For theorem 1, part (d) is equivalent to (a), (a) is equivalent to (c), (c) is equivalent to (b), (b) is equivalent to (c) and (c) is equivalent to (a).

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Answer 1

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Chapter 1.6, Problem 1.51P

To determine

To show: For theorem 1, part (d) is equivalent to (a), (a) is equivalent to (c), (c) is equivalent to (b), (b) is equivalent to (c) and (c) is equivalent to (a).

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Answer 2

Question

Chapter 1.6, Problem 1.51P

To determine

To show: For theorem 1, part (d) is equivalent to (a), (a) is equivalent to (c), (c) is equivalent to (b), (b) is equivalent to (c) and (c) is equivalent to (a).

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Answer 3

Question

Chapter 1.6, Problem 1.51P

To determine

To show: For theorem 1, part (d) is equivalent to (a), (a) is equivalent to (c), (c) is equivalent to (b), (b) is equivalent to (c) and (c) is equivalent to (a).

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Answer 4

Question

Chapter 1.6, Problem 1.51P

To determine

To show: For theorem 1, part (d) is equivalent to (a), (a) is equivalent to (c), (c) is equivalent to (b), (b) is equivalent to (c) and (c) is equivalent to (a).

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Answer 5

Chapter 1.6, Problem 1.51P

To determine

To show: For theorem 1, part (d) is equivalent to (a), (a) is equivalent to (c), (c) is equivalent to (b), (b) is equivalent to (c) and (c) is equivalent to (a).

Answer 6

Chapter 1.6, Problem 1.51P

To determine

To show: For theorem 1, part (d) is equivalent to (a), (a) is equivalent to (c), (c) is equivalent to (b), (b) is equivalent to (c) and (c) is equivalent to (a).

Answer 7

Chapter 1.6, Problem 1.51P

To determine

To show: For theorem 1, part (d) is equivalent to (a), (a) is equivalent to (c), (c) is equivalent to (b), (b) is equivalent to (c) and (c) is equivalent to (a).

Answer 8

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Answer 9

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Answer 10

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Answer 11

Ch. 1.1 - Using the definitions in Eqs. 1.1 and 1.4, and...Ch. 1.1 - Prob. 1.2P Ch. 1.1 - Prob. 1.3P Ch. 1.1 - Prob. 1.4P Ch. 1.1 - Prob. 1.5P Ch. 1.1 - Prob. 1.6P Ch. 1.1 - Prob. 1.7P Ch. 1.1 - Prob. 1.8P Ch. 1.1 - Prob. 1.9P Ch. 1.1 - Prob. 1.10P

For theorem 1, part (d) is equivalent to (a), (a) is equivalent to (c), (c) is equivalent to (b), (b) is equivalent to (c) and (c) is equivalent to (a).

Solution Summary: The author explains that the expression for stokes theorem is a vector function.

To show: For theorem 1, part (d) is equivalent to (a), (a) is equivalent to (c), (c) is equivalent to (b), (b) is equivalent to (c) and (c) is equivalent to (a).

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Chapter 1 Solutions