Explanation Given: R = 30 m V = 30 m / min Tangential deceleration a T = 15 m / min 2 Formula used: a R = V 2 R Calculation: The motion of a person in a car on a Ferris wheel is similar to a circular motion. In a circular motion the net acceleration of a body has two components as radial or centripetal acceleration and tangential acceleration. That is a → = a R → + a T → The radial acceleration is directed towards the centre and because of this acceleration the body follows a circular path. The radial acceleration is calculated as a R = V 2 R = ( 40 ) 2 30 = 160 3 m / min 2 At the highest point of Ferris wheel the radial acceleration acts in vertically downwards direction... To determine (b) The acceleration vector of a person sitting in a car at two points level with the center of the Ferris wheel.

4th Edition

ISBN: 9781319055844

Author: FRANZOSA

Publisher: VST

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Chapter 14.5, Problem 46E

To determine

(a)

The acceleration vector of a person sitting in a car at the highest point of a Ferris wheel.

To determine

(b)

The acceleration vector of a person sitting in a car at two points level with the center of the Ferris wheel.

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Chapter 14.5, Problem 45E

Chapter 14.5, Problem 47E

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Ch. 14.1 - Prob. 1PQ Ch. 14.1 - Prob. 2PQ Ch. 14.1 - Prob. 3PQ Ch. 14.1 - Prob. 4PQ Ch. 14.1 - Prob. 5PQ Ch. 14.1 - Prob. 6PQ Ch. 14.1 - Prob. 1E Ch. 14.1 - Prob. 2E Ch. 14.1 - Prob. 3E Ch. 14.1 - Prob. 4E

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(a) The acceleration vector of a person sitting in a car at the highest point of a Ferris wheel.

Solution Summary: The author explains how the acceleration vector of a person sitting in the car at the highest point of the Ferris wheel is calculated.