Use Le Châtelier’s principle to explain how the common ion effect affects the pH of a solution.
Expert Solution & Answer
Interpretation Introduction
Interpretation:
By using Le Chatelier’s principle, the changes of pH of a weak acid solution due to common ion effect has to be explained.
Concept introduction:
Le Chatelier's principle states that if a system in equilibrium gets disturbed due to modification of concentration, temperature, volume, and pressure, then it reset to counteract the effect of disturbance.
When the concentration of one of the ions of a chemical solution got higher, it reacts with counter charged ions and precipitated out as salt till the ion product equals solubility product is called common ion effect.
Incomplete dissociation of an acid in aqueous solution is called weak acid.
The pH of weak acid (acetic acid) increases due to addition of acetate ions from sodium acetate which suppress ionization of acetic acid leads to decrease in percent ionization of acetic acid. The equilibrium shifts towards left because of more acetate ion (common ion).
Explanation of Solution
To explain: The changes of pH of a weak acid solution due to common ion effect.
The equilibrium reaction of acetic acid and sodium acetate are as follows,
In an aqueous solution, dissolve acetic acid (weak acid) thoroughly which dissociates as acetate ions and hydronium ions. Then add sodium acetate (strong electrolyte) and it dissociates completely to form sodium ions and acetate ions. The common ion produced from both acetic acid and sodium acetate is acetate ion. By following the principle of Le Chatelier Principle, the acetate ions from sodium acetate combine with hydronium ions and the equilibrium shifts towards left which reduce the ionization of acetic acid.Thus lowers the percent dissociation of acetic acid and due to decrease in hydrogen ion concentration the pH of the solution will increase.
Conclusion
The change of pH of a weak acid solution due to common ion effect was explained by Le Chatelier's principle.
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A student proposes the following two-step synthesis of an ether from an alcohol A:
1. strong base
A
2. R
Is the student's proposed synthesis likely to work?
If you said the proposed synthesis would work, enter the chemical
formula or common abbreviation for an appropriate strong base to use
in Step 1:
If you said the synthesis would work, draw the structure of an alcohol
A, and the structure of the additional reagent R needed in Step 2, in
the drawing area below.
If there's more than one reasonable choice for a good reaction yield,
you can draw any of them.
☐
Click and drag to start drawing a structure.
Yes
No
ロ→ロ
0|0
G
Х
D
: ☐
ப
टे
Predict the major products of this organic reaction.
Be sure to use wedge and dash bonds when necessary, for example to distinguish between different major products.
☐
☐
: ☐
+
NaOH
HO
2
Click and drag to start
drawing a structure.
Shown below are five NMR spectra for five different C6H10O2 compounds. For each spectrum, draw the structure of the compound, and assign the spectrum by labeling H's in your structure (or in a second drawing of the structure) with the chemical shifts of the corresponding signals (which can be estimated to nearest 0.1 ppm). IR information is also provided. As a reminder, a peak near 1700 cm-1 is consistent with the presence of a carbonyl (C=O), and a peak near 3300 cm-1 is consistent with the presence of an O–H.
Extra information: For C6H10O2 , there must be either 2 double bonds, or 1 triple bond, or two rings to account for the unsaturation. There is no two rings for this problem.
A strong band was observed in the IR at 1717 cm-1
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