Physics
5th Edition
ISBN: 9781260486919
Author: GIAMBATTISTA
Publisher: MCG
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Chapter 14.6, Problem 14.6CP
To determine
The material having the larger thermal
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(a) What magnification in multiples is produced by a 0.150 cm focal length microscope objective that is 0.160 cm from the object being viewed?
15.9
(b) What is the overall magnification in multiples if an eyepiece that produces a magnification of 7.90x is used?
126
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Gravitational Potential Energy
E =
кедо
Xo
A continuous line of charge lies along the x axis, extending from x = +x to positive infinity. The line carries positive charge with a uniform linear charge density 10.
(a) What is the magnitude of the electric field at the origin? (Use the following as necessary: 10, Xo, and ke.)
(b) What is the direction of the electric field at the origin?
O O O O O O G
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+x
-x
+y
Chapter 14 Solutions
Physics
Ch. 14.1 - 14.1 On the Rebound
If a rubber ball of mass 1.0...Ch. 14.1 - Prob. 14.2PPCh. 14.2 - CHECKPOINT 14.2
Take a rubber band and stretch it...Ch. 14.2 - Prob. 14.3PPCh. 14.3 - Prob. 14.3CPCh. 14.3 - Prob. 14.4PPCh. 14.3 - Prob. 14.5PPCh. 14.4 - Prob. 14.6PPCh. 14.5 - Prob. 14.5CPCh. 14.5 - Prob. 14.7PP
Ch. 14.5 - Prob. 14.8PPCh. 14.5 - Prob. 14.9PPCh. 14.6 - Prob. 14.6CPCh. 14.6 - Prob. 14.10PPCh. 14.6 - Prob. 14.11PPCh. 14.8 - Prob. 14.12PPCh. 14.8 - Prob. 14.8CPCh. 14.8 - Prob. 14.13PPCh. 14.8 - Prob. 14.14PPCh. 14.8 - Prob. 14.15PPCh. 14 - Prob. 1CQCh. 14 - Prob. 2CQCh. 14 - 3. Why do lakes and rivers freeze first at their...Ch. 14 - Prob. 4CQCh. 14 - Prob. 5CQCh. 14 - Prob. 6CQCh. 14 - Prob. 7CQCh. 14 - Prob. 8CQCh. 14 - 9. What is the purpose of having fins on an...Ch. 14 - Prob. 10CQCh. 14 - Prob. 11CQCh. 14 - 12. Explain the theory behind the pressure cooker....Ch. 14 - Prob. 13CQCh. 14 - Prob. 14CQCh. 14 - Prob. 15CQCh. 14 - Prob. 16CQCh. 14 - Prob. 17CQCh. 14 - Prob. 18CQCh. 14 - Prob. 19CQCh. 14 - Prob. 20CQCh. 14 - Prob. 21CQCh. 14 - Prob. 22CQCh. 14 - Prob. 23CQCh. 14 - Prob. 24CQCh. 14 - Prob. 25CQCh. 14 - Prob. 26CQCh. 14 - 1. The main loss of heat from Earth is by
(a)...Ch. 14 - Prob. 2MCQCh. 14 - Prob. 3MCQCh. 14 - Prob. 4MCQCh. 14 - Prob. 5MCQCh. 14 - Prob. 6MCQCh. 14 - Prob. 7MCQCh. 14 - Prob. 8MCQCh. 14 - Prob. 9MCQCh. 14 - Prob. 10MCQCh. 14 - Prob. 11MCQCh. 14 - Prob. 12MCQCh. 14 - Prob. 1PCh. 14 - Prob. 2PCh. 14 - Prob. 3PCh. 14 - Prob. 4PCh. 14 - Prob. 5PCh. 14 - Prob. 6PCh. 14 - Prob. 7PCh. 14 - Prob. 8PCh. 14 - Prob. 9PCh. 14 - Prob. 10PCh. 14 - Prob. 11PCh. 14 - Prob. 12PCh. 14 - Prob. 13PCh. 14 - Prob. 14PCh. 14 - Prob. 15PCh. 14 - Prob. 16PCh. 14 - Prob. 17PCh. 14 - Prob. 18PCh. 14 - Prob. 19PCh. 14 - Prob. 20PCh. 14 - Prob. 21PCh. 14 - Prob. 22PCh. 14 - Prob. 23PCh. 14 - Prob. 24PCh. 14 - Prob. 25PCh. 14 - Prob. 26PCh. 14 - Prob. 27PCh. 14 - Prob. 28PCh. 14 - Prob. 29PCh. 14 - Prob. 30PCh. 14 - Prob. 31PCh. 14 - Prob. 32PCh. 14 - Prob. 33PCh. 14 - Prob. 34PCh. 14 - Prob. 35PCh. 14 - Prob. 36PCh. 14 - Prob. 37PCh. 14 - Prob. 38PCh. 14 - Prob. 39PCh. 14 - Prob. 40PCh. 14 - Prob. 41PCh. 14 - Prob. 42PCh. 14 - Prob. 43PCh. 14 - Prob. 44PCh. 14 - 45. Is it possible to heat the aluminum of Problem...Ch. 14 - Prob. 46PCh. 14 - Prob. 47PCh. 14 - Prob. 48PCh. 14 - Prob. 49PCh. 14 - Prob. 50PCh. 14 - Prob. 51PCh. 14 - Prob. 53PCh. 14 - Prob. 52PCh. 14 - Prob. 54PCh. 14 - Prob. 55PCh. 14 - Prob. 56PCh. 14 - Prob. 57PCh. 14 - Prob. 58PCh. 14 - Prob. 59PCh. 14 - Prob. 60PCh. 14 - Prob. 61PCh. 14 - Prob. 62PCh. 14 - Prob. 63PCh. 14 - Prob. 64PCh. 14 - Prob. 65PCh. 14 - Prob. 66PCh. 14 - 67. One cross-country skier is wearing a down...Ch. 14 - Prob. 68PCh. 14 - Prob. 69PCh. 14 - Prob. 70PCh. 14 - Prob. 71PCh. 14 - Prob. 72PCh. 14 - Prob. 73PCh. 14 - Prob. 74PCh. 14 - Prob. 75PCh. 14 - Prob. 76PCh. 14 - Prob. 77PCh. 14 - Prob. 78PCh. 14 - Prob. 79PCh. 14 - Prob. 80PCh. 14 - Prob. 81PCh. 14 - Prob. 82PCh. 14 - Prob. 83PCh. 14 - Prob. 84PCh. 14 - Prob. 85PCh. 14 - Prob. 86PCh. 14 - Prob. 87PCh. 14 - Prob. 88PCh. 14 - Prob. 89PCh. 14 - Prob. 93PCh. 14 - Prob. 91PCh. 14 - Prob. 92PCh. 14 - Prob. 94PCh. 14 - Prob. 95PCh. 14 - Prob. 96PCh. 14 - Prob. 97PCh. 14 - Prob. 98PCh. 14 - Prob. 99PCh. 14 - Prob. 100PCh. 14 - Prob. 101PCh. 14 - Prob. 102PCh. 14 - Prob. 103PCh. 14 - Prob. 104PCh. 14 - Prob. 105PCh. 14 - Prob. 106PCh. 14 - Prob. 107PCh. 14 - Prob. 108PCh. 14 - Prob. 109PCh. 14 - Prob. 110PCh. 14 - Prob. 112PCh. 14 - Prob. 111PCh. 14 - 116. It requires 17.10 kJ to melt 1.00 × 102 g of...Ch. 14 - Prob. 113PCh. 14 - Prob. 90PCh. 14 - Prob. 115PCh. 14 - Prob. 116PCh. 14 - Prob. 117PCh. 14 - Prob. 118PCh. 14 - Prob. 119PCh. 14 - Prob. 120P
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- Include free body diagramarrow_forward2 Spring 2025 -03 PITT Calculate the acceleration of a skier heading down a 10.0° slope, assuming the coefficient of cold coast at a constant velocity. You can neglect air resistance in both parts. friction for waxed wood on wet snow fly 0.1 (b) Find the angle of the slope down which this skier Given: 9 = ? 8=10° 4=0.1arrow_forwarddry 5. (a) When rebuilding her car's engine, a physics major must exert 300 N of force to insert a c piston into a steel cylinder. What is the normal force between the piston and cyli=030 What force would she have to exert if the steel parts were oiled? k F = 306N 2 =0.03 (arrow_forward
- Include free body diagramarrow_forwardInclude free body diagramarrow_forwardTest 2 МК 02 5. (a) When rebuilding her car's engine, a physics major must exert 300 N of force to insert a dry = 0.03 (15 pts) piston into a steel cylinder. What is the normal force between the piston and cylinder? What force would she have to exert if the steel parts were oiled? Mk Giren F = 306N MK-0.3 UK = 0.03 NF = ?arrow_forward
- 2. A powerful motorcycle can produce an acceleration of 3.50 m/s² while traveling at 90.0 km/h. At that speed the forces resisting motion, including friction and air resistance, total 400 N. (Air resistance is analogous to air friction. It always opposes the motion of an object.) What force does the motorcycle exert backward on the ground to produce its acceleration if the mass of the motorcycle with rider is 245 ke? a = 350 m/s 2arrow_forward2. A powerful motorcycle can produce an acceleration of 3.50 m/s² while traveling at 90.0 km/h. At that speed the forces resisting motion, including friction and air resistance, total 400 N. (Air resistance is analogous to air friction. It always opposes the motion of an object.) What force does the motorcycle exert backward on the ground to produce its acceleration if the mass of the motorcycle with rider is 245 kg? (10 pts) a = 3.50 m/s 2 distance 90 km/h = 3.50m/62 M = 245garrow_forwardUsing Table 17-4, determine the approximate temperature of metal that has formed a dark blue color.arrow_forward
- A positively charged disk has a uniform charge per unit area σ. dq R P x The total electric field at P is given by the following. Ek [2 - x (R² + x2) 1/2 Sketch the electric field lines in a plane perpendicular to the plane of the disk passing through its center.arrow_forwardConsider a closed triangular box resting within a horizontal electric field of magnitude E = 8.02 104 N/C as shown in the figure below. A closed right triangular box with its vertical side on the left and downward slope on the right rests within a horizontal electric field vector E that points from left to right. The box has a height of 10.0 cm and a depth of 30.0 cm. The downward slope of the box makes an angle of 60 degrees with the vertical. (a) Calculate the electric flux through the vertical rectangular surface of the box. kN · m2/C(b) Calculate the electric flux through the slanted surface of the box. kN · m2/C(c) Calculate the electric flux through the entire surface of the box. kN · m2/Carrow_forwardThe figure below shows, at left, a solid disk of radius R = 0.600 m and mass 75.0 kg. Tu Mounted directly to it and coaxial with it is a pulley with a much smaller mass and a radius of r = 0.230 m. The disk and pulley assembly are on a frictionless axle. A belt is wrapped around the pulley and connected to an electric motor as shown on the right. The turning motor gives the disk and pulley a clockwise angular acceleration of 1.67 rad/s². The tension T in the upper (taut) segment of the belt is 145 N. (a) What is the tension (in N) in the lower (slack) segment of the belt? N (b) What If? You replace the belt with a different one (one slightly longer and looser, but still tight enough that it does not sag). You again turn on the motor so that the disk accelerates clockwise. The upper segment of the belt once again has a tension of 145 N, but now the tension in the lower belt is exactly zero. What is the magnitude of the angular acceleration (in rad/s²)? rad/s²arrow_forward
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