INTRO TO CHEMISTRY EBK ACCESS CARD >I<
5th Edition
ISBN: 9781260916430
Author: BAUER
Publisher: MCG
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 15, Problem 83QP
Interpretation Introduction
Interpretation:
The reason so as to why the heat of fission reaction is used directly to create steam to operate a turbine is to be stated.
Concept Introduction:
Some of the heavy radioactive nuclides are very unstable. They undergo decay in two ways, one is alpha decay and another is splitting of the nucleus and releasing a large amount of energy. Again, some of the heavy nuclides do not undergo fission spontaneously, but will undergo if irradiated or bombarded with suitable particle like neutron. Splitting of heavy radioactive nuclides into two or more nucleus with some number of neutrons is called fission reaction. The nuclear waste is the material that nuclear fuel becomes after its use in a fission reactor.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
5
What would the complete ionic reaction be if aqueous solutions of potassium sulfate and barium acetate were mixed?
ed
of
Select one:
O a
2 K SO4 + Ba2 +2 C₂H3O21
K+SO4 + Ba2+ + 2 C2H3O21
K+SO42 + Ba2 +2 C2H3O2
BaSO4 +2 K+ + 2 C2H3O
estion
Ob.
O c.
Od.
2 K SO4 +Ba2 +2 C₂H₂O₂
BaSO4 + K+ + 2 C2H3O
BaSO4 + K + 2 C2H301
→Ba² +SO42 +2 KC2H3O
s page
(28 pts.) 7. Propose a synthesis for each of the following transformations. You must include the
reagents and product(s) for each step to receive full credit. The number of steps is provided.
(OC 4)
4 steps
4 steps
OH
b.
LTS
Solid:
AT=Te-Ti
Trial 1
Trial 2
Trial 3
Average
ΔΗ
Mass water, g
24.096
23.976
23.975
Moles of solid, mol
0.01763
001767
0101781
Temp. change, °C
2.9°C
11700
2.0°C
Heat of reaction, J
-292.37J -170.473
-193.26J
AH, kJ/mole
16.58K 9.647 kJ 10.85 kr
16.58K59.64701
KJ
mol
12.35k
Minimum AS,
J/mol K
41.582
mol-k
Remember: q = mCsAT (m = mass of water, Cs=4.184J/g°C) & qsin =-qrxn &
Show your calculations for:
AH in J and then in kJ/mole for Trial 1:
qa (24.0969)(4.1845/g) (-2.9°C)=-292.37J
qsin =
qrxn =
292.35 292.37J
AH in J = 292.375 0.2923kJ
0.01763m01
=1.65×107
AH in kJ/mol =
=
16.58K
0.01763mol
mol
qrx
Minimum AS in J/mol K (Hint: use the average initial temperature of the three trials, con
Kelvin.)
AS=AHIT
(1.65×10(9.64×103) + (1.0
Jimai
Chapter 15 Solutions
INTRO TO CHEMISTRY EBK ACCESS CARD >I<
Ch. 15 - Prob. 1QCCh. 15 - Prob. 2QCCh. 15 - Prob. 3QCCh. 15 - Prob. 4QCCh. 15 - Prob. 5QCCh. 15 - Prob. 6QCCh. 15 - Prob. 1PPCh. 15 - Prob. 2PPCh. 15 - Prob. 3PPCh. 15 - Prob. 4PP
Ch. 15 - Prob. 5PPCh. 15 - Prob. 6PPCh. 15 - Prob. 7PPCh. 15 - Prob. 8PPCh. 15 - Prob. 9PPCh. 15 - Prob. 10PPCh. 15 - Prob. 11PPCh. 15 - Prob. 1QPCh. 15 - Prob. 2QPCh. 15 - Prob. 3QPCh. 15 - Prob. 4QPCh. 15 - Prob. 5QPCh. 15 - Prob. 6QPCh. 15 - Prob. 7QPCh. 15 - Prob. 8QPCh. 15 - Prob. 9QPCh. 15 - Prob. 10QPCh. 15 - Prob. 11QPCh. 15 - Prob. 12QPCh. 15 - Prob. 13QPCh. 15 - Prob. 14QPCh. 15 - Prob. 15QPCh. 15 - Prob. 16QPCh. 15 - Prob. 17QPCh. 15 - Prob. 18QPCh. 15 - Prob. 19QPCh. 15 - Prob. 20QPCh. 15 - Prob. 21QPCh. 15 - Prob. 22QPCh. 15 - Prob. 23QPCh. 15 - Prob. 24QPCh. 15 - Prob. 25QPCh. 15 - Prob. 26QPCh. 15 - Prob. 27QPCh. 15 - Prob. 28QPCh. 15 - Prob. 29QPCh. 15 - Prob. 30QPCh. 15 - Prob. 31QPCh. 15 - Prob. 32QPCh. 15 - Prob. 33QPCh. 15 - Prob. 34QPCh. 15 - Prob. 35QPCh. 15 - Prob. 36QPCh. 15 - Prob. 37QPCh. 15 - Prob. 38QPCh. 15 - Prob. 39QPCh. 15 - Prob. 40QPCh. 15 - Prob. 41QPCh. 15 - Prob. 42QPCh. 15 - Prob. 43QPCh. 15 - Prob. 44QPCh. 15 - Prob. 45QPCh. 15 - Prob. 46QPCh. 15 - Prob. 47QPCh. 15 - Prob. 48QPCh. 15 - Prob. 49QPCh. 15 - Prob. 50QPCh. 15 - Prob. 51QPCh. 15 - Prob. 52QPCh. 15 - Prob. 53QPCh. 15 - Prob. 54QPCh. 15 - Prob. 55QPCh. 15 - Prob. 56QPCh. 15 - Prob. 57QPCh. 15 - Prob. 58QPCh. 15 - Prob. 59QPCh. 15 - Prob. 60QPCh. 15 - Prob. 61QPCh. 15 - Prob. 62QPCh. 15 - Prob. 63QPCh. 15 - Prob. 64QPCh. 15 - Prob. 65QPCh. 15 - Prob. 66QPCh. 15 - Prob. 67QPCh. 15 - Prob. 68QPCh. 15 - Prob. 69QPCh. 15 - Prob. 70QPCh. 15 - Prob. 73QPCh. 15 - Prob. 74QPCh. 15 - Prob. 75QPCh. 15 - Prob. 76QPCh. 15 - Prob. 77QPCh. 15 - Prob. 78QPCh. 15 - Prob. 79QPCh. 15 - Prob. 80QPCh. 15 - Prob. 81QPCh. 15 - Prob. 82QPCh. 15 - Prob. 83QPCh. 15 - Prob. 84QPCh. 15 - Prob. 85QPCh. 15 - Prob. 86QPCh. 15 - Prob. 87QPCh. 15 - Prob. 88QPCh. 15 - Prob. 89QPCh. 15 - Prob. 90QPCh. 15 - Prob. 91QPCh. 15 - Prob. 92QPCh. 15 - Prob. 93QPCh. 15 - Prob. 94QPCh. 15 - Prob. 95QPCh. 15 - Prob. 96QPCh. 15 - Prob. 97QPCh. 15 - Prob. 98QPCh. 15 - Prob. 99QPCh. 15 - Prob. 100QPCh. 15 - Prob. 101QPCh. 15 - Prob. 102QPCh. 15 - Prob. 103QPCh. 15 - Prob. 104QPCh. 15 - Prob. 105QPCh. 15 - Prob. 106QPCh. 15 - Prob. 107QPCh. 15 - Prob. 108QPCh. 15 - Prob. 109QPCh. 15 - Prob. 110QPCh. 15 - Prob. 111QPCh. 15 - Prob. 112QPCh. 15 - Prob. 113QPCh. 15 - Prob. 114QPCh. 15 - Prob. 115QPCh. 15 - Prob. 116QPCh. 15 - Prob. 117QPCh. 15 - Prob. 118QPCh. 15 - Prob. 119QPCh. 15 - Prob. 120QPCh. 15 - Prob. 121QPCh. 15 - Prob. 122QPCh. 15 - Prob. 123QP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- For the compound: C8H17NO2 Use the following information to come up with a plausible structure: 8 This compound has "carboxylic acid amide" and ether functional groups. The peaks at 1.2ppm are two signals that are overlapping one another. One of the two signals is a doublet that represents 6 hydrogens; the other signal is a quartet that represents 3 hydrogens.arrow_forwardVnk the elements or compounds in the table below in decreasing order of their boiling points. That is, choose 1 next to the substance with the highest bolling point, choose 2 next to the substance with the next highest boiling point, and so on. substance C D chemical symbol, chemical formula or Lewis structure. CH,-N-CH, CH, H H 10: H C-C-H H H H Cale H 10: H-C-C-N-CH, Bri CH, boiling point (C) Сен (C) B (Choosearrow_forwardPlease help me find the 1/Time, Log [I^-] Log [S2O8^2-], Log(time) on the data table. With calculation steps. And the average for runs 1a-1b. Please help me thanks in advance. Will up vote!arrow_forward
- Q1: Answer the questions for the reaction below: ..!! Br OH a) Predict the product(s) of the reaction. b) Is the substrate optically active? Are the product(s) optically active as a mix? c) Draw the curved arrow mechanism for the reaction. d) What happens to the SN1 reaction rate in each of these instances: 1. Change the substrate to Br "CI 2. Change the substrate to 3. Change the solvent from 100% CH3CH2OH to 10% CH3CH2OH + 90% DMF 4. Increase the substrate concentration by 3-fold.arrow_forwardExperiment 27 hates & Mechanisms of Reations Method I visual Clock Reaction A. Concentration effects on reaction Rates Iodine Run [I] mol/L [S₂082] | Time mo/L (SCC) 0.04 54.7 Log 1/ Time Temp Log [ ] 13,20] (time) / [I] 199 20.06 23.0 30.04 0.04 0.04 80.0 22.8 45 40.02 0.04 79.0 21.6 50.08 0.03 51.0 22.4 60-080-02 95.0 23.4 7 0.08 0-01 1970 23.4 8 0.08 0.04 16.1 22.6arrow_forward(15 pts) Consider the molecule B2H6. Generate a molecular orbital diagram but this time using a different approach that draws on your knowledge and ability to put concepts together. First use VSEPR or some other method to make sure you know the ground state structure of the molecule. Next, generate an MO diagram for BH2. Sketch the highest occupied and lowest unoccupied MOs of the BH2 fragment. These are called frontier orbitals. Now use these frontier orbitals as your basis set for producing LGO's for B2H6. Since the BH2 frontier orbitals become the LGOS, you will have to think about what is in the middle of the molecule and treat its basis as well. Do you arrive at the same qualitative MO diagram as is discussed in the book? Sketch the new highest occupied and lowest unoccupied MOs for the molecule (B2H6).arrow_forward
- Q8: Propose an efficient synthesis of cyclopentene from cyclopentane.arrow_forwardQ7: Use compound A-D, design two different ways to synthesize E. Which way is preferred? Please explain. CH3I ONa NaOCH 3 A B C D E OCH3arrow_forwardPredict major product(s) for the following reactions. Note the mechanism(s) of the reactions (SN1, E1, SN2 or E2).arrow_forward
- (10 pts) The density of metallic copper is 8.92 g cm³. The structure of this metal is cubic close-packed. What is the atomic radius of copper in copper metal?arrow_forwardPredict major product(s) for the following reactions. Note the mechanism(s) of the reactions (SN1, E1, SN2 or E2).arrow_forwardPredict major product(s) for the following reactions. Note the mechanism(s) of the reactions (SN1, E1, SN2 or E2).arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Chemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub Co
World of Chemistry, 3rd editionChemistryISBN:9781133109655Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCostePublisher:Brooks / Cole / Cengage Learning
Chemistry: Principles and PracticeChemistryISBN:9780534420123Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward MercerPublisher:Cengage Learning
Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
Living By Chemistry: First Edition TextbookChemistryISBN:9781559539418Author:Angelica StacyPublisher:MAC HIGHER
Chemistry: Matter and Change
Chemistry
ISBN:9780078746376
Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl Wistrom
Publisher:Glencoe/McGraw-Hill School Pub Co
World of Chemistry, 3rd edition
Chemistry
ISBN:9781133109655
Author:Steven S. Zumdahl, Susan L. Zumdahl, Donald J. DeCoste
Publisher:Brooks / Cole / Cengage Learning
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Chemistry: The Molecular Science
Chemistry
ISBN:9781285199047
Author:John W. Moore, Conrad L. Stanitski
Publisher:Cengage Learning
Living By Chemistry: First Edition Textbook
Chemistry
ISBN:9781559539418
Author:Angelica Stacy
Publisher:MAC HIGHER