Midpoint Rule for Triple Integrals In the Midpoint Rule for triple integrals we use a triple Riemann sum to approximate a triple integral over a box B , where f ( x , y , z ) is evaluated at the center x ¯ i , y ¯ j , z ¯ k of the box B i j k . Use the Midpoint Rule to estimate the value of the integral. Divide B into eight sub-boxes of equal size. 29. ∭ B cos ( x y z ) d V , where B = { ( x , y , z ) ∣ 0 ⩽ x ⩽ 1 , 0 ⩽ y ⩽ 1 , 0 ⩽ z ⩽ 1 }
Midpoint Rule for Triple Integrals In the Midpoint Rule for triple integrals we use a triple Riemann sum to approximate a triple integral over a box B , where f ( x , y , z ) is evaluated at the center x ¯ i , y ¯ j , z ¯ k of the box B i j k . Use the Midpoint Rule to estimate the value of the integral. Divide B into eight sub-boxes of equal size. 29. ∭ B cos ( x y z ) d V , where B = { ( x , y , z ) ∣ 0 ⩽ x ⩽ 1 , 0 ⩽ y ⩽ 1 , 0 ⩽ z ⩽ 1 }
Solution Summary: The author evaluates the value of the triple integral by dividing B into eight sub-boxes of equal size.
Midpoint Rule for Triple Integrals In the Midpoint Rule for triple integrals we use a triple Riemann sum to approximate a triple integral over a box
B
, where
f
(
x
,
y
,
z
)
is evaluated at the center
x
¯
i
,
y
¯
j
,
z
¯
k
of the box
B
i
j
k
. Use the Midpoint Rule to estimate the value of the integral. Divide
B
into eight sub-boxes of equal size.
29.
∭
B
cos
(
x
y
z
)
d
V
, where
B
=
{
(
x
,
y
,
z
)
∣
0
⩽
x
⩽
1
,
0
⩽
y
⩽
1
,
0
⩽
z
⩽
1
}
With differentiation, one of the major concepts of calculus. Integration involves the calculation of an integral, which is useful to find many quantities such as areas, volumes, and displacement.
Use Euler's method to numerically integrate
dy
dx
-2x+12x² - 20x +8.5
from x=0 to x=4 with a step size of 0.5. The initial condition at x=0 is y=1. Recall
that the exact solution is given by y = -0.5x+4x³- 10x² + 8.5x+1
Find an equation of the line tangent to the graph of f(x) = (5x-9)(x+4) at (2,6).
Find the point on the graph of the given function at which the slope of the tangent line is the given slope.
2
f(x)=8x²+4x-7; slope of the tangent line = -3
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