Explanation Given Information: The provided equations are as follows: 3 x − 5 = 3 , 3 x + 1 = 2 x + 3 , 3 x + 1 = x + 12 , x − 1 = x + 5 , 1 + 1 − x = x And x − 1 = x − 3 Calculation: Consider the equation, 3 x − 5 = 3 Steps to calculate the solution of the equation by using Ti- 83 graphing calculator are as follows: Step1: Press ON key. Step2: Press “ Y = ” key and insert the equations as, Y 1 = ( 3X ) − 5 Y 2 = 3 Step3: Set the window as, X min = 0 X max = 40 X scl = 5 Y min = − 5 And, Y max = 10 Yscl = 1 Step4: Press the “ 2 nd ” key, then “TRACE” key and then press 5 . Step5: Press the “TRACE” key followed by pressing “ENTER” key thrice, the window will appear as, The solution of the equation is x = 21.333333 . Consider the equation, 3 x + 1 = 2 x + 3 Steps to calculate the solution of the equation by using Ti- 83 graphing calculator are as follows: Step1: Press ON key. Step2: Press “ Y = ” key and insert the equations as, Y 1 = ( 3X + 1 ) Y 2 = ( 2X + 3 ) Step3: Set the “WINDOW” as, X min = − 2 X max = 10 X scl = 1 Y min = 0 And, Y max = 10 Yscl = 1 Step4: Press the “ 2 nd ” key, then “TRACE” key and then press 5 . Step5: Press the “TRACE” key followed by pressing “ENTER” key thrice, the window will appear as, The solution of the equation is x = 2 . Consider the equation, 3 x + 1 = x + 12 Steps to calculate the solution of the equation by using Ti- 83 graphing calculator are as follows: Step1: Press ON key. Step2: Press “ Y = ” key and insert the equations as, Y 1 = 3 ( X + 1 ) Y 2 = ( X + 12 ) Step3: Set the “WINDOW” as, X min = − 2 X max = 4 X scl = 2 Y min = − 2 And, Y max = 4 Yscl = 2 Step4: Press the “ 2 nd ” key, then “TRACE” key and then press 5 . Step5: Press the “TRACE” key followed by pressing “ENTER” key thrice, the window will appear as, The solution of the equation is x = 0.375 . Consider the equation, x − 1 = x + 5 Steps to calculate the solution of the equation by using Ti- 83 graphing calculator are as follows: Step1: Press ON key

9th Edition

ISBN: 9780321997173

Author: Marvin L. Bittinger, Judith A. Beecher

Publisher: PEARSON

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Question

Chapter 14.5, Problem 2CCE1

To determine

To calculate: The solution of the following equations by using the graphing utility,

3x−5=3,3x+1=2x+3,3x+1=x+12,x−1=x+5,1+1−x=x And

x−1=x−3

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Chapter 14.5, Problem 1CCE1

Chapter 14.5, Problem 6DE

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Chapter 14 Solutions

Developmental Mathematics (9th Edition)

Ch. 14.1 - Prob. 1SR Ch. 14.1 - Prob. 2SR Ch. 14.1 - Prob. 1DE Ch. 14.1 - Prob. 2DE Ch. 14.1 - Prob. 3DE Ch. 14.1 - Prob. 4DE Ch. 14.1 - Prob. 5DE Ch. 14.1 - Prob. 6DE Ch. 14.1 - Prob. 7DE Ch. 14.1 - Prob. 8DE

Knowledge Booster

The solution of the following equations by using the graphing utility, 3 x − 5 = 3 , 3 x + 1 = 2 x + 3 , 3 x + 1 = x + 12 , x − 1 = x + 5 , 1 + 1 − x = x And x − 1 = x − 3

Solution Summary: The author calculates the solution of the following equations by using the graphing utility.

To calculate: The solution of the following equations by using the graphing utility,

3x−5=3,3x+1=2x+3,3x+1=x+12,x−1=x+5,1+1−x=x And

x−1=x−3

Want to see the full answer?

Chapter 14 Solutions

The solution of the following equations by using the graphing utility, 3 x − 5 = 3 , 3 x + 1 = 2 x + 3 , 3 x + 1 = x + 12 , x − 1 = x + 5 , 1 + 1 − x = x And x − 1 = x − 3

Solution Summary: The author calculates the solution of the following equations by using the graphing utility.

To calculate: The solution of the following equations by using the graphing utility, 3x−5=3,3x+1=2x+3,3x+1=x+12,x−1=x+5,1+1−x=x And x−1=x−3

Want to see the full answer?

Chapter 14 Solutions

To calculate: The solution of the following equations by using the graphing utility,

3x−5=3,3x+1=2x+3,3x+1=x+12,x−1=x+5,1+1−x=x And

x−1=x−3