Interpretation Introduction To determine: K c and K p for the given reaction. Explanation The given reaction is, CH 4 ( g ) + H 2 O ( g ) ⇌ CO ( g ) + 3 H 2 ( g ) . The gas produced has a volume of 5.00 L . The gas contains 8.62 g of CO , 2.60 g of H 2 , 43.0 g of CH 4 and 48.4 g of H 2 O . Temperature at which reaction takes place is 1000 K . Moles of CO at equilibrium are calculated by the formula, n CO = m CO M CO Where, n CO are moles of CO at equilibrium. m CO is the mass of CO in the gas. M CO is the molar mass of CO ( 28.01 g/mol ) . Substitute the values of m CO and M CO in the above formula. n CO = 8.62 g 28.01 g/mol = 0.308 mol Concentration of CO at equilibrium is calculated as, [ CO ] = n CO V Where, [ CO ] is concentration of CO at equilibrium. V is the volume of flask. Substitute the values of V and n CO in the above formula. [ CO ] = 0.308 mol 5.00 L = 0.062 mol/L = 0.062 M Moles of H 2 at equilibrium are calculated by the formula, n H 2 = m H 2 M H 2 Where, n H 2 are moles of H 2 at equilibrium. m H 2 is the mass of H 2 in the gas. M H 2 is the molar mass of H 2 ( 2.02 g/mol ) . Substitute the values of m H 2 and M H 2 in the above formula. n H 2 = 2.60 g 2.02 g/mol = 1.287 mol Concentration of H 2 at equilibrium is calculated as, [ H 2 ] = n H 2 V Where, [ H 2 ] is concentration of H 2 at equilibrium. V is the volume of flask. Substitute the values of V and n H 2 in the above formula. [ H 2 ] = 1.287 mol 5.00 L = 0.257 mol/L = 0.257 M Moles of CH 4 at equilibrium are calculated by the formula, n CH 4 = m CH 4 M CH 4 Where, n CH 4 are moles of CH 4 at equilibrium. m CH 4 is the mass of CH 4 in the gas. M CH 4 is the molar mass of CH 4 ( 16.05 g/mol ) . Substitute the values of m CH 4 and M CH 4 in the above formula. n CH 4 = 43.0 g 16.05 g/mol = 2.679 mol Concentration of CH 4 at equilibrium is calculated as, [ CH 4 ] = n CH 4 V Where, [ CH 4 ] is concentration of CO at equilibrium

7th Edition

ISBN: 9781323912027

Author: Brown

Publisher: PEARSON C

See similar textbooks

Videos

Question

Chapter 15, Problem 73AE

Interpretation Introduction

To determine: Kc and Kp for the given reaction.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 15, Problem 72AE

Chapter 15, Problem 74AE

Students have asked these similar questions

Indicate how to calculate the potential E of the reaction Hg2Cl2(s) + 2e ⇄ 2Hg + 2Cl- as a function of the concentration of Cl- ions. Data: the solubility product of Hg2Cl2.

How can Beer’s Law be used to determine the concentration in a selected food sample. Provide an in-depth discussion and examples of this.

b) H3C- H3C Me CH 3 I HN Me H+

Chapter 15 Solutions

LAB EXPERIMENTS FOR CHEM >C<

Ch. 15.2 - Prob. 15.1.1PE Ch. 15.2 - Prob. 15.1.2PE Ch. 15.2 - Prob. 15.2.1PE Ch. 15.2 - Prob. 15.2.2PE Ch. 15.3 - Prob. 15.3.1PE Ch. 15.3 - Practice Exercise 2 For the reaction H2 (g) + I2...Ch. 15.3 - Prob. 15.4.1PE Ch. 15.3 - Prob. 15.4.2PE Ch. 15.4 - Prob. 15.5.1PE Ch. 15.4 - Prob. 15.5.2PE

Ch. 15.4 - Practice Exercise 1 If 8.0 g of NH4HS(s)...Ch. 15.4 - Prob. 15.6.2PE Ch. 15.5 - Practice Exercise 1 A mixture of gaseous sulfur...Ch. 15.5 - Prob. 15.7.2PE Ch. 15.5 - Practice Exercise 1 In Section 15.1, we discussed...Ch. 15.5 - Practice Exercise 2 The gaseous compound BrCl...Ch. 15.6 - Prob. 15.9.1PE Ch. 15.6 - Practice Exercise 2 At 1000 k, the value of Kp for...Ch. 15.6 - Prob. 15.10.1PE Ch. 15.6 - Prob. 15.10.2PE Ch. 15.6 - Practice Exercise 1 For the equilibrium Br2(g) +...Ch. 15.6 - Prob. 15.11.2PE Ch. 15.7 - Practice Exercise 1 For the reaction 4 NH3(g) + 5...Ch. 15.7 - Prob. 15.12.2PE Ch. 15 - Prob. 1DE Ch. 15 - Based on the following energy profile, predict...Ch. 15 - 15.2 The following diagrams represent a...Ch. 15 - Prob. 3E Ch. 15 - Prob. 4E Ch. 15 - Prob. 5E Ch. 15 - 15.6 Ethene (C2H4) reacts with healogens (X2) by...Ch. 15 - When lead(IV) oxide is heated above 300 O C, it...Ch. 15 - Prob. 8E Ch. 15 - The reactin A2(g) + B(g) + A(g) + AB(g) has an...Ch. 15 - Prob. 10E Ch. 15 - Prob. 11E Ch. 15 - The following graph represents the yield of the...Ch. 15 - Suppose that the gas-phase reactions A B and B A...Ch. 15 - Prob. 14E Ch. 15 - Prob. 15E Ch. 15 - Write the expression for KC for the following...Ch. 15 - When the following reaction come to equilibrium,...Ch. 15 - Prob. 18E Ch. 15 - Prob. 19E Ch. 15 - Prob. 20E Ch. 15 - If Kc = 0.042 for PC13(g) + C12 (g) PC15 (g) at...Ch. 15 - Prob. 22E Ch. 15 - 15.23 The equilibrium constant for the...Ch. 15 - Prob. 24E Ch. 15 - Prob. 25E Ch. 15 - Prob. 26E Ch. 15 - The following equilibria were attained at 823 K:...Ch. 15 - Consider the equilibrium N2(g) + O2(g) + Br2(g) 2...Ch. 15 - Mercury(I) oxide decomposes into elemental mercury...Ch. 15 - Prob. 30E Ch. 15 - Prob. 31E Ch. 15 - Prob. 32E Ch. 15 - Prob. 33E Ch. 15 - Phosphorus trichloride gas and chlorine gas react...Ch. 15 - A mixture of 0.10 mol of NO, 0.050 mol of H2, and...Ch. 15 - Prob. 36E Ch. 15 - A mixture of 0.2000 mol of CO2, 0.1000 mol of H2,...Ch. 15 - 15.38 A flask is charged with 1.500 atm of N2O4(g)...Ch. 15 - Prob. 39E Ch. 15 - Prob. 40E Ch. 15 - a. If QC KC, in which direction will a reaction...Ch. 15 - Prob. 42E Ch. 15 - At 100 OC , the equilibrium constant for the...Ch. 15 - 15.44 As shown in Table 15.2, KP for the...Ch. 15 - At 100 C, K = 0.078 for the reaction SO2Cl2 (g) ...Ch. 15 - Prob. 46E Ch. 15 - Prob. 47E Ch. 15 - Prob. 48E Ch. 15 - At 800 k, the equilibrium constant for I2 (g) ...Ch. 15 - Prob. 50E Ch. 15 - At 2000 OC, the equilibrium constant for the...Ch. 15 - For the equilibrium Br2 (g) + Cl2 (g) 2BrCl(g) At...Ch. 15 - At 373 k, Kp = 0.416 for the equilibrium 2NOBr (g)...Ch. 15 - At 218 oC, KC= 1.2 X 10-4 for the equilibrium NH4...Ch. 15 - Prob. 55E Ch. 15 - At 80 oC, K =1.87 X 10-3 for the reaction PH3 BCl3...Ch. 15 - Prob. 57E Ch. 15 - Prob. 58E Ch. 15 - Prob. 59E Ch. 15 - Prob. 60E Ch. 15 - Consider the following equilibrium for which H<0...Ch. 15 - Prob. 62E Ch. 15 - 15.63 How do the following changes affect the...Ch. 15 - Prob. 64E Ch. 15 - Consider the following equilibrium between oxides...Ch. 15 - Prob. 66E Ch. 15 - Ozone, O3, decomposes to molecular oxygen in the...Ch. 15 - Prob. 68E Ch. 15 - Prob. 69E Ch. 15 - 15.70 True or false: When the temperature of an...Ch. 15 - Prob. 71AE Ch. 15 - Prob. 72AE Ch. 15 - 15.73 A mixture of CH4 and H2O is passed over a...Ch. 15 - Prob. 74AE Ch. 15 - Prob. 75AE Ch. 15 - Prob. 76AE Ch. 15 - Prob. 77AE Ch. 15 - Prob. 78AE Ch. 15 - Prob. 79AE Ch. 15 - For the equilibrium PH3BCI3 (s) PH3 (g) + BCI3...Ch. 15 - Prob. 81AE Ch. 15 - Prob. 82AE Ch. 15 - Prob. 83AE Ch. 15 - At 900 o C, Kc = 0.0108 for the reaction CaCO3(g) ...Ch. 15 - Prob. 85AE Ch. 15 - The equilibrium constant Kc for C(s) +CO2 2CO(g)...Ch. 15 - Prob. 87AE Ch. 15 - Le Chatelier noted that many industrial processes...Ch. 15 - Prob. 89AE Ch. 15 - Prob. 90AE Ch. 15 - [15.91] An equilibrium mixture of H2, I2, and HI...Ch. 15 - Consider the hypothetical reaction A(g) + 2B(g) 2...Ch. 15 - Prob. 93AE Ch. 15 - Prob. 94AE Ch. 15 - Prob. 95IE Ch. 15 - The following equilibria were measured at 823 K:...Ch. 15 - Prob. 97IE Ch. 15 - Prob. 98IE Ch. 15 - At 800 K, the equilibrium constant for the...Ch. 15 - Prob. 100IE Ch. 15 - Prob. 101IE Ch. 15 - Prob. 102IE

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.