The solubility of A g B r and F e ( O H ) 2 should be explained using the solubility product value of A g B r and F e ( O H ) 2 . Concept Introduction: Solubility is defined as the maximum quantity of solute dissolved in a given amount of solvent to make a saturated solution at a particular temperature. Molar solubility is the number of moles of a solute that can be dissolved in one liter of a solution. It is expressed as mol/L or M (molarity). Consider a general reaction: M n X m (s) ⇌ n M m+ (aq)+m X n+ (aq) The relation between solubility product and molar solubility is as follows: K sp = [ M m+ ] n [ X n- ] m Here The solubility product of salt is K sp . The molar solubility of M m+ ion is [ M m+ ] . The molar solubility of X n- ion is [ X n- ] . Molarity: The concentration for solutions is expressed in terms of molarity as follows, Molarity = No . of moles of solute Volume of solution in L Moles: One mole is equivalent to the mass of the substance consists same number of units equal to the atoms present in 12 g of 12 C . From given mass of substance moles could be calculated by using the following formula, Moles of substance = Given mass of substance Molecular mass
The solubility of A g B r and F e ( O H ) 2 should be explained using the solubility product value of A g B r and F e ( O H ) 2 . Concept Introduction: Solubility is defined as the maximum quantity of solute dissolved in a given amount of solvent to make a saturated solution at a particular temperature. Molar solubility is the number of moles of a solute that can be dissolved in one liter of a solution. It is expressed as mol/L or M (molarity). Consider a general reaction: M n X m (s) ⇌ n M m+ (aq)+m X n+ (aq) The relation between solubility product and molar solubility is as follows: K sp = [ M m+ ] n [ X n- ] m Here The solubility product of salt is K sp . The molar solubility of M m+ ion is [ M m+ ] . The molar solubility of X n- ion is [ X n- ] . Molarity: The concentration for solutions is expressed in terms of molarity as follows, Molarity = No . of moles of solute Volume of solution in L Moles: One mole is equivalent to the mass of the substance consists same number of units equal to the atoms present in 12 g of 12 C . From given mass of substance moles could be calculated by using the following formula, Moles of substance = Given mass of substance Molecular mass
Solution Summary: The author explains the solubility product value of AgBr and Fe(OH)_2.
The solubility of AgBr and Fe(OH)2 should be explained using the solubility product value of AgBr and Fe(OH)2.
Concept Introduction:
Solubility is defined as the maximum quantity of solute dissolved in a given amount of solvent to make a saturated solution at a particular temperature.
Molar solubility is the number of moles of a solute that can be dissolved in one liter of a solution. It is expressed as mol/L or M (molarity).
Consider a general reaction:
MnXm(s)⇌nMm+(aq)+mXn+(aq)
The relation between solubility product and molar solubility is as follows:
Ksp=[Mm+]n[Xn-]m
Here
The solubility product of salt is Ksp.
The molar solubility of Mm+ ion is [Mm+].
The molar solubility of Xn- ion is [Xn-].
Molarity: The concentration for solutions is expressed in terms of molarity as follows,
Molarity = No. of moles of soluteVolume of solution in L
Moles: One mole is equivalent to the mass of the substance consists same number of units equal to the atoms present in 12g of 12C.
From given mass of substance moles could be calculated by using the following formula,
Using the graphs could you help me explain the answers. I assumed that both graphs are proportional to the inverse of time, I think. Could you please help me.
Synthesis of Dibenzalacetone
[References]
Draw structures for the carbonyl electrophile and enolate nucleophile that react to give the enone below.
Question 1
1 pt
Question 2
1 pt
Question 3
1 pt
H
Question 4
1 pt
Question 5
1 pt
Question 6
1 pt
Question 7
1pt
Question 8
1 pt
Progress:
7/8 items
Que Feb 24 at
You do not have to consider stereochemistry.
. Draw the enolate ion in its carbanion form.
• Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner.
⚫ Separate multiple reactants using the + sign from the drop-down menu.
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4
Shown below is the mechanism presented for the formation of biasplatin in reference 1 from the Background and Experiment document. The amounts used of each reactant are shown. Either draw or describe a better alternative to this mechanism. (Note that the first step represents two steps combined and the proton loss is not even shown; fixing these is not the desired improvement.) (Hints: The first step is correct, the second step is not; and the amount of the anhydride is in large excess to serve a purpose.)
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell