Chapter 15, Problem 39PP

Interpretation Introduction

Interpretation:

The given bonds are needed to be arranged in order of their increasing wavenumber.

Concept introduction

Reciprocal of wavelength is called wavenumber or Number of waves in one centimeter is called wavenumber

Unit of wave number is reciprocal of Centimeter.

 According to Hooke’s law the factors affecting wave numbers are

1. Bond strength

2. Mass of bond shared pair of atoms

$\begin{array}{l}\overline{\text{ν}}\text{=}\left(\frac{\text{1}}{\text{2πc}}\right){\left(\frac{\text{f}}{{\text{m}}_{\text{red}}}\right)}^{\text{1/2}}\\ \text{f}\text{=}\text{force}\text{constant}\left(\text{bond}\text{strength}\right)\\ {\text{m}}_{\text{red}}\text{=}\text{reduced}\text{mass}\\ \text{=}\frac{{\text{m}}_{\text{1}}{\text{m}}_{\text{2}}}{{\text{m}}_{\text{1}}{\text{+m}}_{\text{2}}}\end{array}$

To explain: the wave number of given $\text{X-H}$ $\text{(X}\text{=}\text{C, N, O)}$ type bonds, triple bond, double bonds and single bond.