EXPLOR. CHEM ANALYSIS (LL) - W/ ACHIEVE
EXPLOR. CHEM ANALYSIS (LL) - W/ ACHIEVE
5th Edition
ISBN: 9781319468859
Author: Harris
Publisher: MAC HIGHER
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Chapter 16, Problem 16.10P
Interpretation Introduction

Interpretation:

Reason behind the use of I2 in a solution that contains excess I has to be explained.

Concept Introduction:

Solubility of a substance is the ability to dissolve in a given solvent. Practically solubility is measured in terms of the amount of species that can be dissolved in a given solvent at equilibrium conditions to make a saturated solution.

The substance with high solubility indicates the lesser number of solute molecules near the surface of the solution, and hence vapor pressure over the solution is low.

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1. Consider these three reactions as the elementary steps in the mechanism for a chemical reaction. 2600 2400 2200 2000 1800 1600 1400 1200 1000 800 Potential Energy (kJ) 600 400 200 0 -200- -400 -600- -800 (i) Cl₂ (g) + Pt(s) → 2Cl (g) + Pt(s) (ii) Cl (g)+ CO (g) + Pt (s) → CICO (g) + Pt (s) Ea = 1550 kJ Ea = 2240 kJ (iii) Cl (g) + CICO (g) → Cl₂CO (g) Ea = 2350 kJ AH=-950 kJ ΔΗ = 575 ΚΙ AH=-825 kJ a. Draw the potential energy diagram for the reaction. Label the data points for clarity. The potential energy of the reactants is 600 kJ Reaction Progress b. What is the overall chemical equation? c. What is the overall change in enthalpy for the above chemical reaction? d. What is the overall amount of activation energy for the above chemical reaction? e. Which reaction intermediate would be considered a catalyst (if any) and why? f. If you were to add 2700kJ of energy to the reaction (e.g. 2700 kl of heat or electricity), would you be able to make the reaction reverse itself (i.e. have…
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