Introduction To Chemistry 5th Edition
5th Edition
ISBN: 9781260162097
Author: BAUER
Publisher: MCG
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Chapter 15, Problem 83QP
Interpretation Introduction
Interpretation:
The reason so as to why the heat of fission reaction is used directly to create steam to operate a turbine is to be stated.
Concept Introduction:
Some of the heavy radioactive nuclides are very unstable. They undergo decay in two ways, one is alpha decay and another is splitting of the nucleus and releasing a large amount of energy. Again, some of the heavy nuclides do not undergo fission spontaneously, but will undergo if irradiated or bombarded with suitable particle like neutron. Splitting of heavy radioactive nuclides into two or more nucleus with some number of neutrons is called fission reaction. The nuclear waste is the material that nuclear fuel becomes after its use in a fission reactor.
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Please explain your steps and thought process. Thank you!
Using the general properties of equilibrium constants
At a certain temperature, the equilibrium constant K for the following reaction is 1.3 × 10 4:
Cl2(g) + CHCl3(g) HCl(g) + CC₁(g)
Use this information to complete the following table.
Suppose a 16. L reaction vessel is filled with 1.6 mol of HCI and
1.6 mol of CCl4. What can you say about the composition of the
mixture in the vessel at equilibrium?
There will be very little Cl2 and CHCl3.
☐ x10
There will be very little HCI and CCl4.
Neither of the above is true.
What is the equilibrium constant for the following reaction? Be
sure your answer has the correct number of significant digits.
HCl(g)+CC14(g)
12
Cl2(9)+CHCl3(9)
K = 0 ☐
What is the equilibrium constant for the following reaction? Be
sure your answer has the correct number of significant digits.
2 Cl₂(9)+2CHCl3(9)
2 HCl(9)+2CC₁₁(9)
K =
✓
00.
18
Ar
Chapter 15 Solutions
Introduction To Chemistry 5th Edition
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