Explanation Given: The interval [ 0 , 8 ] is partitioned into four subintervals [ 0 , 2 ] , [ 2 , 4 ] , [ 4 , 6 ] and [ 6 , 8 ] . Calculation: Each of length 2, and choose u as right end point. The area A is approximated as A = f ( 2 ) 2 + f ( ...

11th Edition

ISBN: 9780135228982

Author: Sullivan

Publisher: PEARSON

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Chapter 14.5, Problem 8AYU

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To solve: The interval $[0, 8]$ is partitioned into four subintervals $[0, 2]$ , $[2, 4]$ , $[4, 6]$ and $[6, 8]$ .

Approximate the area $A$ choosing $u$ as the right endpoint of each subinterval.

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Chapter 14.5, Problem 7AYU

Chapter 14.5, Problem 9AYU

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The interval [ 0 , 8 ] is partitioned into four subintervals [ 0 , 2 ] , [ 2 , 4 ] , [ 4 , 6 ] and [ 6 , 8 ] . Approximate the area A choosing u as the right endpoint of each subinterval.

Solution Summary: The author explains how the interval [0, 8] is partitioned into four subintervals and calculates the area A using u as the right endpoint.

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To solve: The interval $[0, 8]$ is partitioned into four subintervals $[0, 2]$ , $[2, 4]$ , $[4, 6]$ and $[6, 8]$ .

Approximate the area $A$ choosing $u$ as the right endpoint of each subinterval.

Want to see the full answer?

Chapter 14 Solutions

Additional Math Textbook Solutions

The interval [ 0 , 8 ] is partitioned into four subintervals [ 0 , 2 ] , [ 2 , 4 ] , [ 4 , 6 ] and [ 6 , 8 ] . Approximate the area A choosing u as the right endpoint of each subinterval.

Solution Summary: The author explains how the interval [0, 8] is partitioned into four subintervals and calculates the area A using u as the right endpoint.

Concept explainers

Videos

To solve: The interval [ 0, 8 ] is partitioned into four subintervals [ 0, 2 ] , [ 2, 4 ] , [ 4, 6 ] and [ 6, 8 ] . Approximate the area A choosing u as the right endpoint of each subinterval.

Want to see the full answer?

Chapter 14 Solutions

Additional Math Textbook Solutions

To solve: The interval $[0, 8]$ is partitioned into four subintervals $[0, 2]$ , $[2, 4]$ , $[4, 6]$ and $[6, 8]$ .

Approximate the area $A$ choosing $u$ as the right endpoint of each subinterval.