Chapter 15, Problem 62QAP

Interpretation Introduction

Interpretation:

The amount of water that must be added to $10.0\text{mL}$ of $6.00\text{M}$

$\text{NaOH}$ to produce a $0.300\text{M}$ solution is to be calculated.

Concept Introduction:

The atomic mass of an element is defined as the sum of number of protons and number of neutrons. Molar mass of an element is determined from atomic mass of an element.

The moles of any element is calculated by the formula,

$\text{Moles}=\frac{\text{Mass}\left(\text{g}\right)}{\text{Molar}\text{mass}}$

Molarity is used to find out the concentration of solution.

The molarity is calculated by the formula,

$\text{Molarity}=\frac{\text{Number}\text{of}\text{moles}\text{of}\text{solute}}{\text{Volume}\text{of}\text{solution}}$.