Explanation Given information: Each A992 steel member has a cross-sectional area of A = 1.5 in . 2 . Method adopted: Castigliano’s theorem to determine displacement and Method of Joints to determine the force in the member. Assumptions: Young’s modulus or modulus of elasticity of A992 steel is E = 29 ( 10 3 ) ksi . Explanation: Castigliano’s theorem for the entire truss is as follows: Δ = ∑ N ( ∂ N ∂ P ) L A E (1) Here, Δ is displacement of the truss joint, P an external force of variable magnitude applied to the truss joint in the direction of Δ , N is internal axial force in a member caused by both force P and the actual loads of the truss, L is length of a member, A is cross-sectional area of a member, and E is modulus of elasticity of a member. Internal axial force ( N ) in the member calculation: Apply a vertical external force P in the direction of displacement to be determined. Determine the reactions: Entire truss: Show the free-body diagram of the entire truss as on Figure 1. Moment about point A : Determine the vertical reaction at point C by taking moment about the point A . ∑ M A = 0 C y ( 16 ) − 2 ( 16 ) − 2 ( 8 ) − P ( 8 ) = 0 (2) Along the vertical direction: Determine the vertical reaction at point A by resolving the vertical component of forces. ∑ F y = 0 A y + C y − 2 − 2 − 2 − P = 0 (3) Along the horizontal direction: Determine the horizontal reaction at point A by resolving the horizontal component of forces. ∑ F x = 0 A x = 0 Show the calculation of values as follows: Solve Equation (2). C y ( 16 ) − 32 − 16 − 8 P = 0 C y = 3 + 0.5 P Substitute ( 3 + 0.5 P ) for C y in Equation (3). A y + 3 + 0.5 P − 6 − P = 0 A y = 3 + 0.5 P Joint C : Show the free-body diagram of the joint C as in Figure 2. Along the vertical direction: Determine the internal force in the member CD by resolving the vertical component of forces. ∑ F y = 0 C y − N C D = 0 (4) Along the horizontal direction: Determine the internal force in the member BC by resolving the horizontal component of forces. ∑ F x = 0 N B C = 0 Show the calculation of internal force in the members as follows: Substitute ( 3 + 0.5 P ) for C y in Equation (4). ( 3 + 0.5 P ) − N C D = 0 N C D = ( 3 + 0.5 P ) ( C ) Joint D : Show the free-body diagram of the joint D as in Figure 3. Determine the value of θ : tan θ = Opposite side Adjacent side (5) Along the vertical direction: Determine the internal force in the member BD by resolving the vertical component of forces. ∑ F y = 0 N C D − N B D sin θ − 2 = 0 (6) Along the horizontal direction: Determine the internal force in the member ED by resolving the horizontal component of forces. ∑ F x = 0 N E D − N B D cos θ = 0 (7) Show the calculation of internal force in the member as follows: Substitute 6 ft for opposite side and 8 ft for adjacent side in Equation (5). tan θ = 6 8 θ = 36.87 ° Substitute ( 3 + 0.5 P ) for N C D and 36.87 ° for θ in Equation (6). ( 3 + 0.5 P ) − N B D sin 36.87 ° − 2 = 0 N B D = 1 + 0.5 P sin 36.87 ° N B D = ( 1.67 + 0.833 P ) ( T ) Substitute ( 1.67 + 0.833 P ) for N B D and 36.87 ° for θ in Equation (7). N E D − ( 1.67 + 0.833 P ) cos 36.87 ° = 0 N E D = ( 1.34 + 0.667 P ) ( C ) Joint B : Show the free-body diagram of the joint B as in Figure 4. Along the vertical direction: Determine the internalforce in the member BE by resolving the vertical component of forces. ∑ F y = 0 N B D sin θ − N B E − P = 0 (8) Along the horizontal direction: Determine the internal force in the member AB by resolving the horizontal component of forces. ∑ F x = 0 N B C + N B D cos θ − N A B = 0 (9) Show the calculation of internal force as follows: Substitute ( 1

STANDALONE CODE MECHANICS OF MATERIALS-M

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ISBN: 9780137605200

Author: HIBBELER

Publisher: PEARSON

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Axial Load

When a bar of the uniform cross-section is acted by a load, such that the load acts along the longitudinal axis of the bar, such kinds of loadings are known as axial loadings. In general terms, a load is an external force acting on a component. An axial …

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Chapter 14.9, Problem 125P

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The vertical displacement of joint B.

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Chapter 14.9, Problem 124P

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Chapter 14 Solutions

STANDALONE CODE MECHANICS OF MATERIALS-M

Ch. 14.2 - A material is subjected to a general state of...Ch. 14.2 - The strain-energy density for plane stress must be...Ch. 14.2 - The A-36 steel bar consists of two segments, one...Ch. 14.2 - If P = 10 kip, determine the total strain energy...Ch. 14.2 - Determine the maximum force P and the...Ch. 14.2 - Consider the thin-walled tube of Fig.5-26 . Use...Ch. 14.2 - Determine the bending strain energy in the 2-in...Ch. 14.2 - Determine the bending strain energy in the...Ch. 14.2 - Determine the bending strain energy in the simply...Ch. 14.3 - Determine the horizontal displacement of joint A....

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The vertical displacement of joint B .

Solution Summary: The author explains Castigliano's theorem for the entire truss and Method of Joints to determine the force in the member.

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The vertical displacement of joint B.

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