Chapter 15, Problem 15.116P

(a)

Interpretation Introduction

Interpretation:

The hydrolysis of a 100.00-g sample of peptide forms the given individual amounts of amino acids (molar mass in g/mol are given in parentheses).

  $\begin{array}{l}\text{3}\text{.00 g of glycine (75}\text{.07) 0}\text{.90 g of alanine (89}\text{.10)}\\ \\ \text{3}\text{.70 g of valine (117}\text{.15) 6}\text{.90 g of proline (115}\text{.13)}\\ \\ \text{7}\text{.30 g of serine (105}\text{.10) 86}\text{.00 g of arginine (174}\text{.21)}\end{array}$

Why the total mass of amino acids exceeds the mass of peptide has to be given.

(b)

Interpretation Introduction

Interpretation:

The hydrolysis of a 100.00-g sample of peptide forms the given individual amounts of amino acids (molar mass in g/mol are given in parentheses).

  $\begin{array}{l}\text{3}\text{.00 g of glycine (75}\text{.07) 0}\text{.90 g of alanine (89}\text{.10)}\\ \\ \text{3}\text{.70 g of valine (117}\text{.15) 6}\text{.90 g of proline (115}\text{.13)}\\ \\ \text{7}\text{.30 g of serine (105}\text{.10) 86}\text{.00 g of arginine (174}\text{.21)}\end{array}$

The relative numbers of amino acids in the peptide has to be given.

Concept Introduction:

The relative numbers can be calculated by converting the mass in to moles and by dividing the moles with smallest number.

(c)

Interpretation Introduction

Interpretation:

The hydrolysis of a 100.00-g sample of peptide forms the given individual amounts of amino acids (molar mass in g/mol are given in parentheses).

  $\begin{array}{l}\text{3}\text{.00 g of glycine (75}\text{.07) 0}\text{.90 g of alanine (89}\text{.10)}\\ \\ \text{3}\text{.70 g of valine (117}\text{.15) 6}\text{.90 g of proline (115}\text{.13)}\\ \\ \text{7}\text{.30 g of serine (105}\text{.10) 86}\text{.00 g of arginine (174}\text{.21)}\end{array}$

The minimum molar mass of the peptide has to be given.

Concept Introduction:

The minimum molar mass of peptide can be calculated by adding the products of moles of each amino acid with their molar mass to get the amount of amino acids and the water molecules mass is eliminated from the mass of amino acids to get the molar mass of peptide.