Chemistry: The Science in Context (Fourth Edition)
4th Edition
ISBN: 9780393124187
Author: Thomas R. Gilbert, Rein V. Kirss, Natalie Foster, Geoffrey Davies
Publisher: W. W. Norton & Company
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Question
Chapter 16, Problem 16.75QP
Interpretation Introduction
Interpretation: Among the given compounds, ethanolamine having a greater value of
Concept introduction: The value of
To determine: An explanation corresponding to ethanolamine having a greater value of
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TRANSMITTANCE
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Please identify the one structure below that is consistent with the 'H NMR and IR spectra
shown and draw its complete structure in the box below with the protons alphabetically labeled as
shown in the NMR spectrum and label the IR bands, including sp³C-H and sp2C-H stretch, indicated by
the arrows.
D
4000
OH
LOH
H₂C
CH3
OH
H₂C
OCH3
CH3
OH
3000
2000
1500
HAVENUMBERI-11
1000
LOCH3
Draw your structure below and label its equivalent protons according to the peak labeling that is used
in the NMR spectrum in order to assign the peaks.
Integrals indicate number of equivalent protons. Splitting patterns are: s=singlet, d=doublet, m-multiplet
8
3Hb s
m
1Hd s
3Hf
m 2Hcd
2Had
1He
鄙视
m
7
7
6
5
4
3
22
500
T
1
0
Chapter 16 Solutions
Chemistry: The Science in Context (Fourth Edition)
Ch. 16.1 - Prob. 1PECh. 16.2 - Prob. 2PECh. 16.2 - Prob. 3PECh. 16.3 - Prob. 4PECh. 16.3 - Prob. 5PECh. 16.4 - Prob. 6PECh. 16.6 - Prob. 7PECh. 16.6 - Prob. 8PECh. 16.7 - Prob. 9PECh. 16.8 - Prob. 10PE
Ch. 16.8 - Prob. 11PECh. 16.8 - Prob. 12PECh. 16.8 - Prob. 13PECh. 16.10 - Prob. 17PECh. 16.10 - Prob. 18PECh. 16 - Prob. 16.1VPCh. 16 - Prob. 16.2VPCh. 16 - Prob. 16.3VPCh. 16 - Prob. 16.4VPCh. 16 - Prob. 16.5VPCh. 16 - Prob. 16.6VPCh. 16 - Prob. 16.7VPCh. 16 - Prob. 16.8VPCh. 16 - Prob. 16.9VPCh. 16 - Prob. 16.10VPCh. 16 - Prob. 16.11QPCh. 16 - Prob. 16.12QPCh. 16 - Prob. 16.13QPCh. 16 - Prob. 16.14QPCh. 16 - Prob. 16.15QPCh. 16 - Prob. 16.16QPCh. 16 - Prob. 16.17QPCh. 16 - Prob. 16.18QPCh. 16 - Prob. 16.19QPCh. 16 - Prob. 16.20QPCh. 16 - Prob. 16.21QPCh. 16 - Prob. 16.22QPCh. 16 - Prob. 16.23QPCh. 16 - Prob. 16.24QPCh. 16 - Prob. 16.25QPCh. 16 - Prob. 16.26QPCh. 16 - Prob. 16.27QPCh. 16 - Prob. 16.28QPCh. 16 - Prob. 16.29QPCh. 16 - Prob. 16.30QPCh. 16 - Prob. 16.31QPCh. 16 - Prob. 16.32QPCh. 16 - Prob. 16.33QPCh. 16 - Prob. 16.34QPCh. 16 - Prob. 16.35QPCh. 16 - Prob. 16.36QPCh. 16 - Prob. 16.37QPCh. 16 - Prob. 16.38QPCh. 16 - Prob. 16.39QPCh. 16 - Prob. 16.40QPCh. 16 - Prob. 16.42QPCh. 16 - Prob. 16.43QPCh. 16 - Prob. 16.44QPCh. 16 - Prob. 16.45QPCh. 16 - Prob. 16.46QPCh. 16 - Prob. 16.47QPCh. 16 - Prob. 16.48QPCh. 16 - Prob. 16.49QPCh. 16 - Prob. 16.50QPCh. 16 - Prob. 16.51QPCh. 16 - Prob. 16.52QPCh. 16 - Prob. 16.53QPCh. 16 - Prob. 16.54QPCh. 16 - Prob. 16.55QPCh. 16 - Prob. 16.56QPCh. 16 - Prob. 16.57QPCh. 16 - Prob. 16.58QPCh. 16 - Prob. 16.59QPCh. 16 - Prob. 16.60QPCh. 16 - Prob. 16.61QPCh. 16 - Prob. 16.62QPCh. 16 - Prob. 16.63QPCh. 16 - Prob. 16.64QPCh. 16 - Prob. 16.65QPCh. 16 - Prob. 16.66QPCh. 16 - Prob. 16.67QPCh. 16 - Prob. 16.68QPCh. 16 - Prob. 16.69QPCh. 16 - Prob. 16.70QPCh. 16 - Prob. 16.71QPCh. 16 - Prob. 16.72QPCh. 16 - Prob. 16.73QPCh. 16 - Prob. 16.74QPCh. 16 - Prob. 16.75QPCh. 16 - Prob. 16.76QPCh. 16 - Prob. 16.77QPCh. 16 - Prob. 16.78QPCh. 16 - Prob. 16.79QPCh. 16 - Prob. 16.80QPCh. 16 - Prob. 16.81QPCh. 16 - Prob. 16.82QPCh. 16 - Prob. 16.83QPCh. 16 - Prob. 16.84QPCh. 16 - Prob. 16.85QPCh. 16 - Prob. 16.86QPCh. 16 - Prob. 16.87QPCh. 16 - Prob. 16.88QPCh. 16 - Prob. 16.89QPCh. 16 - Prob. 16.90QPCh. 16 - Prob. 16.91QPCh. 16 - Prob. 16.92QPCh. 16 - Prob. 16.93QPCh. 16 - Prob. 16.94QPCh. 16 - Prob. 16.95QPCh. 16 - Prob. 16.96QPCh. 16 - Prob. 16.97QPCh. 16 - Prob. 16.98QPCh. 16 - Prob. 16.99QPCh. 16 - Prob. 16.100QPCh. 16 - Prob. 16.101QPCh. 16 - Prob. 16.102QPCh. 16 - Prob. 16.103QPCh. 16 - Prob. 16.104QPCh. 16 - Prob. 16.105QPCh. 16 - Prob. 16.106QPCh. 16 - Prob. 16.107QPCh. 16 - Prob. 16.108QPCh. 16 - Prob. 16.109QPCh. 16 - Prob. 16.110QPCh. 16 - Prob. 16.111QPCh. 16 - Prob. 16.112QPCh. 16 - Prob. 16.113QPCh. 16 - Prob. 16.114QPCh. 16 - Prob. 16.115QPCh. 16 - Prob. 16.116QPCh. 16 - Prob. 16.117QPCh. 16 - Prob. 16.118QPCh. 16 - Prob. 16.119QPCh. 16 - Prob. 16.120QPCh. 16 - Prob. 16.121QPCh. 16 - Prob. 16.122QPCh. 16 - Prob. 16.123QPCh. 16 - Prob. 16.124QPCh. 16 - Prob. 16.125QPCh. 16 - Prob. 16.126QPCh. 16 - Prob. 16.127QPCh. 16 - Prob. 16.128QPCh. 16 - Prob. 16.129QPCh. 16 - Prob. 16.130QPCh. 16 - Prob. 16.131QPCh. 16 - Prob. 16.132QPCh. 16 - Prob. 16.133QPCh. 16 - Prob. 16.134QPCh. 16 - Prob. 16.135QPCh. 16 - Prob. 16.136QPCh. 16 - Prob. 16.137QPCh. 16 - Prob. 16.138QPCh. 16 - Prob. 16.139QPCh. 16 - Prob. 16.140QPCh. 16 - Prob. 16.141QPCh. 16 - Prob. 16.142QPCh. 16 - Prob. 16.143QPCh. 16 - Prob. 16.144QPCh. 16 - Prob. 16.145QPCh. 16 - Prob. 16.146QPCh. 16 - Prob. 16.147QPCh. 16 - Prob. 16.148QPCh. 16 - Prob. 16.149QPCh. 16 - Prob. 16.150QPCh. 16 - Prob. 16.151APCh. 16 - Prob. 16.152APCh. 16 - Prob. 16.153APCh. 16 - Prob. 16.154APCh. 16 - Prob. 16.155APCh. 16 - Prob. 16.156APCh. 16 - Prob. 16.157APCh. 16 - Prob. 16.158APCh. 16 - Prob. 16.159APCh. 16 - Prob. 16.160APCh. 16 - Prob. 16.161APCh. 16 - Prob. 16.162APCh. 16 - Prob. 16.163APCh. 16 - Prob. 16.164APCh. 16 - Prob. 16.165APCh. 16 - Prob. 16.166APCh. 16 - Prob. 16.167APCh. 16 - Prob. 16.168APCh. 16 - Prob. 16.169APCh. 16 - Prob. 16.170APCh. 16 - Prob. 16.171APCh. 16 - Prob. 16.173APCh. 16 - Prob. 16.174AP
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Similar questions
- Relative Transmittance 0.995 0.99 0.985 0.98 Please draw the structure that is consistent with all the spectral data below in the box and alphabetically label the equivalent protons in the structure (Ha, Hb, Hc ....) in order to assign all the proton NMR peaks. Label the absorption bands in the IR spectrum indicated by the arrows. INFRARED SPECTRUM 1 0.975 3000 2000 Wavenumber (cm-1) 1000 Structure with assigned H peaks 1 3 180 160 140 120 100 f1 (ppm) 80 60 40 20 0 C-13 NMR note that there are 4 peaks between 120-140ppm Integral values equal the number of equivalent protons 10.0 9.0 8.0 7.0 6.0 5.0 4.0 3.0 2.0 1.0 0.0 fl (ppm)arrow_forwardCalculate the pH of 0.0025 M phenol.arrow_forwardIn the following reaction, the OH- acts as which of these? NO2-(aq) + H2O(l) ⇌ OH-(aq) + HNO2(aq)arrow_forward
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