Explanation Given The concentration of the solution is 2 .5 × 10 − 9 M . A strong base completely dissociates into its ions in a solution. Sodium hydroxide is a strong base, so it completely dissociates into its respective ions. Hence, the concentration of OH − is equal to the concentration of sodium hydroxide solution. The value of pOH is calculated by the following formula, pOH = − log [ OH − ] Substitute the value of [ OH − ] in the above expression, pOH = − log [ 2 .5 × 10 − 9 M ] =8 .6 The value of pH is calculated by the formula, pH = 14 − pOH Substitute the value of pOH in the above equation, pH = 14 − pOH = 14 − 8 .6 = 5 .4 Hence, the pH of the solution is 5 .4 . Sodium hydroxide is a strong base and its pH value is approximately 14 . But the calculated value of pH in the given case is to 5

Laboratory Experiments For Chemistry: The Central Science, Si Edition

14th Edition

ISBN: 9781292221335

Author: Theodore E. Brown

Publisher: PEARSON

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Chapter 16, Problem 106AE

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To determine: The pH of the solution that is 2.5×10−9 M in NaOH and if any assumption had to be made to calculate the pH of the given solution should be identified

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Chapter 16, Problem 105AE

Chapter 16, Problem 107AE

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Laboratory Experiments For Chemistry: The Central Science, Si Edition

Ch. 16.2 - Practice Exercise 1 Consider the following...Ch. 16.2 - Prob. 16.1.2PE Ch. 16.2 - Prob. 16.2.1PE Ch. 16.2 - Practice Exercise 2 When lithium oxide (Li2O) is...Ch. 16.2 - Based on information in Figure 16.4, place the...Ch. 16.2 - Practice Exercise 2 For each reaction, use Figure...Ch. 16.3 - Practice Exercise 1 In a certain acidic solution...Ch. 16.3 - Practice Exercise 2 Indicate whether solutions...Ch. 16.3 - Prob. 16.5.1PE Ch. 16.3 - Prob. 16.5.2PE

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The pH of the solution that is 2 .5 × 10 − 9 M in NaOH and if any assumption had to be made to calculate the pH of the given solution should be identified

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To determine: The pH of the solution that is 2.5×10−9 M in NaOH and if any assumption had to be made to calculate the pH of the given solution should be identified

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Chapter 16 Solutions