Explanation Result used: Descartes’ Rule of Signs: “(a) The number of positive zeros of a polynomial equation f ( x ) = 0 cannot exceed than the number of changes in sign in f ( x ) in going from one term to the next in f ( x ) . (b) The number of negative zeros cannot exceed the number of sign changes in f ( − x ) ”. Calculation: It is given that the polynomial equation is x 4 − 3 x 2 + x + 1 = 0 . Here, f ( x ) = x 4 − 3 x 2 + x + 1 and the degree is 4. Substitute – x for x in f ( x ) = x 4 − 3 x 2 + x + 1

Basic Technical Mathematics with Calculus (11th Edition)

11th Edition

ISBN: 9780134437736

Author: Allyn J. Washington, Richard Evans

Publisher: PEARSON

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Chapter 15, Problem 4RE

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Whether the statement “ Without solving, it can be determined that there is no more than one possible negative root of the equation x4−3x2+x+1=0” is true or false.

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Chapter 15, Problem 3RE

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Chapter 15 Solutions

Basic Technical Mathematics with Calculus (11th Edition)

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Whether the statement “ Without solving, it can be determined that there is no more than one possible negative root of the equation x 4 − 3 x 2 + x + 1 = 0 ” is true or false.

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Whether the statement “ Without solving, it can be determined that there is no more than one possible negative root of the equation x4−3x2+x+1=0” is true or false.

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Chapter 15 Solutions