BEGINNING+INTERM.ALG.(LL) >CUSTOM PKG.<
6th Edition
ISBN: 9781266148941
Author: Miller
Publisher: MCG CUSTOM
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Chapter 15.7, Problem 52PE
To determine
To state: The number of three-number codes that are possible if a school locker consists of three different numbers taken from 1 to 39 in a specific order.
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You are given a plane Π in R3 defined by two vectors, p1 and p2, and a subspace W in R3 spanned by twovectors, w1 and w2. Your task is to project the plane Π onto the subspace W.First, answer the question of what the projection matrix is that projects onto the subspace W and how toapply it to find the desired projection. Second, approach the task in a different way by using the Gram-Schmidtmethod to find an orthonormal basis for subspace W, before then using the resulting basis vectors for theprojection. Last, compare the results obtained from both methods
Plane II is spanned by the vectors:
- (2) · P² - (4)
P1=2
P21
3
Subspace W is spanned by the vectors:
2
W1
- (9) ·
1
W2
1
= (³)
Chapter 15 Solutions
BEGINNING+INTERM.ALG.(LL) >CUSTOM PKG.<
Ch. 15.1 - Prob. 1SPCh. 15.1 - Prob. 2SPCh. 15.1 - Prob. 3SPCh. 15.1 - Prob. 4SPCh. 15.1 - Prob. 5SPCh. 15.1 - Prob. 6SPCh. 15.1 - Prob. 7SPCh. 15.1 - Prob. 8SPCh. 15.1 - Prob. 9SPCh. 15.1 - Prob. 1PE
Ch. 15.1 - Prob. 2PECh. 15.1 - Prob. 3PECh. 15.1 - Prob. 4PECh. 15.1 - Prob. 5PECh. 15.1 - Prob. 6PECh. 15.1 - Prob. 7PECh. 15.1 - Prob. 8PECh. 15.1 - Prob. 9PECh. 15.1 - Prob. 10PECh. 15.1 - Prob. 11PECh. 15.1 - Prob. 12PECh. 15.1 - Prob. 13PECh. 15.1 - Prob. 14PECh. 15.1 - Prob. 15PECh. 15.1 - Prob. 16PECh. 15.1 - Prob. 17PECh. 15.1 - Prob. 18PECh. 15.1 - Prob. 19PECh. 15.1 - Prob. 20PECh. 15.1 - Prob. 21PECh. 15.1 - Prob. 22PECh. 15.1 - Prob. 23PECh. 15.1 - Prob. 24PECh. 15.1 - Prob. 25PECh. 15.1 - Prob. 26PECh. 15.1 - Prob. 27PECh. 15.1 - Prob. 28PECh. 15.1 - Prob. 29PECh. 15.1 - Prob. 30PECh. 15.1 - Prob. 31PECh. 15.1 - Prob. 32PECh. 15.1 - Prob. 33PECh. 15.1 - Prob. 34PECh. 15.1 - Prob. 35PECh. 15.1 - Prob. 36PECh. 15.1 - Prob. 37PECh. 15.1 - Prob. 38PECh. 15.1 - Prob. 39PECh. 15.1 - Prob. 40PECh. 15.1 - Prob. 41PECh. 15.1 - Prob. 42PECh. 15.1 - Prob. 43PECh. 15.1 - Prob. 44PECh. 15.1 - Prob. 45PECh. 15.1 - Prob. 46PECh. 15.1 - Prob. 47PECh. 15.1 - Prob. 48PECh. 15.1 - Prob. 49PECh. 15.2 - Prob. 1SPCh. 15.2 - Prob. 2SPCh. 15.2 - Prob. 3SPCh. 15.2 - Prob. 4SPCh. 15.2 - Prob. 5SPCh. 15.2 - Prob. 6SPCh. 15.2 - Prob. 7SPCh. 15.2 - Prob. 8SPCh. 15.2 - Prob. 9SPCh. 15.2 - Prob. 10SPCh. 15.2 - Prob. 11SPCh. 15.2 - Prob. 12SPCh. 15.2 - Prob. 13SPCh. 15.2 - Prob. 14SPCh. 15.2 - Prob. 1PECh. 15.2 - Prob. 2PECh. 15.2 - Prob. 3PECh. 15.2 - Prob. 4PECh. 15.2 - Prob. 5PECh. 15.2 - Prob. 6PECh. 15.2 - Prob. 7PECh. 15.2 - Prob. 8PECh. 15.2 - Prob. 9PECh. 15.2 - Prob. 10PECh. 15.2 - Prob. 11PECh. 15.2 - Prob. 12PECh. 15.2 - Prob. 13PECh. 15.2 - Prob. 14PECh. 15.2 - Prob. 15PECh. 15.2 - Prob. 16PECh. 15.2 - Prob. 17PECh. 15.2 - Prob. 18PECh. 15.2 - Prob. 19PECh. 15.2 - Prob. 20PECh. 15.2 - Prob. 21PECh. 15.2 - Prob. 22PECh. 15.2 - Prob. 23PECh. 15.2 - Prob. 24PECh. 15.2 - Prob. 25PECh. 15.2 - Prob. 26PECh. 15.2 - Prob. 27PECh. 15.2 - Prob. 28PECh. 15.2 - Prob. 29PECh. 15.2 - Prob. 30PECh. 15.2 - Prob. 31PECh. 15.2 - Prob. 32PECh. 15.2 - Prob. 33PECh. 15.2 - Prob. 34PECh. 15.2 - Prob. 35PECh. 15.2 - Prob. 36PECh. 15.2 - Prob. 37PECh. 15.2 - Prob. 38PECh. 15.2 - Prob. 39PECh. 15.2 - Prob. 40PECh. 15.2 - Prob. 41PECh. 15.2 - Prob. 42PECh. 15.2 - Prob. 43PECh. 15.2 - Prob. 44PECh. 15.2 - Prob. 45PECh. 15.2 - Prob. 46PECh. 15.2 - Prob. 47PECh. 15.2 - Prob. 48PECh. 15.2 - Prob. 49PECh. 15.2 - Prob. 50PECh. 15.2 - Prob. 51PECh. 15.2 - Prob. 52PECh. 15.2 - Prob. 53PECh. 15.2 - Prob. 54PECh. 15.2 - Prob. 55PECh. 15.2 - Prob. 56PECh. 15.2 - Prob. 57PECh. 15.2 - Prob. 58PECh. 15.2 - Prob. 59PECh. 15.2 - Prob. 60PECh. 15.2 - Prob. 61PECh. 15.2 - Prob. 62PECh. 15.2 - Prob. 63PECh. 15.2 - Prob. 64PECh. 15.2 - Prob. 65PECh. 15.2 - Prob. 66PECh. 15.2 - Prob. 67PECh. 15.2 - Prob. 68PECh. 15.2 - Prob. 69PECh. 15.2 - Prob. 70PECh. 15.2 - Prob. 71PECh. 15.2 - Prob. 72PECh. 15.2 - Prob. 73PECh. 15.2 - Prob. 74PECh. 15.2 - Prob. 75PECh. 15.2 - Prob. 76PECh. 15.2 - Prob. 77PECh. 15.2 - Prob. 78PECh. 15.2 - Prob. 79PECh. 15.2 - Prob. 80PECh. 15.2 - Prob. 81PECh. 15.2 - Prob. 82PECh. 15.2 - Prob. 83PECh. 15.2 - 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Prob. 21PECh. 15.3 - Prob. 22PECh. 15.3 - Prob. 23PECh. 15.3 - Prob. 24PECh. 15.3 - Prob. 25PECh. 15.3 - Prob. 26PECh. 15.3 - Prob. 27PECh. 15.3 - Prob. 28PECh. 15.3 - Prob. 29PECh. 15.3 - Prob. 30PECh. 15.3 - Prob. 31PECh. 15.3 - Prob. 32PECh. 15.3 - Prob. 33PECh. 15.3 - Prob. 34PECh. 15.3 - Prob. 35PECh. 15.3 - Prob. 36PECh. 15.3 - Prob. 37PECh. 15.3 - Prob. 38PECh. 15.3 - Prob. 39PECh. 15.3 - Prob. 40PECh. 15.3 - Prob. 41PECh. 15.3 - Prob. 42PECh. 15.3 - Prob. 43PECh. 15.3 - Prob. 44PECh. 15.3 - Prob. 45PECh. 15.3 - Prob. 46PECh. 15.3 - Prob. 47PECh. 15.3 - Prob. 48PECh. 15.3 - Prob. 49PECh. 15.3 - Prob. 50PECh. 15.3 - Prob. 51PECh. 15.3 - Prob. 52PECh. 15.3 - Prob. 53PECh. 15.3 - Prob. 54PECh. 15.3 - Prob. 55PECh. 15.3 - Prob. 56PECh. 15.3 - Prob. 57PECh. 15.3 - Prob. 58PECh. 15.3 - Prob. 59PECh. 15.3 - Prob. 60PECh. 15.3 - Prob. 61PECh. 15.3 - Prob. 62PECh. 15.3 - Prob. 63PECh. 15.3 - Prob. 64PECh. 15.3 - Prob. 65PECh. 15.3 - Prob. 66PECh. 15.3 - Prob. 67PECh. 15.3 - Prob. 68PECh. 15.4 - Prob. 1SPCh. 15.4 - Prob. 2SPCh. 15.4 - Prob. 3SPCh. 15.4 - Prob. 4SPCh. 15.4 - Prob. 5SPCh. 15.4 - Prob. 6SPCh. 15.4 - Prob. 7SPCh. 15.4 - Prob. 8SPCh. 15.4 - Prob. 9SPCh. 15.4 - Prob. 10SPCh. 15.4 - Prob. 11SPCh. 15.4 - Prob. 12SPCh. 15.4 - Prob. 13SPCh. 15.4 - Prob. 1PECh. 15.4 - Prob. 2PECh. 15.4 - Prob. 3PECh. 15.4 - Prob. 4PECh. 15.4 - Prob. 5PECh. 15.4 - Prob. 6PECh. 15.4 - Prob. 7PECh. 15.4 - Prob. 8PECh. 15.4 - Prob. 9PECh. 15.4 - Prob. 10PECh. 15.4 - Prob. 11PECh. 15.4 - Prob. 12PECh. 15.4 - Prob. 13PECh. 15.4 - Prob. 14PECh. 15.4 - Prob. 15PECh. 15.4 - Prob. 16PECh. 15.4 - Prob. 17PECh. 15.4 - Prob. 18PECh. 15.4 - Prob. 19PECh. 15.4 - Prob. 20PECh. 15.4 - Prob. 21PECh. 15.4 - Prob. 22PECh. 15.4 - Prob. 23PECh. 15.4 - Prob. 24PECh. 15.4 - Prob. 25PECh. 15.4 - Prob. 26PECh. 15.4 - Prob. 27PECh. 15.4 - Prob. 28PECh. 15.4 - Prob. 29PECh. 15.4 - Prob. 30PECh. 15.4 - Prob. 31PECh. 15.4 - Prob. 32PECh. 15.4 - Prob. 33PECh. 15.4 - Prob. 34PECh. 15.4 - Prob. 35PECh. 15.4 - Prob. 36PECh. 15.4 - Prob. 37PECh. 15.4 - Prob. 38PECh. 15.4 - Prob. 39PECh. 15.4 - Prob. 40PECh. 15.4 - Prob. 41PECh. 15.4 - Prob. 42PECh. 15.4 - Prob. 43PECh. 15.4 - Prob. 44PECh. 15.4 - Prob. 45PECh. 15.4 - Prob. 46PECh. 15.4 - Prob. 47PECh. 15.4 - Prob. 48PECh. 15.4 - Prob. 49PECh. 15.4 - Prob. 50PECh. 15.4 - Prob. 51PECh. 15.4 - Prob. 52PECh. 15.4 - Prob. 53PECh. 15.4 - Prob. 54PECh. 15.4 - Prob. 55PECh. 15.4 - Prob. 56PECh. 15.4 - Prob. 57PECh. 15.4 - Prob. 58PECh. 15.4 - Prob. 59PECh. 15.4 - Prob. 60PECh. 15.4 - Prob. 61PECh. 15.4 - Prob. 62PECh. 15.5 - Prob. 1SPCh. 15.5 - Prob. 2SPCh. 15.5 - Prob. 3SPCh. 15.5 - Prob. 4SPCh. 15.5 - Prob. 5SPCh. 15.5 - Prob. 6SPCh. 15.5 - Prob. 7SPCh. 15.5 - Prob. 8SPCh. 15.5 - Prob. 9SPCh. 15.5 - Prob. 1PECh. 15.5 - Prob. 2PECh. 15.5 - Prob. 3PECh. 15.5 - Prob. 4PECh. 15.5 - Prob. 5PECh. 15.5 - Prob. 6PECh. 15.5 - Prob. 7PECh. 15.5 - Prob. 8PECh. 15.5 - Prob. 9PECh. 15.5 - Prob. 10PECh. 15.5 - Prob. 11PECh. 15.5 - Prob. 12PECh. 15.5 - Prob. 13PECh. 15.5 - Prob. 14PECh. 15.5 - Prob. 15PECh. 15.5 - Prob. 16PECh. 15.5 - Prob. 17PECh. 15.5 - Prob. 18PECh. 15.5 - Prob. 19PECh. 15.5 - Prob. 20PECh. 15.5 - Prob. 21PECh. 15.5 - Prob. 22PECh. 15.5 - Prob. 23PECh. 15.5 - Prob. 24PECh. 15.5 - Prob. 25PECh. 15.5 - Prob. 26PECh. 15.5 - Prob. 27PECh. 15.5 - Prob. 28PECh. 15.5 - Prob. 29PECh. 15.5 - Prob. 30PECh. 15.5 - Prob. 31PECh. 15.5 - Prob. 32PECh. 15.5 - Prob. 33PECh. 15.5 - Prob. 34PECh. 15.5 - Prob. 35PECh. 15.5 - Prob. 36PECh. 15.5 - Prob. 37PECh. 15.5 - Prob. 38PECh. 15.5 - Prob. 39PECh. 15.5 - Prob. 40PECh. 15.5 - Prob. 41PECh. 15.5 - Prob. 42PECh. 15.5 - Prob. 43PECh. 15.5 - Prob. 44PECh. 15.5 - Prob. 45PECh. 15.5 - Prob. 46PECh. 15.5 - Prob. 47PECh. 15.5 - Prob. 48PECh. 15.5 - Prob. 49PECh. 15.5 - Prob. 50PECh. 15.5 - Prob. 51PECh. 15.5 - Prob. 52PECh. 15.5 - Prob. 53PECh. 15.5 - Prob. 54PECh. 15.5 - Prob. 55PECh. 15.5 - Prob. 56PECh. 15.5 - Prob. 57PECh. 15.5 - Prob. 58PECh. 15.5 - Prob. 59PECh. 15.5 - Prob. 60PECh. 15.5 - Prob. 61PECh. 15.5 - Prob. 62PECh. 15.5 - Prob. 63PECh. 15.5 - Prob. 64PECh. 15.5 - Prob. 65PECh. 15.5 - Prob. 66PECh. 15.5 - Prob. 67PECh. 15.5 - Prob. 68PECh. 15.5 - Prob. 69PECh. 15.5 - Prob. 70PECh. 15.5 - Prob. 71PECh. 15.5 - Prob. 72PECh. 15.6 - Prob. 1SPCh. 15.6 - Prob. 2SPCh. 15.6 - Prob. 3SPCh. 15.6 - Prob. 4SPCh. 15.6 - Prob. 5SPCh. 15.6 - Prob. 6SPCh. 15.6 - Prob. 7SPCh. 15.6 - Prob. 8SPCh. 15.6 - Prob. 9SPCh. 15.6 - Prob. 10SPCh. 15.6 - Prob. 11SPCh. 15.6 - Prob. 1PECh. 15.6 - Prob. 2PECh. 15.6 - Prob. 3PECh. 15.6 - Prob. 4PECh. 15.6 - Prob. 5PECh. 15.6 - Prob. 6PECh. 15.6 - Prob. 7PECh. 15.6 - Prob. 8PECh. 15.6 - Prob. 9PECh. 15.6 - Prob. 10PECh. 15.6 - Prob. 11PECh. 15.6 - Prob. 12PECh. 15.6 - Prob. 13PECh. 15.6 - Prob. 14PECh. 15.6 - Prob. 15PECh. 15.6 - Prob. 16PECh. 15.6 - Prob. 17PECh. 15.6 - Prob. 18PECh. 15.6 - Prob. 19PECh. 15.6 - Prob. 20PECh. 15.6 - Prob. 21PECh. 15.6 - Prob. 22PECh. 15.6 - Prob. 23PECh. 15.6 - Prob. 24PECh. 15.6 - Prob. 25PECh. 15.6 - Prob. 26PECh. 15.6 - Prob. 27PECh. 15.6 - Prob. 28PECh. 15.6 - 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Prob. 29PECh. 15.9 - Prob. 30PECh. 15.9 - Prob. 31PECh. 15.9 - Prob. 32PECh. 15.9 - Prob. 33PECh. 15.9 - Prob. 34PECh. 15.9 - Prob. 35PECh. 15.9 - Prob. 36PECh. 15.9 - Prob. 37PECh. 15.9 - Prob. 38PECh. 15.9 - Prob. 39PECh. 15.9 - Prob. 40PECh. 15.9 - Prob. 41PECh. 15.9 - Prob. 42PECh. 15.9 - Prob. 43PECh. 15.9 - Prob. 44PECh. 15.9 - Prob. 45PECh. 15.9 - Prob. 46PECh. 15.9 - Prob. 47PECh. 15.9 - Prob. 48PECh. 15.9 - Prob. 49PECh. 15.9 - Prob. 50PECh. 15.9 - Prob. 51PECh. 15.9 - Prob. 52PECh. 15.9 - Prob. 53PECh. 15.9 - Prob. 54PECh. 15.9 - Prob. 55PECh. 15.9 - Prob. 56PECh. 15.9 - Prob. 57PECh. 15.9 - Prob. 58PECh. 15.9 - Prob. 59PECh. 15.9 - Prob. 60PE
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- show that v3 = (−√3, −3, 3)⊤ is an eigenvector of M3 . Also here find the correspondingeigenvalue λ3 . Just from looking at M3 and its components, can you say something about the remaining twoeigenvalues? If so, what would you say? find v42 so that v4 = ( 2/5, v42, 1)⊤ is an eigenvector of M4 with corresp. eigenvalue λ4 = 45arrow_forwardChapter 4 Quiz 2 As always, show your work. 1) FindΘgivencscΘ=1.045. 2) Find Θ given sec Θ = 4.213. 3) Find Θ given cot Θ = 0.579. Solve the following three right triangles. B 21.0 34.6° ca 52.5 4)c 26° 5) A b 6) B 84.0 a 42° barrow_forwardQ1: A: Let M and N be two subspace of finite dimension linear space X, show that if M = N then dim M = dim N but the converse need not to be true. B: Let A and B two balanced subsets of a linear space X, show that whether An B and AUB are balanced sets or nor. Q2: Answer only two A:Let M be a subset of a linear space X, show that M is a hyperplane of X iff there exists ƒ€ X'/{0} and a € F such that M = (x = x/f&x) = x}. fe B:Show that every two norms on finite dimension linear space are equivalent C: Let f be a linear function from a normed space X in to a normed space Y, show that continuous at x, E X iff for any sequence (x) in X converge to Xo then the sequence (f(x)) converge to (f(x)) in Y. Q3: A:Let M be a closed subspace of a normed space X, constract a linear space X/M as normed space B: Let A be a finite dimension subspace of a Banach space X, show that A is closed. C: Show that every finite dimension normed space is Banach space.arrow_forward
- • Plane II is spanned by the vectors: P12 P2 = 1 • Subspace W is spanned by the vectors: W₁ = -- () · 2 1 W2 = 0arrow_forwardThree streams - Stream A, Stream B, and Stream C - flow into a lake. The flow rates of these streams are not yet known and thus to be found. The combined water inflow from the streams is 300 m³/h. The rate of Stream A is three times the combined rates of Stream B and Stream C. The rate of Stream B is 50 m³/h less than half of the difference between the rates of Stream A and Stream C. Find the flow rates of the three streams by setting up an equation system Ax = b and solving it for x. Provide the values of A and b. Assuming that you get to an upper-triangular matrix U using an elimination matrix E such that U = E A, provide also the components of E.arrow_forwarddent Application X GA spinner is divided into five cox | + 9/26583471/4081d162951bfdf39e254aa2151384b7 A spinner is divided into five colored sections that are not of equal size: red, blue, green, yellow, and purple. The spinner is spun several times, and the results are recorded below: Spinner Results Color Frequency Red 5 Blue 11 Green 18 Yellow 5 Purple 7 Based on these results, express the probability that the next spin will land on purple as a fraction in simplest form. Answer Attempt 1 out of 2 Submit Answer 0 Feb 12 10:11 Oarrow_forward
- A student completed the problem below. Identify whether the student was correct or incorrect. Explain your reasoning. (identification 1 point; explanation 1 point) 4x 3x (x+7)(x+5)(x+7)(x-3) 4x (x-3) (x+7)(x+5) (x03) 3x (x+5) (x+7) (x-3)(x+5) 4x²-12x-3x²-15x (x+7) (x+5) (x-3) 2 × - 27x (x+7)(x+5) (x-3)arrow_forward2 Add the rational expressions below. Can you add them in this original form? Explain why or why not. 3x-7 5x + x² - 7x+12 4x-12 Show all steps. State your least common denominator and explain in words your process on how you determined your least common denominator. Be sure to state your claim, provide your evidence, and provide your reasoning before submitting.arrow_forwardcarol mailed a gift box to her sister the boxed gift weighed a total of 2 pounds the box alone weighed 13 ounces what was the wright of the giftarrow_forward
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