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(a)
Interpretation:
The given compound can exhibit optical activity. The chiral centres have to be identified in the compound.
Concept Introduction:
The isomers which are mirror images of each other and are non-superimposable are said to be optical isomers and the isomerism is said to be optical isomerism. The optical isomers are also called as enantiomers. The optical isomers which rotates the plane-polarized light are optically active.
The optical isomers are asymmetric and plane of symmetry will be absent. An organic molecule is said to be chiral when it is bonded to four different groups and is asymmetric. The carbon atom bonded to four different groups is said to be chiral carbon or asymmetric carbon. An organic compound is said to be optically active when it contains at least one chiral center.
(b)
Interpretation:
The given compound can exhibit optical activity. The chiral center has to be identified in the compound.
Concept Introduction:
The isomers which are mirror images of each other and are non-superimposable are said to be optical isomers and the isomerism is said to be optical isomerism. The optical isomers are also called as enantiomers. The optical isomers which rotates the plane-polarized light are optically active.
The optical isomers are asymmetric and plane of symmetry will be absent. An organic molecule is said to be chiral when it is bonded to four different groups and is asymmetric. The carbon atom bonded to four different groups is said to be chiral carbon or asymmetric carbon. An organic compound is said to be optically active when it contains at least one chiral center.
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Chapter 15 Solutions
ALEKS 360 for Silberberg Chemistry: The Molecular Nature of Matter and Change
- Nonearrow_forwardman Campus Depa (a) Draw the three products (constitutional isomers) obtained when 2-methyl-3-hexene reacts with water and a trace of H2SO4. Hint: one product forms as the result of a 1,2-hydride shift. (1.5 pts) This is the acid-catalyzed alkene hydration reaction.arrow_forwardNonearrow_forward
- H HgSO4, H2O H2SO4arrow_forward12. Choose the best diene and dienophile pair that would react the fastest. CN CN CO₂Et -CO₂Et .CO₂Et H3CO CO₂Et A B C D E Farrow_forward(6 pts - 2 pts each part) Although we focused our discussion on hydrogen light emission, all elements have distinctive emission spectra. Sodium (Na) is famous for its spectrum being dominated by two yellow emission lines at 589.0 and 589.6 nm, respectively. These lines result from electrons relaxing to the 3s subshell. a. What is the photon energy (in J) for one of these emission lines? Show your work. b. To what electronic transition in hydrogen is this photon energy closest to? Justify your answer-you shouldn't need to do numerical calculations. c. Consider the 3s subshell energy for Na - use 0 eV as the reference point for n=∞. What is the energy of the subshell that the electron relaxes from? Choose the same emission line that you did for part (a) and show your work.arrow_forward
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