Explanation 1) Concept: Solving an expression is to find the value of unknown in the expression, which on substitution must satisfy the expression. 2) Calculation: Given, 5000 = l w Here, w = 150 − l 5000 = l ( 150 − l ) By distributive property of multiplication over subtraction, 5000 = l ⋅ 150 − l ⋅ l 5000 = 150 l − l 2 150 l − l 2 = 5000 − l 2 + 150 l = 5000 Add − 5000 on both sides, − l 2 + 150 l − 5000 = 5000 − 5000 − l 2 + 150 l − 5000 = 0 Multiply each term by − 1 on both sides, − l 2 ⋅ ( − 1 ) + 150 l ⋅ ( − 1 ) ⋅ − 5000 ⋅ ( − 1 ) = 0 l 2 − 150 l + 5000 = 0 Factorizing l 2 − 150 l + 5000 by middle term splitting method. Product of the coefficient of x 2 and constant = 5000. Coefficient of the middle term = − 150. Now 5000 is factorized as − 100 and − 50 so as to get the sum − 150. Hence, l 2 − 150 l + 5000 = 0 becomes l 2 − 100 l − 50 l + 5000 = 0

Essentials of College Algebra (11th Edition)

11th Edition

ISBN: 9780321912251

Author: Margaret L. Lial, John Hornsby, David I. Schneider, Callie Daniels

Publisher: PEARSON

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Chapter 1.5, Problem 20E

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The dimensions of the garden such that an ecology center wants to set up an experimental garden using 300 m of fencing to enclose a rectangular area of 5000 m².

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Chapter 1.5, Problem 19E

Chapter 1.5, Problem 21E

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Chapter 1 Solutions

Essentials of College Algebra (11th Edition)

Ch. 1.1 - Prob. 1E Ch. 1.1 - Prob. 2E Ch. 1.1 - Prob. 3E Ch. 1.1 - Prob. 4E Ch. 1.1 - Prob. 5E Ch. 1.1 - Prob. 6E Ch. 1.1 - Prob. 7E Ch. 1.1 - Prob. 8E Ch. 1.1 - Prob. 9E Ch. 1.1 - Prob. 10E

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The dimensions of the garden such that an ecology center wants to set up an experimental garden using 300 m of fencing to enclose a rectangular area of 5000 m 2 .

To find: The dimensions of the garden such that an ecology center wants to set up an experimental garden using 300 m of fencing to enclose a rectangular area of 5000 m2.

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Chapter 1 Solutions

To find:

The dimensions of the garden such that an ecology center wants to set up an experimental garden using 300 m of fencing to enclose a rectangular area of 5000 m².