(a) Explanation Given Info: The density of the raw milk is 1023 kg / m 3 , the depth of the tank up to the milk is filled is 1.8 m and the pressure at height h is the atmospheric pressure. The value of the atmospheric pressure is 1.01 × 10 5 Pa . The acceleration due to gravity is 9.8 m / s 2 . The pressure difference in any liquid is expressed in terms of pressure in terms of meters of mercury as, P 2 − P 1 = 760 mmHg Here, P 1 is the pressure at location 1 . P 2 is the pressure at location 2 . From the Bernoulli’s equation: P 1 + 1 2 ρ ( v 1 ) 2 + ρ g h 1 = P 2 + 1 2 ρ ( v 2 ) 2 + ρ g h 2 Here, v 1 is speed of the milk at location 1 . h 1 is the height of location 1 . v 2 is speed of the milk at location 2 . h 2 is the height of location 2 . ρ is the density of the milk. The speed of the milk at location 2 is zero as it is at rest and the height of location 1 is zero from ground level. Substitute 0 for h 1 and 0 for v 2 in the above equation. P 1 + 1 2 ρ ( v 1 ) 2 + ρ g 0 = P 2 + 1 2 ρ 0 2 + ρ g h 2 P 1 + 1 2 ρ ( v 1 ) 2 = P 2 + ρ g h 2 ( v 1 ) = 2 ( P 2 − P 1 ρ ) + 2 ( g h 2 ) Substitute 760 mmHg for P 2 − P 1 , 1023 kg / m 3 for ρ , 1 (b) To determine The pressure at the bottom of the tank.

5th Edition

ISBN: 9780321976444

Author: James S. Walker

Publisher: PEARSON

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Question

Chapter 15, Problem 95GP

(a)

To determine

The minimum speed v1 of the milk to enter the tank.

(b)

To determine

The pressure at the bottom of the tank.

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Chapter 15, Problem 94GP

Chapter 15, Problem 96GP

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The minimum speed v 1 of the milk to enter the tank.

Solution Summary: The author calculates the minimum speed of the milk to enter the tank. The value of atmospheric pressure is 1.01times 105Pa.

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The minimum speed v1 of the milk to enter the tank.

The pressure at the bottom of the tank.

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Chapter 15 Solutions