine

(a)

The vector assigned to the given point by the given vector field.

Expert Solution

Answer to Problem 1CRE

Solution:

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 - 3 (5), 5 - (- 3) 〉 = 〈 - 15, 8 〉$

Explanation of Solution

Given:

The given vector field is $\vec{F} = 〈 x y, y - x 〉$

Calculation:

Here, $\vec{F} = 〈 x y, y - x 〉$

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 - 3 (5), 5 - (- 3) 〉 = 〈 - 15, 8 〉$

To determine

(b)

The vector assigned to the given point by the given vector field.

Expert Solution

Answer to Problem 1CRE

Solution:

Vector assigned to the point P(–3, 5) is given by $\vec{F} = 〈 4, 8 〉$

Explanation of Solution

Given:

The given vector field is $\vec{F} = 〈 4, 8 〉$

Calculation:

Here, $\vec{F} = 〈 4, 8 〉$

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 4, 8 〉$

To determine

(c)

The vector assigned to the given point by the given vector field.

Expert Solution

Answer to Problem 1CRE

Solution:

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 9, 1 〉$

Explanation of Solution

Given:

The given vector field is $\vec{F} = 〈 3^{x + y}, \log_{2} (x + y) 〉$

Calculation:

Here, $\vec{F} = 〈 3^{x + y}, \log_{2} (x + y) 〉$

Vector assigned to the point P(–3, 5) is given by

$\begin{array}{l} \vec{F} = 〈 3^{- 3 + 5}, \log_{2} (- 3 + 5) 〉 \\ = 〈 3^{2}, \log_{2} (2) 〉 \\ ∴ \vec{F} = 〈 9, 1 〉 [∵ \log_{2} (2) = 1] \end{array}$

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Students have asked these similar questions

The correct answer is D Could you explain and show the steps please

Taylor Series Approximation Example- H.W More terms used implies better approximation f(x) 4 f(x) Zero order f(x + 1) = f(x;) First order f(x; + 1) = f(x;) + f'(x;)h 1.0 Second order 0.5 True f(x + 1) = f(x) + f'(x)h + ƒ"(x;) h2 2! f(x+1) 0 x; = 0 x+1 = 1 x h f(x)=0.1x4-0.15x³- 0.5x2 -0.25x + 1.2 51 Taylor Series Approximation H.w: Smaller step size implies smaller error Errors f(x) + f(x,) Zero order f(x,+ 1) = f(x) First order 1.0 0.5 Reduced step size Second order True f(x + 1) = f(x) + f'(x)h f(x; + 1) = f(x) + f'(x)h + "(xi) h2 f(x,+1) O x₁ = 0 x+1=1 Using Taylor Series Expansion estimate f(1.35) with x0 =0.75 with 5 iterations (or & s= 5%) for f(x)=0.1x 0.15x³-0.5x²- 0.25x + 1.2 52

Could you explain this using the formula I attached and polar coorindates

Answer 2

Question

Chapter 16, Problem 1CRE

To determine

(a)

The vector assigned to the given point by the given vector field.

Expert Solution

Answer to Problem 1CRE

Solution:

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 - 3 (5), 5 - (- 3) 〉 = 〈 - 15, 8 〉$

Explanation of Solution

Given:

The given vector field is $\vec{F} = 〈 x y, y - x 〉$

Calculation:

Here, $\vec{F} = 〈 x y, y - x 〉$

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 - 3 (5), 5 - (- 3) 〉 = 〈 - 15, 8 〉$

To determine

(b)

The vector assigned to the given point by the given vector field.

Expert Solution

Answer to Problem 1CRE

Solution:

Vector assigned to the point P(–3, 5) is given by $\vec{F} = 〈 4, 8 〉$

Explanation of Solution

Given:

The given vector field is $\vec{F} = 〈 4, 8 〉$

Calculation:

Here, $\vec{F} = 〈 4, 8 〉$

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 4, 8 〉$

To determine

(c)

The vector assigned to the given point by the given vector field.

Expert Solution

Answer to Problem 1CRE

Solution:

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 9, 1 〉$

Explanation of Solution

Given:

The given vector field is $\vec{F} = 〈 3^{x + y}, \log_{2} (x + y) 〉$

Calculation:

Here, $\vec{F} = 〈 3^{x + y}, \log_{2} (x + y) 〉$

Vector assigned to the point P(–3, 5) is given by

$\begin{array}{l} \vec{F} = 〈 3^{- 3 + 5}, \log_{2} (- 3 + 5) 〉 \\ = 〈 3^{2}, \log_{2} (2) 〉 \\ ∴ \vec{F} = 〈 9, 1 〉 [∵ \log_{2} (2) = 1] \end{array}$

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Answer 3

Question

Chapter 16, Problem 1CRE

To determine

(a)

The vector assigned to the given point by the given vector field.

Expert Solution

Answer to Problem 1CRE

Solution:

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 - 3 (5), 5 - (- 3) 〉 = 〈 - 15, 8 〉$

Explanation of Solution

Given:

The given vector field is $\vec{F} = 〈 x y, y - x 〉$

Calculation:

Here, $\vec{F} = 〈 x y, y - x 〉$

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 - 3 (5), 5 - (- 3) 〉 = 〈 - 15, 8 〉$

To determine

(b)

The vector assigned to the given point by the given vector field.

Expert Solution

Answer to Problem 1CRE

Solution:

Vector assigned to the point P(–3, 5) is given by $\vec{F} = 〈 4, 8 〉$

Explanation of Solution

Given:

The given vector field is $\vec{F} = 〈 4, 8 〉$

Calculation:

Here, $\vec{F} = 〈 4, 8 〉$

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 4, 8 〉$

To determine

(c)

The vector assigned to the given point by the given vector field.

Expert Solution

Answer to Problem 1CRE

Solution:

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 9, 1 〉$

Explanation of Solution

Given:

The given vector field is $\vec{F} = 〈 3^{x + y}, \log_{2} (x + y) 〉$

Calculation:

Here, $\vec{F} = 〈 3^{x + y}, \log_{2} (x + y) 〉$

Vector assigned to the point P(–3, 5) is given by

$\begin{array}{l} \vec{F} = 〈 3^{- 3 + 5}, \log_{2} (- 3 + 5) 〉 \\ = 〈 3^{2}, \log_{2} (2) 〉 \\ ∴ \vec{F} = 〈 9, 1 〉 [∵ \log_{2} (2) = 1] \end{array}$

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Answer 4

Question

Chapter 16, Problem 1CRE

To determine

(a)

The vector assigned to the given point by the given vector field.

Expert Solution

Answer to Problem 1CRE

Solution:

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 - 3 (5), 5 - (- 3) 〉 = 〈 - 15, 8 〉$

Explanation of Solution

Given:

The given vector field is $\vec{F} = 〈 x y, y - x 〉$

Calculation:

Here, $\vec{F} = 〈 x y, y - x 〉$

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 - 3 (5), 5 - (- 3) 〉 = 〈 - 15, 8 〉$

To determine

(b)

The vector assigned to the given point by the given vector field.

Expert Solution

Answer to Problem 1CRE

Solution:

Vector assigned to the point P(–3, 5) is given by $\vec{F} = 〈 4, 8 〉$

Explanation of Solution

Given:

The given vector field is $\vec{F} = 〈 4, 8 〉$

Calculation:

Here, $\vec{F} = 〈 4, 8 〉$

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 4, 8 〉$

To determine

(c)

The vector assigned to the given point by the given vector field.

Expert Solution

Answer to Problem 1CRE

Solution:

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 9, 1 〉$

Explanation of Solution

Given:

The given vector field is $\vec{F} = 〈 3^{x + y}, \log_{2} (x + y) 〉$

Calculation:

Here, $\vec{F} = 〈 3^{x + y}, \log_{2} (x + y) 〉$

Vector assigned to the point P(–3, 5) is given by

$\begin{array}{l} \vec{F} = 〈 3^{- 3 + 5}, \log_{2} (- 3 + 5) 〉 \\ = 〈 3^{2}, \log_{2} (2) 〉 \\ ∴ \vec{F} = 〈 9, 1 〉 [∵ \log_{2} (2) = 1] \end{array}$

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Answer 5

Chapter 16, Problem 1CRE

To determine

(a)

The vector assigned to the given point by the given vector field.

Expert Solution

Answer to Problem 1CRE

Solution:

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 - 3 (5), 5 - (- 3) 〉 = 〈 - 15, 8 〉$

Explanation of Solution

Given:

The given vector field is $\vec{F} = 〈 x y, y - x 〉$

Calculation:

Here, $\vec{F} = 〈 x y, y - x 〉$

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 - 3 (5), 5 - (- 3) 〉 = 〈 - 15, 8 〉$

To determine

(b)

The vector assigned to the given point by the given vector field.

Expert Solution

Answer to Problem 1CRE

Solution:

Vector assigned to the point P(–3, 5) is given by $\vec{F} = 〈 4, 8 〉$

Explanation of Solution

Given:

The given vector field is $\vec{F} = 〈 4, 8 〉$

Calculation:

Here, $\vec{F} = 〈 4, 8 〉$

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 4, 8 〉$

To determine

(c)

The vector assigned to the given point by the given vector field.

Expert Solution

Answer to Problem 1CRE

Solution:

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 9, 1 〉$

Explanation of Solution

Given:

The given vector field is $\vec{F} = 〈 3^{x + y}, \log_{2} (x + y) 〉$

Calculation:

Here, $\vec{F} = 〈 3^{x + y}, \log_{2} (x + y) 〉$

Vector assigned to the point P(–3, 5) is given by

$\begin{array}{l} \vec{F} = 〈 3^{- 3 + 5}, \log_{2} (- 3 + 5) 〉 \\ = 〈 3^{2}, \log_{2} (2) 〉 \\ ∴ \vec{F} = 〈 9, 1 〉 [∵ \log_{2} (2) = 1] \end{array}$

Answer 6

Chapter 16, Problem 1CRE

To determine

(a)

The vector assigned to the given point by the given vector field.

Expert Solution

Answer to Problem 1CRE

Solution:

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 - 3 (5), 5 - (- 3) 〉 = 〈 - 15, 8 〉$

Explanation of Solution

Given:

The given vector field is $\vec{F} = 〈 x y, y - x 〉$

Calculation:

Here, $\vec{F} = 〈 x y, y - x 〉$

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 - 3 (5), 5 - (- 3) 〉 = 〈 - 15, 8 〉$

Answer 7

Chapter 16, Problem 1CRE

To determine

(a)

The vector assigned to the given point by the given vector field.

Answer 8

Expert Solution

Answer to Problem 1CRE

Solution:

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 - 3 (5), 5 - (- 3) 〉 = 〈 - 15, 8 〉$

Answer 9

Expert Solution

Answer 10

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Given:

The given vector field is $\vec{F} = 〈 x y, y - x 〉$

Calculation:

Here, $\vec{F} = 〈 x y, y - x 〉$

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 - 3 (5), 5 - (- 3) 〉 = 〈 - 15, 8 〉$

Answer 13

To determine

(b)

The vector assigned to the given point by the given vector field.

Expert Solution

Answer to Problem 1CRE

Solution:

Vector assigned to the point P(–3, 5) is given by $\vec{F} = 〈 4, 8 〉$

Explanation of Solution

Given:

The given vector field is $\vec{F} = 〈 4, 8 〉$

Calculation:

Here, $\vec{F} = 〈 4, 8 〉$

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 4, 8 〉$

Answer 14

To determine

(b)

The vector assigned to the given point by the given vector field.

Answer 15

Expert Solution

Answer to Problem 1CRE

Solution:

Vector assigned to the point P(–3, 5) is given by $\vec{F} = 〈 4, 8 〉$

Answer 16

Expert Solution

Answer 17

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Given:

The given vector field is $\vec{F} = 〈 4, 8 〉$

Calculation:

Here, $\vec{F} = 〈 4, 8 〉$

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 4, 8 〉$

Answer 20

To determine

(c)

The vector assigned to the given point by the given vector field.

Expert Solution

Answer to Problem 1CRE

Solution:

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 9, 1 〉$

Explanation of Solution

Given:

The given vector field is $\vec{F} = 〈 3^{x + y}, \log_{2} (x + y) 〉$

Calculation:

Here, $\vec{F} = 〈 3^{x + y}, \log_{2} (x + y) 〉$

Vector assigned to the point P(–3, 5) is given by

$\begin{array}{l} \vec{F} = 〈 3^{- 3 + 5}, \log_{2} (- 3 + 5) 〉 \\ = 〈 3^{2}, \log_{2} (2) 〉 \\ ∴ \vec{F} = 〈 9, 1 〉 [∵ \log_{2} (2) = 1] \end{array}$

Answer 21

To determine

(c)

The vector assigned to the given point by the given vector field.

Answer 22

Expert Solution

Answer to Problem 1CRE

Solution:

Vector assigned to the point P(–3, 5) is given by

$\vec{F} = 〈 9, 1 〉$

Answer 23

Expert Solution

Answer 24

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Given:

The given vector field is $\vec{F} = 〈 3^{x + y}, \log_{2} (x + y) 〉$

Calculation:

Here, $\vec{F} = 〈 3^{x + y}, \log_{2} (x + y) 〉$

Vector assigned to the point P(–3, 5) is given by

$\begin{array}{l} \vec{F} = 〈 3^{- 3 + 5}, \log_{2} (- 3 + 5) 〉 \\ = 〈 3^{2}, \log_{2} (2) 〉 \\ ∴ \vec{F} = 〈 9, 1 〉 [∵ \log_{2} (2) = 1] \end{array}$