EP BASIC CHEMISTRY-MODIFIED MASTERING
6th Edition
ISBN: 9780137452392
Author: Timberlake
Publisher: SAVVAS L
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Question
Chapter 15.1, Problem 12PP
(a)
Interpretation Introduction
Interpretation: Assign oxidation numbers to all of the elements in the following:
N2O
Concept Introduction: The rules for assigning oxidation number to elements are:
- For an element in its free state it is assigned an oxidation number of zero.
- Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
- Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
- In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
- For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.
If the oxidation number of an element increases then it undergoes oxidation and if the oxidation number of the element decreases then it undergoes reduction.
(b)
Interpretation Introduction
Interpretation: Assign oxidation numbers to all of the elements in each of the following:
LiOH
Concept Introduction: The rules for assigning oxidation number to elements are:
- For an element in its free state it is assigned an oxidation number of zero.
- Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
- Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
- In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
- For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.
If the oxidation number of an element increases then it undergoes oxidation and if the oxidation number of the element decreases then it undergoes reduction.
(c)
Interpretation Introduction
Interpretation: Assign oxidation numbers to all of the elements in each of the following:
SbO2-
Concept Introduction: The rules for assigning oxidation number to elements are:
- For an element in its free state it is assigned an oxidation number of zero.
- Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
- Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
- In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
- For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.
If the oxidation number of an element increases then it undergoes oxidation and if the oxidation number of the element decreases then it undergoes reduction.
(d)
Interpretation Introduction
Interpretation: Assign oxidation numbers to all of the elements in each of the following:
IO4-
Concept Introduction: The rules for assigning oxidation number to elements are:
- For an element in its free state it is assigned an oxidation number of zero.
- Monatomic ions have oxidation number that is equal to charge of the monatomic ion.
- Alkali metals have +1 oxidation number, alkaline earth metals have +2 oxidation number and halogens are assigned -1 oxidation number.
- In most compounds H is assigned a +1 oxidation number and O is assigned a -2 oxidation number.
- For a neutral compound the summation of oxidation numbers of all elements in the compound is zero.
If the oxidation number of an element increases then it undergoes oxidation and if the oxidation number of the element decreases then it undergoes reduction.
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A solution contains 0.097 M Ce3+, 1.55x10-3 M Ce4+, 1.55x10-3 M Mn2+, 0.097 M MnO4-, and 1.00 M HClO4 (F= 9.649 x 104 C/mol).
a) Write a balanced net reaction that can occur between species in this solution.
b) Calculate deltaG0 and K for the reaction.
c) Calculate E and deltaG for the conditions given.
Ce4+ + e- = Ce3+ E0= 1.70 V
MnO4- + 8H+ + 5e- = Mn2+ + 4H2O E0= 1.507 V
1. Provide a step-by-step mechanism for formation of ALL STEREOISOMERS in
the following reaction.
Na HCO3 (Sodium bicarbonate, baking soda) is not soluble in CH2Cl2. The powder is
a weak base used to neutralize strong acid (pKa < 0) produced by the reaction.
Redraw the product to show the configuration(s) that form at C-2 and C-4.
Br2
OH
CH2Cl2
Na* HCO3
Br
HO
OH
+ Na Br +
2. Specify the solvent and reagent(s) required to carry out each of the following FGI. If
two reagent sets must be used for the FGI, specify the solvent and reagent(s) for each
reagent set. If a reaction cannot be carried out with reagents (sets)
class, write NP (not possible) in the solvent box for reagent set #1.
Use the letter abbreviation for each solvent; use a number abbreviation for reagent(s).
Solvents: CH2Cl2 (A);
H₂O (B);
Reagents:
HBr (1);
R₂BH (6);
H2SO4 (2);
CH3OH (C);
Br₂ (3);
CH3CO₂H (D)
NaHCO3 (4);
Hg(OAc)2 (5);
H₂O2/HO (7);
NaBH4 (8)
Reagent Set #1
Reagent Set #2
FGI
+ enant
OH
Solvent Reagent(s) Solvent Reagent(s)
Chapter 15 Solutions
EP BASIC CHEMISTRY-MODIFIED MASTERING
Ch. 15.1 - Identify each of the following as an oxidation or...Ch. 15.1 - Identify each of the following as an oxidation or...Ch. 15.1 - Prob. 3PPCh. 15.1 - Prob. 4PPCh. 15.1 - Prob. 5PPCh. 15.1 - Prob. 6PPCh. 15.1 - Prob. 7PPCh. 15.1 - Prob. 8PPCh. 15.1 - Prob. 9PPCh. 15.1 - Prob. 10PP
Ch. 15.1 - Prob. 11PPCh. 15.1 - Prob. 12PPCh. 15.1 - What is the oxidation number of the specified...Ch. 15.1 - What is the oxidation number of the specified...Ch. 15.1 - Prob. 15PPCh. 15.1 - Prob. 16PPCh. 15.1 - Prob. 17PPCh. 15.1 - Prob. 18PPCh. 15.1 - Prob. 19PPCh. 15.1 - Prob. 20PPCh. 15.2 - Balance each of the following half-reactions in...Ch. 15.2 - Prob. 22PPCh. 15.2 - Prob. 23PPCh. 15.2 - Use the half-reaction method to balance each of...Ch. 15.2 - Use the half-reaction method to balance each of...Ch. 15.2 - Use the half-reaction method to balance each of...Ch. 15.3 - Use the activity series in Table 15.3 to predict...Ch. 15.3 - Use the activity series in Table 15.3 to predict...Ch. 15.3 - Prob. 29PPCh. 15.3 - Prob. 30PPCh. 15.3 - Prob. 31PPCh. 15.3 - Prob. 32PPCh. 15.3 - The following half-reaction takes place in a...Ch. 15.3 - The following half-reaction takes place in a...Ch. 15.3 - The following half-reaction takes place in a...Ch. 15.3 - Prob. 36PPCh. 15.4 - What we call "tin cans" are really iron cans...Ch. 15.4 - Prob. 38PPCh. 15.4 - Prob. 39PPCh. 15.4 - Prob. 40PPCh. 15.4 - Prob. 41PPCh. 15.4 - Prob. 42PPCh. 15 - Prob. 43UTCCh. 15 - Prob. 44UTCCh. 15 - Prob. 45UTCCh. 15 - Prob. 46UTCCh. 15 - The chapter sections to review are shown in...Ch. 15 - The chapter sections to review are shown in...Ch. 15 - The chapter sections to review are shown in...Ch. 15 - Prob. 50UTCCh. 15 - Prob. 51UTCCh. 15 - Prob. 52UTCCh. 15 - The chapter sections to review are shown in...Ch. 15 - The chapter sections to review are shown in...Ch. 15 - Which of the following are oxidation-reduction...Ch. 15 - Which of the following are oxidation-reduction...Ch. 15 - In the mitochondria of human cells, energy is...Ch. 15 - Prob. 58APPCh. 15 - Prob. 59APPCh. 15 - Prob. 60APPCh. 15 - Prob. 61APPCh. 15 - Prob. 62APPCh. 15 - Prob. 63APPCh. 15 - Write the balanced half-reactions and a balanced...Ch. 15 - Prob. 65APPCh. 15 - Use the activity series in Table 15.3 to predict...Ch. 15 - Prob. 67APPCh. 15 - Prob. 68APPCh. 15 - Prob. 69APPCh. 15 - Prob. 70APPCh. 15 - Prob. 71APPCh. 15 - In an acidic dry-cell battery, the following...Ch. 15 - Steel bolts made for sailboats are coated with...Ch. 15 - Copper cooking pans are stainless steel pans...Ch. 15 - Prob. 75CPCh. 15 - Prob. 76CPCh. 15 - Prob. 77CPCh. 15 - The following problems are related to the topics...Ch. 15 - The following problems are related to the topics...Ch. 15 - The following problems are related to the topics...Ch. 15 - Prob. 81CPCh. 15 - Prob. 82CPCh. 15 - Prob. 83CPCh. 15 - Prob. 84CPCh. 15 - Prob. 85CPCh. 15 - Prob. 86CPCh. 15 - Prob. 87CPCh. 15 - Prob. 88CP
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