Explanation Description: It is given that the edge of cube is 10 cm greater than the radius of a sphere. Let a be the edge of a cube and x be the radius of a sphere. Then a = x + 10 . The volume of cube and radius are equal. That is, a 3 = 4 3 π x 3 . ( x + 10 ) 3 = 4 3 π x 3 x 3 + 30 x 2 + 300 x + 1000 = 4 3 π x 3 ( 1 − 4 3 π ) x 3 + 30 x 2 + 300 x + 1000 = 0 Solve the equation ( 1 − 4 3 π ) x 3 + 30 x 2 + 300 x + 1000 = 0 graphically. Press the button “ Y = ” to access equation editor Y = and then write Y 1 = ( 1 − 4 3 π ) X ^ 3 + 30 X ^ 2 + 300 X + 1000

11th Edition

ISBN: 9780134508290

Author: Evans

Publisher: PEARSON CUSTOM PUB.(CONSIGNMENT)

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Chapter 15, Problem 58RE

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The volume of a cube and sphere.

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Chapter 15, Problem 57RE

Chapter 15, Problem 59RE

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Chapter 15 Solutions

EBK BASIC TECHNICAL MATHEMATICS

Ch. 15.1 - Use the factor theorem to determine whether t − 2...Ch. 15.1 - Prob. 2PE Ch. 15.1 - Prob. 3PE Ch. 15.1 - Prob. 4PE Ch. 15.1 - Prob. 1E Ch. 15.1 - Prob. 2E Ch. 15.1 - In Exercises 1–4, make the given changes in the...Ch. 15.1 - Prob. 4E Ch. 15.1 - Prob. 5E Ch. 15.1 - Prob. 6E

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