Creating pointers to base class: The pointer object can be created to a base class and it uses “*” before the object. This object can be assigned to the address of the derived class. Program: The below program explains the creation of pointer object to the base class. /*Include required files*/ #include<iostream> using namespace std; /*Base Class*/ class One { /*Access specifier*/ protected: /*Declare the variable "base_var" as "int"*/ int base_var; /*Access specifier*/ public: /*Constructor*/ One (int num = 10) { /*Assign val to base_var*/ base_var = num; } /*Function getValue()*/ int getValue() { /*Return the value of base_var*/ return base_var; } }; /*Derived class*/ class Two: public One { /*Access specifier*/ private: /*Declare the variable "der_var" as "int"*/ int der_var; /*Access specifier*/ public: /*Constructor*/ Two(int num = 30 ) { /*Assign “val” to “der_var” */ der_var = num; } /*Function getValue()�...
Creating pointers to base class: The pointer object can be created to a base class and it uses “*” before the object. This object can be assigned to the address of the derived class. Program: The below program explains the creation of pointer object to the base class. /*Include required files*/ #include<iostream> using namespace std; /*Base Class*/ class One { /*Access specifier*/ protected: /*Declare the variable "base_var" as "int"*/ int base_var; /*Access specifier*/ public: /*Constructor*/ One (int num = 10) { /*Assign val to base_var*/ base_var = num; } /*Function getValue()*/ int getValue() { /*Return the value of base_var*/ return base_var; } }; /*Derived class*/ class Two: public One { /*Access specifier*/ private: /*Declare the variable "der_var" as "int"*/ int der_var; /*Access specifier*/ public: /*Constructor*/ Two(int num = 30 ) { /*Assign “val” to “der_var” */ der_var = num; } /*Function getValue()�...
Solution Summary: The author explains the creation of pointers to a base class. The pointer object uses "*" before the object, and is assigned to the derived class's address.
We are considering the RSA encryption scheme. The involved numbers are small, so the communication is insecure. Alice's public key (n,public_key) is (247,7).
A code breaker manages to factories 247 = 13 x 19
Determine Alice's secret key.
To solve the problem, you need not use the extended Euclid algorithm, but you may assume that her private key is one of the following numbers 31,35,55,59,77,89.
Consider the following Turing Machine (TM). Does the TM halt if it begins on the empty tape? If it halts, after how many steps? Does the TM halt if it begins on a tape that contains a single letter A followed by blanks? Justify your answer.
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