Elementary Statistics 2nd Edition
2nd Edition
ISBN: 9781259724275
Author: William Navidi, Barry Monk
Publisher: McGraw-Hill Education
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Question
Chapter 15, Problem 1CQ
a.
To determine
To find:The value of test statistic.
a.
Expert Solution
Answer to Problem 1CQ
The value of test statistic is
Explanation of Solution
Given information:
The data is
Concept used:
The test statistic is,
If the
If the sample size is greater than
Here, the number of times the less frequent sign occur is
The conditions for test statistics are shown below in table.
| Type of test | Test statistic |
| Right-tailed test | Number of minus signs |
| Left-tailed test | Number of plus signs |
| Two-tailed test | Number of plus or minus signs, whichever is smaller |
Calculations:
The value of test statistic is shown below.
| Sample | Difference | Signs |
| 50 | 20 | - |
| 38 | 8 | + |
| 23 | -7 | - |
| 29 | -1 | - |
| 57 | 27 | + |
| 26 | -4 | - |
| 53 | 23 | + |
| 42 | 12 | + |
| 60 | 30 | + |
| 23 | -7 | - |
From the above table, the number of minus sign is
Since, the sample size is less than
The test statistic is given by the number of plus or minus sign which are smaller in number.
Therefore, the value of test statistic for the given sample is
b.
To determine
To find:Whether the hypothesis
b.
Expert Solution
Answer to Problem 1CQ
The hypothesis
Explanation of Solution
Given information:
The level of significance is
Calculations:
The critical value for two-tailed test at sample size of
Since, the test statistics is
Therefore, the hypothesis
c.
To determine
To find:Whether the hypothesis
c.
Expert Solution
Answer to Problem 1CQ
The hypothesis
Explanation of Solution
Given information:
The level of significance is
Calculations:
The critical value for two-tailed test at sample size of
Since, the test statistics is
Therefore, the hypothesis
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Students have asked these similar questions
(a) Test the hypothesis.
Consider the hypothesis test Ho
=
:
against H₁o < 02. Suppose that the sample sizes aren₁ =
7 and n₂
= 13 and that
$²
= 22.4 and $22
= 28.2. Use α = 0.05.
Ho
is not
✓ rejected.
9-9
IV
(b) Find a 95% confidence interval on of 102. Round your answer to two decimal places (e.g. 98.76).
Let us suppose we have some article reported on a study of potential sources of injury to equine veterinarians conducted at a
university veterinary hospital. Forces on the hand were measured for several common activities that veterinarians engage in when
examining or treating horses. We will consider the forces on the hands for two tasks, lifting and using ultrasound. Assume that both
sample sizes are 6, the sample mean force for lifting was 6.2 pounds with standard deviation 1.5 pounds, and the sample mean force
for using ultrasound was 6.4 pounds with standard deviation 0.3 pounds. Assume that the standard deviations are known.
Suppose that you wanted to detect a true difference in mean force of 0.25 pounds on the hands for these two activities. Under the null
hypothesis, 40 = 0. What level of type II error would you recommend here?
Round your answer to four decimal places (e.g. 98.7654). Use a
= 0.05.
β
= i
What sample size would be required?
Assume the sample sizes are to be equal.…
=
Consider the hypothesis test Ho: μ₁ = μ₂ against H₁ μ₁ μ2. Suppose that sample sizes are n₁ =
15 and n₂ =
15, that x1 = 4.7
and X2 = 7.8 and that s² = 4 and s² = 6.26. Assume that o and that the data are drawn from normal distributions. Use
απ 0.05.
(a) Test the hypothesis and find the P-value.
(b) What is the power of the test in part (a) for a true difference in means of 3?
(c) Assuming equal sample sizes, what sample size should be used to obtain ẞ = 0.05 if the true difference in means is - 2? Assume
that α = 0.05.
(a) The null hypothesis is
98.7654).
rejected. The P-value is 0.0008
(b) The power is 0.94
. Round your answer to four decimal places (e.g.
Round your answer to two decimal places (e.g. 98.76).
(c) n₁ = n2 =
1
. Round your answer to the nearest integer.
Chapter 15 Solutions
Elementary Statistics 2nd Edition
Ch. 15.1 - In Exercises 3 and 4, fill in each blank with the...Ch. 15.1 - Prob. 4ECh. 15.1 - Prob. 5ECh. 15.1 - In Exercises 5 and 6, determine whether the...Ch. 15.1 - Prob. 7ECh. 15.1 - Prob. 8ECh. 15.1 - Prob. 9ECh. 15.1 - Prob. 10ECh. 15.1 - Weight loss: A weight loss company claims that the...Ch. 15.1 - At the movies: A sample of 12 movies released in a...
Ch. 15.1 - Prob. 13ECh. 15.1 - Prob. 14ECh. 15.1 - Prob. 15ECh. 15.1 - Prob. 16ECh. 15.1 - Scam alert: The rates of fraud complaints (per...Ch. 15.1 - Prob. 18ECh. 15.1 - Prob. 19ECh. 15.2 - Prob. 3ECh. 15.2 - Prob. 4ECh. 15.2 - Prob. 5ECh. 15.2 - Prob. 6ECh. 15.2 - Prob. 7ECh. 15.2 - Prob. 8ECh. 15.2 - Prob. 9ECh. 15.2 - In Exercises 7-10, compute s,s, and the value of...Ch. 15.2 - Prob. 11ECh. 15.2 - Prob. 12ECh. 15.2 - Prob. 13ECh. 15.2 - Recovery times: A new postsurgical treatment was...Ch. 15.2 - Prob. 15ECh. 15.2 - Prob. 16ECh. 15.2 - Prob. 17ECh. 15.3 - Prob. 3ECh. 15.3 - Prob. 4ECh. 15.3 - Prob. 5ECh. 15.3 - Prob. 6ECh. 15.3 - Prob. 7ECh. 15.3 - Prob. 8ECh. 15.3 - Prob. 9ECh. 15.3 - Prob. 10ECh. 15.3 - Prob. 11ECh. 15.3 - Prob. 12ECh. 15.3 - Prob. 13ECh. 15.3 - Prob. 14ECh. 15.3 - Prob. 15ECh. 15.3 - Prob. 16ECh. 15.3 - Exercise 17 demonstrates that the results of the...Ch. 15 - Prob. 1CQCh. 15 - Prob. 2CQCh. 15 - Prob. 3CQCh. 15 - Prob. 4CQCh. 15 - Prob. 5CQCh. 15 - Prob. 6CQCh. 15 - Prob. 7CQCh. 15 - Prob. 8CQCh. 15 - In Exercises 8-10, use the signed-rank test to...Ch. 15 - Prob. 10CQCh. 15 - Prob. 1RECh. 15 - Prob. 2RECh. 15 - Prob. 3RECh. 15 - Prob. 4RECh. 15 - Prob. 5RECh. 15 - Prob. 6RECh. 15 - Prob. 7RECh. 15 - Prob. 8RECh. 15 - Prob. 9RECh. 15 - Prob. 10RECh. 15 - Prob. 1WAICh. 15 - Prob. 2WAICh. 15 - Prob. 3WAICh. 15 - Prob. 1CSCh. 15 - Prob. 2CSCh. 15 - Microorganisms play a crucial role in wastewater...Ch. 15 - Prob. 4CS
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