Explanation Given: The mass of an empty truck, m = 50 Mg The density of sand, ρ s = 1520 kg/m 3 The volume of the sand, V s = 5 m 3 The constant rate of sand, Q = 0.8 m 3 /s The sand flows back at rate, v D / e = 7 m/s Express the total mass of the truck. m T = m + V s ρ s (I) Express the mass flow of the truck. d m e d t = Q ρ s (II) Write the resultant of all the external forces acting on the sand in the direction of motion equals to zero. ∑ F s = m d v d t − v D / e d m e d t m d v d t − v D / e d m e d t = 0 m a − v D / e d m e d t = 0 (III) Here, change in time is dt , change in the velocity is dv , and increase in the mass is d m e . Conclusion: Substitute 50 Mg for m , 5 m 3 for V s , and 1520 kg/m 3 for ρ s in Equation (I)

Engineering Mechanics: Dynamics; Modified Mastering Engineering with Pearson eText -- Standalone Access Card -- for Engineering Mechanics: Dynamics (14th Edition)

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ISBN: 9780134229294

Author: HIBBELER

Publisher: PEARSON

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Chapter 15.9, Problem 148P

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The initial acceleration when load begins to empty.

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Chapter 15.9, Problem 147P

Chapter 15.9, Problem 149P

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Engineering Mechanics: Dynamics; Modified Mastering Engineering with Pearson eText -- Standalone Access Card -- for Engineering Mechanics: Dynamics (14th Edition)

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The initial acceleration when load begins to empty.

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