(a)
Interpretation:
The missing products have to be predicted and the balanced equation has to be written for the decomposition and chlorination of diborane to boron trichloride.
Concept Introduction:
Decomposition reaction:
It is an elimination reaction. When a saturated reactant becomes an unsaturated (presence of double bond) product, the reaction is said to be elimination reaction. In elimination reaction, two products are formed from one reactant.
Chlorination:
The addition halogens to the organic compounds is said to be halogenation and the addition of chlorine atoms to the organic compound is said to be chlorination.
(b)
Interpretation:
The missing products has to be predicted and the balanced equation has to be written for the combustion of Pentaborane (
Concept Introduction:
Combustion reaction:
When hydrocarbon reacts with oxygen to form carbon dioxide and water, the reaction is said to be combustion.
(c)
Interpretation:
The missing products has to be predicted and the balanced equation has to be written for the hydrolysis of trisilane (
Concept Introduction:
Hydrolysis:
Addition of water molecule to the reactant to form the product is known as hydrolysis.
(d)
Interpretation:
The missing products has to be predicted and the balanced equation has to be written for the complete halogenation of disilane with
Concept Introduction:
Halogenation:
The addition halogens (
(e)
Interpretation:
The missing products have to be predicted and the balanced equation has to be written for the thermal decomposition of
Concept Introduction:
Thermal decomposition:
It is an elimination reaction which occurs in presence of light. When a saturated reactant becomes an unsaturated (presence of double bond) product, the reaction is said to be elimination reaction. In elimination reaction, two products are formed from one reactant.
(f)
Interpretation:
The missing products has to be predicted and the balanced equation has to be written for the hydrolysis of
Concept Introduction:
Hydrolysis:
Addition of water molecule to the reactant to form the product is known as hydrolysis.
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Chapter 15 Solutions
Student Solutions Manual For Silberberg Chemistry: The Molecular Nature Of Matter And Change With Advanced Topics
- IX) By writing the appropriate electron configurations and orbital box diagrams briefly EXPLAIN in your own words each one of the following questions: a) The bond length of the Br2 molecule is 2.28 Å, while the bond length of the compound KBr is 3.34 Å. The radius of K✶ is 1.52 Å. Determine the atomic radius in Å of the bromine atom and of the bromide ion. Br = Br b) Explain why there is a large difference in the atomic sizes or radius of the two (Br and Br). Tarrow_forwardWhen 15.00 mL of 3.00 M NaOH was mixed in a calorimeter with 12.80 mL of 3.00 M HCl, both initially at room temperature (22.00 C), the temperature increased to 29.30 C. The resultant salt solution had a mass of 27.80 g and a specific heat capacity of 3.74 J/Kg. What is heat capacity of the calorimeter (in J/C)? Note: The molar enthalpy of neutralization per mole of HCl is -55.84 kJ/mol.arrow_forwardWhen 15.00 mL of 3.00 M NaOH was mixed in a calorimeter with 12.80 mL of 3.00 M HCl, both initially at room temperature (22.00 C), the temperature increased to 29.30 C. The resultant salt solution had a mass of 27.80 g and a specific heat capacity of 3.74 J/Kg. What is heat capacity of the calorimeter (in J/C)? Note: The molar enthalpy of neutralization per mole of HCl is -55.84 kJ/mol. Which experimental number must be initialled by the Lab TA for the first run of Part 1 of the experiment? a) the heat capacity of the calorimeter b) Mass of sample c) Ti d) The molarity of the HCl e) Tfarrow_forward
- Predict products for the Following organic rxn/s by writing the structurels of the correct products. Write above the line provided" your answer D2 ①CH3(CH2) 5 CH3 + D₂ (adequate)" + 2 mited) 19 Spark Spark por every item. 4 CH 3 11 3 CH 3 (CH2) 4 C-H + CH3OH CH2 CH3 + CH3 CH2OH 0 CH3 fou + KMnDy→ C43 + 2 KMn Dy→→ C-OH ") 0 C-OH 1110 (4.) 9+3 =C CH3 + HNO 3 0 + Heat> + CH3 C-OH + Heat CH2CH3 - 3 2 + D Heat H 3 CH 3 CH₂ CH₂ C = CH + 2 H₂ → 2 2arrow_forwardWhen 15.00 mL of 3.00 M NaOH was mixed in a calorimeter with 12.80 mL of 3.00 M HCl, both initially at room temperature (22.00 C), the temperature increased to 29.30 C. The resultant salt solution had a mass of 27.80 g and a specific heat capacity of 3.74 J/Kg. What is heat capacity of the calorimeter (in J/C)? Note: The molar enthalpy of neutralization per mole of HCl is -55.84 kJ/mol.arrow_forwardQ6: Using acetic acid as the acid, write the balanced chemical equation for the protonation of the two bases shown (on the -NH2). Include curved arrows to show the mechanism. O₂N- O₂N. -NH2 -NH2 a) Which of the two Bronsted bases above is the stronger base? Why? b) Identify the conjugate acids and conjugate bases for the reactants. c) Identify the Lewis acids and bases in the reactions.arrow_forward
- Q5: For the two reactions below: a) Use curved electron-pushing arrows to show the mechanism for the reaction in the forward direction. Redraw the compounds to explicitly illustrate all bonds that are broken and all bonds that are formed. b) Label Bronsted acids and bases in the left side of the reactions. c) For reaction A, which anionic species is the weakest base? Which neutral compound is the stronger acid? Is the forward or reverse reaction favored? d) Label Lewis acids and bases, nucleophiles and electrophiles in the left side of the reactions. A. 용 CH3OH я хон CH3O OH B. HBr CH3ONa NaBr CH3OHarrow_forwardpotential energy Br b) Translate the Newman projection below to its wedge-and-dash drawing. F H. OH CH3 CI c) Isopentane (2-methylbutane) is a compound containing a branched carbon chain. Draw a Newman projection of six conformations about the C2-C3 bond of isopentane. On the curve of potential energy versus angle of internal rotation for isopentane, label each energy maximum and minimum with one of the conformations. 0° 。 F A B D C angle of internal rotation E F 360° (=0°) JDownlarrow_forwardQ7: Identify the functional groups in these molecules a) CH 3 b) Aspirin: HO 'N' Capsaicin HO O CH3 CH 3arrow_forward
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