Foundations of Materials Science and Engineering
Foundations of Materials Science and Engineering
6th Edition
ISBN: 9781259696558
Author: SMITH
Publisher: MCG
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Chapter 15.10, Problem 40AAP

(a)

To determine

The minimum wavelength of the radiation absorbed by GaP material.

(a)

Expert Solution
Check Mark

Answer to Problem 40AAP

The minimum wavelength of the radiation absorbed by GaP material is 0.552μm.

Explanation of Solution

Write the equation to calculate the minimum wavelength of the radiation (λ).

 λ=hcEg                                                                                                                   (I)

Here, energy band gap of the material is Eg, Planck's constant is h and speed of light is c.

Conclusion:

The values of Planck constant and speed of light are 6.63×1034Js and 3×108m/s respectively.

Refer Table 14.6, "Electrical properties of intrinsic semiconducting compounds at room temperature", select the energy band gap of the GaP material.

  Eg=2.25eV

Substitute 2.25eV for Eg, 6.63×1034Js for h and 3×108m/s for c in Equation (I).

 λ=(6.63×1034Js)(3×108m/s)2.25eV=(6.63×1034Js)(3×108m/s)(2.25eV×1.602×1019J1eV)=5.52×107m=0.552μm

Thus, the minimum wavelength of the radiation absorbed by GaP material is 0.552μm.

(b)

To determine

The minimum wavelength of the radiation absorbed by GaSb material.

(b)

Expert Solution
Check Mark

Answer to Problem 40AAP

The minimum wavelength of the radiation absorbed by GaSb material is 1.83μm.

Explanation of Solution

Conclusion:

Refer Table 14.6, "Electrical properties of intrinsic semiconducting compounds at room temperature", select the energy band gap of the GaSb material.

  Eg=0.68eV

Substitute 0.68eV for Eg, 6.63×1034Js for h and 3×108m/s for c in Equation (I).

 λ=(6.63×1034Js)(3×108m/s)0.68eV=(6.63×1034Js)(3×108m/s)(0.68eV×1.602×1019J1eV)=1.83×106m=1.83μm

Thus, the minimum wavelength of the radiation absorbed by GaSb material is 1.83μm.

(c)

To determine

The minimum wavelength of the radiation absorbed by InP material.

(c)

Expert Solution
Check Mark

Answer to Problem 40AAP

The minimum wavelength of the radiation absorbed by InP material is 0.98μm.

Explanation of Solution

Conclusion:

Refer Table 14.6, "Electrical properties of intrinsic semiconducting compounds at room temperature", select the energy band gap of the InP material.

  Eg=1.27eV

Substitute 1.27eV for Eg, 6.63×1034Js for h and 3×108m/s for c in Equation (I).

 λ=(6.63×1034Js)(3×108m/s)1.27eV=(6.63×1034Js)(3×108m/s)(1.27eV×1.602×1019J1eV)=9.77×107m=0.98μm

Thus, the minimum wavelength of the radiation absorbed by InP material is 0.98μm.

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Foundations of Materials Science and Engineering

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