Explanation Write the balance chemical reaction: CO+ 1 2 O 2 → z CO+ z 2 O 2 + ( 1 − z ) CO 2 (I) Here, amount of carbon monoxide in the mixture is z , amount of oxygen in the mixture is ( z 2 ) , and amount of carbon dioxide in the mixture is ( 1 − z ) . Write the expression for the total number of moles in the mixture: n = z + z 2 + ( 1 − z ) n = 2 + z 2 Write the expression for the number of moles of carbon monoxide in the mixture. y CO = z n (II) Write the expression for the number of moles of oxygen in the mixture. y O 2 = z / 2 n (III) Write the expression for the number of moles of carbon dioxide in the mixture. y CO 2 = 1 − z n (IV) Write the general reaction between the carbon monoxide and carbon dioxide. CO 2 ⇌ CO+ 1 2 O 2 Write the expression to calculate the equilibrium constant ( K P ) from the number of moles of reactants and products. K P = N H CO v CO N O 2 v O 2 N CO 2 v CO 2 ( P / P r e f n ) ( v CO + v O 2 − v CO 2 ) (V) Here, stoichiometric coefficient is v , number of moles of CO is N CO , number of moles of O 2 is N O 2 , number of moles of CO 2 is N CO 2 , pressure is P / P r e f , and the total number of moles of products is n

Fundamentals of Engineering Thermodynamics

8th Edition

ISBN: 9781118412930

Author: Michael J. Moran, Howard N. Shapiro, Daisie D. Boettner, Margaret B. Bailey

Publisher: WILEY

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Chapter 14.6, Problem 15CU

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Chapter 14.6, Problem 14CU

Chapter 14.6, Problem 16CU

Chapter 14 Solutions

Fundamentals of Engineering Thermodynamics

Ch. 14.6 - 1. Why is using the Gibbs function advantageous...Ch. 14.6 - Prob. 2E Ch. 14.6 - Prob. 3E Ch. 14.6 - Prob. 4E Ch. 14.6 - Prob. 5E Ch. 14.6 - Prob. 6E Ch. 14.6 - Prob. 7E Ch. 14.6 - Prob. 8E Ch. 14.6 - Prob. 9E Ch. 14.6 - Prob. 10E

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