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Proof In Exercises 51 and 52, prove the identity, where R is a simply connected region with piecewise smooth boundary C. Assume that the required partial derivatives of the scalar functions f and g are continuous. The expressions
Green’s second identity:
(Hint: Use Green’s first identity from Exercise 51 twice.)
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CALCULUS EARLY TRANSCENDENTAL FUNCTIONS
- 2. Suppose that U(x, y, z) = x² + y²+ z² represents the temperature of a 3-dimensional solid object at any point (x, y, z). Then F(x, y, z) = -KVU (x, y, z) represents the heat flow at (x, y, z) where K > 0 is called the conductivity constant and the negative sign indicates that the heat moves from higher temperature region into lower temperature region. Answer the following questions. (A) [90%] Compute the inward heat flux (i.e., the inward flux of F) across the surface z = 1 - x² - y². (B) [10%] Use the differential operator(s) to determine if the heat flow is rotational or irrotational.arrow_forwardCould you show why the answer is B Using polar coordinates and the area formulaarrow_forward1. The parametric equations x = u, y = u cos v, z = usin v, with Ou≤ 2, 0 ≤ v ≤ 2π represent the cone that is obtained by revolving (about x-axis) the line y = x (for 0 ≤ x ≤2) in the xy-plane. Answer the following questions. (A) [50%] Sketch the cone and compute its surface area, which is given by dS = [ | Ər Or ди მა × du dv with S being the cone surface and D being the projection of S on the uv-plane. (B) [50%] Suppose that the density of the thin cone is σ(x, y, z) = 0.25x gr/cm². Compute the total mass of the cone.arrow_forward
- The value of sin (2V · F) at x = 3, y = 3, z = −4, where F -0.592 -0.724 0.661 -0.113 -0.822 -0.313 0.171 0.427 = (-2x² + -4,2yz − x − 3, −5xz - 2yz), isarrow_forwardThe correct answer is C Could you show me whyarrow_forwardThe graph of f(x) is given below. Select each true statement about the continuity of f(x) at x = -4. Select all that apply: ☐ f(x) is not continuous at x = -4 because it is not defined at x = −4. ☐ f(x) is not continuous at x = -4 because lim f(x) does not exist. x-4 f(x) is not continuous at x = -4 because lim f(x) = f(−4). ☐ f(x) is continuous at x = -4. x-4 ين من طلب نہ 1 2 3 4 5 6 7arrow_forward
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