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Science Chemistry Chemistry: An Atoms-Focused Approach

How would you prepare 2.50 L of N a O H solution in which [ O H - ] = 0.70 M , starting with solid N a O H . Solution: 70 . g N a O H needs to dissolve in 2.50 L of water, to prepare the 2.50 L of N a O H solution which contains 0.70 M o f O H - . Explanation: Concept: We are asked to describe the preparation of 2.50 L of N a O H with O H - = 0.70 M . For this, we need to know the exact amount of solid N a O H that needs to be weighed. First, we need to work out how many moles of N a O H are needed. N a O H is a strong base that dissociates completely, so the concentration of N a O H must be equal to the concentration of [ O H - ] = 0.70 M . Using the concentration and given volume, we can determine the moles of N a O H needed and then the amount of N a O H in grams can be calculated using the molar mass of N a O H . Formula: M = n V Given: O H - = N a O H = 0.70 M Volume of solution = 2.50 L Molar mass of N a O H = 39.996 g / m o l Calculation: As the N a O H is strong base, [ N a O H ] = [ O H - ] = 0.70 M Plug in the value in the formula to determine the moles of N a O H needed, 0.70 M = n 2.50 L n = 1.75 m o l Converting the moles of N a O H into mass in grams, 1.75 m o l N a O H × 39.996 g 1 m o l = 69.993 g ~ 70 . g N a O H (In correct significant figures) Therefore, to prepare 2.50 L of N a O H solution in which [ O H - ] = 0.70 M we need to dissolve 70 . g N a O H in 2.50 L of water. Conclusion: We first determine the moles of N a O H needed from the volume and concentration and then calculate the amount of N a O H in grams.

How would you prepare 2.50 L of N a O H solution in which [ O H - ] = 0.70 M , starting with solid N a O H . Solution: 70 . g N a O H needs to dissolve in 2.50 L of water, to prepare the 2.50 L of N a O H solution which contains 0.70 M o f O H - . Explanation: Concept: We are asked to describe the preparation of 2.50 L of N a O H with O H - = 0.70 M . For this, we need to know the exact amount of solid N a O H that needs to be weighed. First, we need to work out how many moles of N a O H are needed. N a O H is a strong base that dissociates completely, so the concentration of N a O H must be equal to the concentration of [ O H - ] = 0.70 M . Using the concentration and given volume, we can determine the moles of N a O H needed and then the amount of N a O H in grams can be calculated using the molar mass of N a O H . Formula: M = n V Given: O H - = N a O H = 0.70 M Volume of solution = 2.50 L Molar mass of N a O H = 39.996 g / m o l Calculation: As the N a O H is strong base, [ N a O H ] = [ O H - ] = 0.70 M Plug in the value in the formula to determine the moles of N a O H needed, 0.70 M = n 2.50 L n = 1.75 m o l Converting the moles of N a O H into mass in grams, 1.75 m o l N a O H × 39.996 g 1 m o l = 69.993 g ~ 70 . g N a O H (In correct significant figures) Therefore, to prepare 2.50 L of N a O H solution in which [ O H - ] = 0.70 M we need to dissolve 70 . g N a O H in 2.50 L of water. Conclusion: We first determine the moles of N a O H needed from the volume and concentration and then calculate the amount of N a O H in grams.

Solution Summary: The author explains how to prepare 2.50L of NaOH with left[OH-right]=0.70M.

Chemistry: An Atoms-Focused Approach

Chemistry: An Atoms-Focused Approach

14th Edition

ISBN: 9780393600681

Author: Gilbert

Publisher: W. W. Norton & Company

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Chemistry: An Atoms-Focused Approach

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