Chapter 15, Problem 15.19P

(a)

Interpretation Introduction

Interpretation:

Value of constant when $E$ is $-0.230\text{ V}$ has to be calculated.

Concept Introduction:

Potential difference for ion selective electrode is evaluated by expression as follows:

  $E=\frac{0.05916}{n}\left[\log \left({\left[{\text{C}}^{+}\right]}_{\text{outer 2}}\right)-\log \left({\left[{\text{C}}^{+}\right]}_{\text{outer 1}}\right)\right]$

Here,

${\left[{\text{C}}^{+}\right]}_{\text{outer 2}}$ denotes concentration of analyte solution 2.

${\left[{\text{C}}^{+}\right]}_{\text{inner}}$ denotes concentration of analyte solution 1.

$n$ denotes charge on analyte.

$E$ denotes potential difference.

(b)

Interpretation Introduction

Interpretation:

Concentration of ${\text{CN}}^{-}$ has to be calculated.

Concept Introduction:

Refer to part (a).