Explanation Given: f ( x , y ) = y 1 + x y Concept used: By substituting 1 + x y = t and treating ‘ y’ as constant then, 1 + x y = To determine (b) Evaluate ∫ ∫ R y 1 + x y d A , where R = [ 0 , 1 ] × [ 01 , ]

4th Edition

ISBN: 9781319055905

Author: FRANZOSA

Publisher: VST

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Chapter 15.1, Problem 49E

To determine

(a)

Which is easier, anti-differentiating y1+xy with respect to ‘ x’ or with respect to ‘ y’ ?

To determine

(b)

Evaluate ∫∫Ry1+xydA, where R=[0,1]×[01,]

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Chapter 15.1, Problem 48E

Chapter 15.1, Problem 50E

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Chapter 15 Solutions

EBK CALCULUS: EARLY TRANSCENDENTALS

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(a) Which is easier, anti-differentiating y 1 + x y with respect to ‘ x’ or with respect to ‘ y’ ?

Solution Summary: The author compares the two formulas: anti-differentiating y1+xy with respect to ‘x’ and treating ‘y’ as constant.

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(a)

Which is easier, anti-differentiating y1+xy with respect to ‘ x’ or with respect to ‘ y’ ?

(b)

Evaluate ∫∫Ry1+xydA, where R=[0,1]×[01,]

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Chapter 15 Solutions

(a) Which is easier, anti-differentiating y 1 + x y with respect to ‘ x’ or with respect to ‘ y’ ?

Solution Summary: The author compares the two formulas: anti-differentiating y1+xy with respect to ‘x’ and treating ‘y’ as constant.

Concept explainers

Videos

(a) Which is easier, anti-differentiating y1+xy with respect to ‘ x’ or with respect to ‘ y’ ?

(b) Evaluate ∫∫Ry1+xydA, where R=[0,1]×[01,]

Want to see the full answer?

Chapter 15 Solutions

(a)

Which is easier, anti-differentiating y1+xy with respect to ‘ x’ or with respect to ‘ y’ ?

(b)

Evaluate ∫∫Ry1+xydA, where R=[0,1]×[01,]