Pearson eText Basic Chemistry -- Instant Access (Pearson+)
6th Edition
ISBN: 9780135765982
Author: Karen Timberlake, William Timberlake
Publisher: PEARSON+
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 15.1, Problem 17PP
(a)
Interpretation Introduction
Interpretation: For the following reaction, identify the substances that is oxidized, the substance that is reduced, the oxidizing agent, and the reducing agent.
Concept Introduction: In an oxidation reaction the oxidation number of the element increase or becomes more positive. In a reduction reaction the oxidation number of the element decrease or becomes more negative.
The rules for assigning oxidation number to elements are:
- For an element in its free state it is assigned an oxidation number of zero.
- Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
- Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
- In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
- For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.
(b)
Interpretation Introduction
Interpretation: For the following reaction, identify the substances that is oxidized, the substance that is reduced, the oxidizing agent, and the reducing agent.
Concept Introduction: In an oxidation reaction the oxidation number of the element increase or becomes more positive. In a reduction reaction the oxidation number of the element decrease or becomes more negative.
The rules for assigning oxidation number to elements are:
- For an element in its free state it is assigned an oxidation number of zero.
- Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
- Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
- In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
- For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.
(c)
Interpretation Introduction
Interpretation: For the following reaction, identify the substances that is oxidized, the substance that is reduced, the oxidizing agent, and the reducing agent.
Concept Introduction: In an oxidation reaction the oxidation number of the element increase or becomes more positive. In a reduction reaction the oxidation number of the element decrease or becomes more negative.
The rules for assigning oxidation number to elements are:
- For an element in its free state it is assigned an oxidation number of zero.
- Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
- Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
- In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
- For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.
(d)
Interpretation Introduction
Interpretation: For the following reaction, identify the substances that is oxidized, the substance that is reduced, the oxidizing agent, and the reducing agent.
Concept Introduction: In an oxidation reaction the oxidation number of the element increase or becomes more positive. In a reduction reaction the oxidation number of the element decrease or becomes more negative.
The rules for assigning oxidation number to elements are:
- For an element in its free state it is assigned an oxidation number of zero.
- Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
- Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
- In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
- For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Bookmarks
Profiles Tab Window Help
Chemical Formula - Aktiv Che X
+
→ C
11
a
app.aktiv.com
Google Chrome isn't your default browser Set as default
Question 12 of 16
Q Fri Feb 2
Verify it's you
New Chrome availabl-
Write the balanced molecular chemical equation for the reaction in aqueous solution for
mercury(I) nitrate and chromium(VI) sulfate. If no reaction occurs, simply write only NR. Be
sure to include the proper phases for all species within the reaction.
3 Hg(NO3)2(aq) + Cг2(SO4)3(aq) → 3 Hg₂SO (s) + 2 Cr(NO3), (aq)
ean Ui
mate co
ence an
climate
bility inc
ulnerabili
women,
main critic
CLIMATE-INI
ernational
+
10
O
2
W
FEB
1
+
4-
3-
2-
2
2
(
3
4
NS
28
2
ty
56
+
2+
3+
4+
7
8
9 0
5
(s)
(1)
Ch
O
8
9
(g) (aq)
Hg
NR
CI
Cr
x H₂O
A
80
Q
A
DII
A
F2
F3
FA
F5
F6
F7
F8
F9
#3
EA
$
do 50
%
6
CO
&
7
E
R
T
Y
U
8
(
9
0
F10
34
F11
川
F12
Subr
+
delete
0
{
P
}
Deducing the reactants of a Diels-Alder reaction
n the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one
step, by moderately heating the reactants?
?
Δ
• If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any
arrangement you like.
• If your answer is no, check the box under the drawing area instead.
Explanation Check
Click and drag to start drawing a structure.
>
Predict the major products of the following organic reaction:
+
Some important notes:
A
?
• Draw the major product, or products, of the reaction in the drawing area below.
• If there aren't any products, because no reaction will take place, check the box below the drawing area instead.
• Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are
enantiomers.
Explanation
Check
Click and drag to start drawing a structure.
Chapter 15 Solutions
Pearson eText Basic Chemistry -- Instant Access (Pearson+)
Ch. 15.1 - Identify each of the following as an oxidation or...Ch. 15.1 - Identify each of the following as an oxidation or...Ch. 15.1 - Prob. 3PPCh. 15.1 - Prob. 4PPCh. 15.1 - Prob. 5PPCh. 15.1 - Prob. 6PPCh. 15.1 - Prob. 7PPCh. 15.1 - Prob. 8PPCh. 15.1 - Prob. 9PPCh. 15.1 - Prob. 10PP
Ch. 15.1 - Prob. 11PPCh. 15.1 - Prob. 12PPCh. 15.1 - What is the oxidation number of the specified...Ch. 15.1 - What is the oxidation number of the specified...Ch. 15.1 - Prob. 15PPCh. 15.1 - Prob. 16PPCh. 15.1 - Prob. 17PPCh. 15.1 - Prob. 18PPCh. 15.1 - Prob. 19PPCh. 15.1 - Prob. 20PPCh. 15.2 - Balance each of the following half-reactions in...Ch. 15.2 - Prob. 22PPCh. 15.2 - Prob. 23PPCh. 15.2 - Use the half-reaction method to balance each of...Ch. 15.2 - Use the half-reaction method to balance each of...Ch. 15.2 - Use the half-reaction method to balance each of...Ch. 15.3 - Use the activity series in Table 15.3 to predict...Ch. 15.3 - Use the activity series in Table 15.3 to predict...Ch. 15.3 - Prob. 29PPCh. 15.3 - Prob. 30PPCh. 15.3 - Prob. 31PPCh. 15.3 - Prob. 32PPCh. 15.3 - The following half-reaction takes place in a...Ch. 15.3 - The following half-reaction takes place in a...Ch. 15.3 - The following half-reaction takes place in a...Ch. 15.3 - Prob. 36PPCh. 15.4 - What we call "tin cans" are really iron cans...Ch. 15.4 - Prob. 38PPCh. 15.4 - Prob. 39PPCh. 15.4 - Prob. 40PPCh. 15.4 - Prob. 41PPCh. 15.4 - Prob. 42PPCh. 15 - Prob. 43UTCCh. 15 - Prob. 44UTCCh. 15 - Prob. 45UTCCh. 15 - Prob. 46UTCCh. 15 - The chapter sections to review are shown in...Ch. 15 - The chapter sections to review are shown in...Ch. 15 - The chapter sections to review are shown in...Ch. 15 - Prob. 50UTCCh. 15 - Prob. 51UTCCh. 15 - Prob. 52UTCCh. 15 - The chapter sections to review are shown in...Ch. 15 - The chapter sections to review are shown in...Ch. 15 - Which of the following are oxidation-reduction...Ch. 15 - Which of the following are oxidation-reduction...Ch. 15 - In the mitochondria of human cells, energy is...Ch. 15 - Prob. 58APPCh. 15 - Prob. 59APPCh. 15 - Prob. 60APPCh. 15 - Prob. 61APPCh. 15 - Prob. 62APPCh. 15 - Prob. 63APPCh. 15 - Write the balanced half-reactions and a balanced...Ch. 15 - Prob. 65APPCh. 15 - Use the activity series in Table 15.3 to predict...Ch. 15 - Prob. 67APPCh. 15 - Prob. 68APPCh. 15 - Prob. 69APPCh. 15 - Prob. 70APPCh. 15 - Prob. 71APPCh. 15 - In an acidic dry-cell battery, the following...Ch. 15 - Steel bolts made for sailboats are coated with...Ch. 15 - Copper cooking pans are stainless steel pans...Ch. 15 - Prob. 75CPCh. 15 - Prob. 76CPCh. 15 - Prob. 77CPCh. 15 - The following problems are related to the topics...Ch. 15 - The following problems are related to the topics...Ch. 15 - The following problems are related to the topics...Ch. 15 - Prob. 81CPCh. 15 - Prob. 82CPCh. 15 - Prob. 83CPCh. 15 - Prob. 84CPCh. 15 - Prob. 85CPCh. 15 - Prob. 86CPCh. 15 - Prob. 87CPCh. 15 - Prob. 88CP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- if the answer is no reaction than state that and please hand draw!arrow_forward"I have written solutions in text form, but I need experts to rewrite them in handwriting from A to Z, exactly as I have written, without any changes."arrow_forwardDon't used hand raiting and don't used Ai solutionarrow_forward
- Please correct answer and don't used hand raitingarrow_forwardreciprocal lattices rotates along with the real space lattices of the crystal. true or false?arrow_forwardDeducing the reactants of a Diels-Alder reaction vn the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ O If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. • If your answer is no, check the box under the drawing area instead. Click and drag to start drawing a structure. Product can't be made in one step. Explanation Checkarrow_forward
- Predict the major products of the following organic reaction: Δ ? Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. Explanation Check Click and drag to start drawing a structure. Larrow_forward> Can the molecule on the right-hand side of this organic reaction be made in good yield from no more than two reactants, in one step, by moderately heating the reactants? ? Δ • If your answer is yes, then draw the reactant or reactants in the drawing area below. You can draw the reactants in any arrangement you like. If your answer is no, check the box under the drawing area instead. Explanation Check Click and drag to start drawing a structure. Х © 2025 McGraw Hill LLC. All Rights Reserved. Terms of Use | Privacy Center | Accesarrow_forwardPredict the major products of the following organic reaction: O O + A ? Some important notes: • Draw the major product, or products, of the reaction in the drawing area below. • If there aren't any products, because no reaction will take place, check the box below the drawing area instead. • Be sure to use wedge and dash bonds when necessary, for example to distinguish between major products that are enantiomers. Explanation Check Click and drag to start drawing a structure. eserved. Terms of Use | Privacy Center >arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Chemistry & Chemical ReactivityChemistryISBN:9781337399074Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Chemistry & Chemical ReactivityChemistryISBN:9781133949640Author:John C. Kotz, Paul M. Treichel, John Townsend, David TreichelPublisher:Cengage Learning
Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage Learning
Chemistry: An Atoms First ApproachChemistryISBN:9781305079243Author:Steven S. Zumdahl, Susan A. ZumdahlPublisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781337399074
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry & Chemical Reactivity
Chemistry
ISBN:9781133949640
Author:John C. Kotz, Paul M. Treichel, John Townsend, David Treichel
Publisher:Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Chemistry
Chemistry
ISBN:9781305957404
Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCoste
Publisher:Cengage Learning
Chemistry: An Atoms First Approach
Chemistry
ISBN:9781305079243
Author:Steven S. Zumdahl, Susan A. Zumdahl
Publisher:Cengage Learning
Introduction to Electrochemistry; Author: Tyler DeWitt;https://www.youtube.com/watch?v=teTkvUtW4SA;License: Standard YouTube License, CC-BY