Concept explainers
(a)
Interpretation:
From the given compounds, compounds with higher value of solubility has to be identified and the reason for the higher value of solubility has to be explained.
The given compounds are chloroethane and methylethylamine.
Concept Introduction:
The physical properties are determined by the intermolecular forces, polarity of the compound and hydrogen bonding. If a compound is polar and have hydrogen bonding, the solubility will be more for that compound than in non-polar compounds.
Intermolecular forces:
The forces which acts in between the atoms to hold a molecule are said to be intermolecular forces. They are weak forces. Intermolecular forces are categorized as hydrogen bonding, ionic bonding, ion-induced dipole forces, ion-dipole forces and Vanderwaal forces.
Hydrogen bonding:
The attraction between a lone pair of hydrogen atom with that of an electronegative atom forms hydrogen bonding. Two water molecules are held together by hydrogen bond.
(b)
Interpretation:
From the given compounds, compounds with higher value of melting point has to be identified and the reason for the higher value of melting point has to be explained.
The given compounds are diethyl ether and 1-butanol.
Concept Introduction:
The physical properties are determined by the intermolecular forces, polarity of the compound and hydrogen bonding. If a compound is polar and have hydrogen bonding, the melting point will be more for that compound than in non-polar compounds.
Intermolecular forces:
The forces which acts in between the atoms to hold a molecule are said to be intermolecular forces. They are weak forces. Intermolecular forces are categorized as hydrogen bonding, ionic bonding, ion-induced dipole forces, ion-dipole forces and Vanderwaal forces.
Hydrogen bonding:
The attraction between a lone pair of hydrogen atom with that of an electronegative atom forms hydrogen bonding. Two water molecules are held together by hydrogen bond.
(c)
Interpretation:
From the given compounds, compounds with higher value of boiling point has to be identified and the reason for the higher value of boiling point has to be explained.
The given compounds are trimethylamine and propylamine.
Concept Introduction:
The physical properties are determined by the intermolecular forces, polarity of the compound and hydrogen bonding. If a compound is polar and have hydrogen bonding, the boiling point will be more for that compound than in non-polar compounds.
Intermolecular forces:
The forces which acts in between the atoms to hold a molecule are said to be intermolecular forces. They are weak forces. Intermolecular forces are categorized as hydrogen bonding, ionic bonding, ion-induced dipole forces, ion-dipole forces and Vanderwaal forces.
Hydrogen bonding:
The attraction between a lone pair of hydrogen atom with that of an electronegative atom forms hydrogen bonding. Two water molecules are held together by hydrogen bond.
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Chapter 15 Solutions
MOLECULAR NATURE OF MATTER ALEKS ACCESS
- The following 'H NMR spectrum was taken with a 750 MHz spectrometer: 1.0 0.5 0.0 10.0 9.0 8.0 7.0 6.0 5.0 4.0 3.0 ' 2.0 1.0 0.0 (ppm) What is the difference Av in the frequency of RF ac Δν ac radiation absorbed by the a and c protons? (Note: it's not equal to the difference in chemical shifts.) Round your answer to 2 significant digits, and be sure it has an appropriate unit symbol. = O O a will shift left, c will shift right. O a will shift right, c will shift left. a and c will both shift left, with more space between them. Suppose a new spectrum is taken with a 500 MHz spectrometer. What will be true about this new spectrum? O a and c will both shift left, with less space between them. O a and c will both shift right, with more space between them. O a and c will both shift right, with less space between them. Which protons have the largest energy gap between spin up and spin down states? O None of the above. ○ a Ob Explanation Check C Ar B 2025 McGraw Hill LLC. All Rights Reserved.…arrow_forwardWhat mass of Na2CO3 must you add to 125g of water to prepare 0.200 m Na2CO3? Calculate mole fraction of Na2CO3, mass percent, and molarity of the resulting solution. MM (g/mol): Na2CO3 105.99; water 18.02. Final solution density is 1.04 g/mL.arrow_forward(ME EX2) Prblms Can you please explain problems to me in detail, step by step? Thank you so much! If needed color code them for me.arrow_forward
- Experiment #8 Electrical conductivity & Electrolytes. Conductivity of solutions FLINN Scientific Scale RED LED Green LED LED Conductivity 0 OFF OFF 1 Dim OFF 2 medium OFF 3 Bright Dim Low or Nowe Low Medium High 4 Very Bright Medium nd very high AA Δ Δ Δ Δ Δ Δ Δ Δ Δ Δ Δ SE=Strong Electrolyte, FE = Fair Electrolyte CWE = Weak Electrolyte, NE= Noni Electrolyte, #Solutions 1 0.1 M NaCl 2/1x 102 M NaCl, 3/1X103 M Nall Can Prediction M Observed Conductivity Very bright red Bright red Dim red you help me understand how I'm supposed to find the predictions of the following solutions? I know this is an Ionic compound and that the more ions in a solution means it is able to carry a charge, right? AAAA Darrow_forward(SE EX 2) Prblsm 4-7: Can you please explain problems 4-7 and color code if needed for me. (step by step) detail explanationsarrow_forward(SE EX 2) Problems 8-11, can you please explain them to me in detail and color-code anything if necessary?arrow_forward
- (ME EX2) Problems 15-16 Could you please explain problems 15 through 16 to me in detail, step by step? Thank you so much! If necessary, please color-code them for me.arrow_forward1.)show any electrophilic aromatic substitution, identify the electriphile, nucleophile and transition statearrow_forward(SE EX 2) Problems 15-16, can you please explain them to me in detail and color-code anything if necessary?arrow_forward
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