MindTap Engineering for Garber/Hoel's Traffic and Highway Engineering, 5th Edition, [Instant Access], 1 term (6 months)
5th Edition
ISBN: 9781305577398
Author: Nicholas J. Garber; Lester A. Hoel
Publisher: Cengage Learning US
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Chapter 15, Problem 15P
To determine
The point of tangent and the deflection angles from PC to full stationsfor lying out of curve in the circular curve connecting two tangents.
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an arterial road is to be connected to a frontage road by a reverse curve with parallel tangents. the distance between the centerline of the two roads is 60 ft. if the pc of the curve is located at station (38 25.31) and the deflection angle is 25°, determine the station of pt.
A horizontal curve is designed with a 2000-ft radius. The curve has a tangent length of 400 ft
and the PI is at station 103+00. Determine the stationing of the PC, PT, deflection angle (A/2),
and chord length for each station between the PC and PT.
The design speed for a two-lane highway (lane width=12 ft.) is 60 mph. The localjurisdiction governs 8% superelevation. The central angel of the curve is 40 degrees. The PI station is at 452+50.What is the curve radius to the travel path (R)? What is the curve radius (R)? What is the curve length (L)? What isthe station of PC? What is the station of PT? What is the SSD? How many feet must be cleared from the lane'sshoulder edge to provide adequate stopping sight distance?
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MindTap Engineering for Garber/Hoel's Traffic and Highway Engineering, 5th Edition, [Instant Access], 1 term (6 months)
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- 3.48 A horizontal curve is being designed for a new two-lane highway (12-ft lanes). The PI is at station 250 + 50, the design speed is 65 mi/h, and a maximum superelevation of 0.07 ft/ft is to be used. If the central angle of the curve is 38 degrees, design a curve for the highway by computing the radius and stationing of the PC and PT. 3.49 You are nalarrow_forward6. The intersection angle of a 4.775º curve is 48 degrees. The Point of Curve is at station (943+33.05). Determine the radius and length of the curve, and the deflection angles and the chord lengths from the Point of Curve to full stations for laying out the curve.arrow_forwardThe intersection angle of a 6.716° curve is 80°41mintes 41.9 seconds and the radius is 260m, and the PC is located at station 4+90. 679 . Determine the length of the curve, the station of the PT, the deflection angles and the chord lengths for setting out the curve at whole stations from the PC.arrow_forward
- 2. A simple curve has a central angle of 36° and a degree of curve of 6°: a. Find the nearest distance from the midpoint of the curve to the point of intersection of the tangents. b. Compute the distance from the midpoint of the curve to the midpoint of the long chord joining the P.C. and P.T. c. If the stationing of P.C. is at 10 + 020, compute the stationing of a point on the curve which intersects with the line making a deflection angle of 10° with the tangent through P.C.arrow_forwardA horizontal curve is being designed for a new two-lane highway (3.6-m lanes). The PI is at station 7 + 640, the design speed is 105 km/h, and a maximum superelevation of 0.08 m/m is to be used. If the central angle of the curve is 35 degrees, design a curve for the highway by computing the radius and stationing of the PC and PT.arrow_forwardA reverse curve connects two converging tangents intersecting at an angle of 32". The direction of the second tangent is due east. The distance of this intersection from the PI of the second curve is 130 m. The deflection angle of the common tangent from the back tangent is 19° (R). The degree of curve of the second curve is 8° and the stationing of the P.C. is 10+ 128.40 m. Determine the following: *Radius of the first and second curve *Length and bearing of the common tangent *Stationing of the P.R.C. and the P.T. *If a 15-meter width of road right way from the P.C. to the P.T. will be negotiated, compute the considered road areaarrow_forward
- Two horizontal tangents meet at station 132+11.00 with a deflection angle of 55 degrees and 18 minutes. The horizontal curve between the two tangents has a radius of 2000 ft. Sketch the curve and Calculate: A) Degree of Curve B) External Distance C) Middle Ordinate D) Tangent distance E) length of curve F) begin and end stationsarrow_forwardIt is required to layout a simple curve by deflection angles. The curve is to connect two tangents with an intersection angle of 32° and a radius of 240 m. Compute the deflection angles to each 20 m full stations on the curve. If the transit is set up at the P.C. which is at station 5+767.2. What is the stationing of the P.T.?arrow_forwardProblem 1. A reversed curve connects two converging tangents intersecting at an angle of 30 degrees. The distance of this intersection from the PI of the curve is 120 meters. The deflection angle of the common tangent from the back tangent is 20 degrees (first curve) and the azimuth of the common tangent is 300 degrees. The degree of curve of the second simple curve is 6 degrees and the stationing of the point of intersection of the first curve is 4+450. Determine the stationing of the PC, PRC and the PT.arrow_forward
- Surveyingarrow_forwardA circular curve connects two tangents that intersect at an angle of 48°. The point of intersection of the tangents is located at station (948 67.32). If the design speed of the highway is 60 mi/h, determine both the point of the tangent and the deflection angles to whole stations for laying out the curve. (Select appropriate values for e and f.)arrow_forwardThe length of the common tangent of a compound curve is equal to 68.62m. The common tangent makes an angle of 12˚ and 18˚ respectively to the tangents of the compound curve. If the length of the tangent of the first curve (on the side of PC) is equal to 41.02m.(a) Compute the radius of the second curve.(b) Compute the radius of the first curve.(c) Compute the stationing of the PT if PC is at 20+042.20arrow_forward
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