Business Driven Technology
Business Driven Technology
6th Edition
ISBN: 9780073376905
Author: Paige Baltzan Instructor
Publisher: McGraw-Hill Education
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Chapter 15, Problem 3CQ

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Challenges face by Companies for social networking websites:

Some of the challenges faced by companies for social networking websites are:

  • Privacy: Privacy is a very big problem faced by social media platforms as social means open to public. Marketing has hitched a ride on a variety of social media sites. The average user may not disclose information that could be considered inflammatory or offensive, but because some users disclose every detail of their lives it can be used to determine the private life of individuals.
  • Loss of workplace productivity: There has been a problem of abuse of social media white at work and hence productivity of work has been reduced...

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#include int main (void) { int i, *p, count } p = &count; = 10%; for (i = 5; i >= 0; i--) { count++; (*p) ++; } printf("count return 0; = %d, Have a wonderful day.\n", count); 1. [20 pts] What is the output of the program? Please explain why. 2. [15 pts] What is the gdb command to set a breakpoint in line 6 (p = &count;)? 3. [15 pts] Explain in your own words how the [break. need to use such command? ... if expr] command works. When might you
Please run and debug the following program and answer the questions.
(OnlineGDB) #include <stdio.h>int main(void) {int a;char *s;int v0 = 4, v1 = 5, v2 = 6, v3 = 1, v4 = 2;printf("Exercise 1:\n====================\n");switch(v0) {case 0: printf("Hello October\n"); break;case 1: printf("Go Kean!\n"); break;case 2: printf("Academic Building Center \n"); break;case 3: printf("UNION \n"); break;case 4: printf("Go ");case 5: printf("Kean! \n");default: printf("Have a great semester! \n"); break;}for(a=5; a<v1; a++) {printf("Kean");}printf("\n");if (v2 == 6) {s = "Go";}else {s = "Hello";}if(v3 != v4) {printf("%s Kean!\n",s);} else {printf("%s Computer Science!\n",s);}return 0;} Assume the following codes are added between line 36 (}) and line 38 (return 0;) v0>0 ? ++v1, ++v2 : --v3; Please give the values of v0, v1, v2, v3, and v4 after this line and explain the reason. You can test the program to verify your answer if you like.
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