Chapter 15, Problem 28CAP

1.

To determine

Find the value of point-biserial correlation coefficient.

Answer to Problem 28CAP

The value of point-biserial correlation coefficient is 0.893.

Explanation of Solution

Calculation:

The given information is that, the researcher is interested to determine the relation between the factors recycle (X) and attitude of Eco friendly (Y).

Point-biserial correlation coefficient:

When the one factor is continuous that is measured on either interval scale or ratio scale and other is dichotomous that is measured on nominal scale, then the strength and direction of the linear relationship between the two factors can be measured by Point-biserial correlation coefficient. It is denoted by $r_{\text{pb}}$. The formula is,

$r_{\text{pb}}=\left(\frac{M_{Y_1}-M_{Y_2}}{s_Y}\right)\left(\sqrt{pq}\right)$.

In the formula, p and q are the proportion of scores for the dichotomous factor at each level, $s_Y=\sqrt{\frac{S{S}_Y}{n}}$ denotes the standard deviation of Y scores, n denotes the number of pairs measured, $S{S}_Y$ denotes the sums of squares for scores Y, $M_{Y_1}$ denotes the mean of Y scores at first level,$M_{Y_2}$ denotes the mean of Y scores at second level.

The Point-biserial correlation for recycle and attitude of Eco friendly is to be calculated. The factor ‘recycle’ has to be coded with 1 and 2. Code the value 1 for ‘No’ and 2 for ‘Yes’ for dichotomous factor ‘recycle’.

The coded data is,

Recycle	Attitude toward Eco friendly
1	1
1	3
1	1
1	1
1	3
2	7
2	6
2	5
2	6
2	4
2	6
2	5

Software procedure:

Step by step procedure to obtain test statistic valuefor recycle and attitude of Eco friendly using SPSS software is given as,

• Choose Variable view.
• Under the name, enter the name as X, Y.
• Choose Data view, enter the data.
• Choose Analyze>Correlate>Bivariate.
• In variables, enter the X, and Y.
• Click OK.

Output using SPSS software is given below:

The correlation coefficient value is 0.893.

2.

To determine

Determine the decision for the null hypothesis using two-tailed test at a 0.05 level of significance

Answer to Problem 28CAP

The decision is to reject the null hypothesis.

The point-biserial correlation coefficient between recycle and attitude of Eco friendly is significant.

Explanation of Solution

Calculation:

The given information is that, the correlation coefficient value is –0.893 and degrees of freedom is 10.

Test statistic:

The coefficient of determination for the point-serial correlation and the effect size of the two-independent-sample t test are similar and hence for significance test of point-biserial correlation, t test is used.

The formula for converting the r to a t statistic is,

$t^2=\frac{r^2}{\left(\frac{\left(1-r^2\right)}{df}\right)}$

In the formula, r denotes the correlation coefficient and df is the degrees of freedom for correlation coefficient.

Degrees of freedom:

The formula is. $df=n-2$

In formula, n denotes the sample size.

Decision rules:

• If the positive test statistic value is greater than the critical value, then reject the null hypothesis and test is significant, or else retains the null hypothesis.
• If the negative test statistic value is less than negative critical value, then reject the null hypothesis and test is significant, or else retains the null hypothesis.

The correlation between recycle and attitude of Eco friendly is to be tested. Let $\rho$ denote the correlation coefficient between recycle and attitude of Eco friendly.

Null hypothesis:

$H_0:\rho =0$

That is, the point-biserialcorrelation coefficient between recycle and attitude of Eco friendly is not significant.

Alternative hypothesis:

$H_1:\rho \ne 0$

That is, the point-biserial correlation coefficient between recycle and attitude of Eco friendly is significant.

Degrees of freedom:

A sample of 12 participants is taken. The degrees of freedom are,

$\begin{array}{c}df=n-2\\ =12-2\\ =10\end{array}$

Test statistic:

Substitute, $r=0.893$ and $df=10$ in test statistic formula

$\begin{array}{c}{t}^2=\frac{{\left(0.893\right)}^2}{\left(\frac{1-{\left(0.893\right)}^2}{10}\right)}\\ =\frac{0.7974}{\left(\frac{1-0.7974}{10}\right)}\\ =\frac{0.7974}{0.0202}\\ =39.4752\end{array}$

The value of t is,

$\begin{array}{c}t=\sqrt{39.4752}\\ =6.283\end{array}$

Critical value:

The given significance level is $\alpha =0.05$.

The test is two tailed, the degrees of freedom are 10, and the alpha level is 0.05.

From the Appendix C: Table C.2 the t Distribution:

• Locate the value 10 in the degrees of freedom (df) column.
• Locate the 0.05 in the proportion in two tails combined row.
• The intersecting value that corresponds to the 10 with level of significance 0.05 is 2.228.

Thus, the critical value for $df=10$ with two-tailed test is $\pm 2.228$.

Conclusion:

The value of test statistic is 6.283.

The critical value is 2.228.

The test statistic value is greater than the critical value.

The test statistic value falls under critical region.

Hence the null hypothesis is rejected and test is significant.

The point-biserial correlation coefficient between recycle and attitude of Eco friendly is significant.