Explanation Theorem used: Pythagorean theorem: In a right angled triangle, the square of the hypotenuse side is equal to the sum of squares of the other two sides. That is c 2 = a 2 + b 2 . Formula used: For a quadratic equation of the form a x 2 + b x + c = 0 the solutions are x 1 , 2 = − b ± b 2 − 4 a c 2 a . Calculation: Let x be the length of edge of small box and y be the length of edge of larger box. It is given that the edge of the larger box is 1.00 in. greater than that of the small box. That is, y = x + 1 . From given figure it is observed that the tape covered 3 sides of large box and one side of the small box. Redraw the given figure as follows. By using the Pythagorean theorem, the remaining two sides can be calculated as 2 x 2 + 0.50 2 . Thus, total tape covered is 3 y + x + 2 x 2 + 0.50 2 = 100 . Write the equation in terms of x . 3 x + 3 + x + 2 x 2 + 0.50 2 = 100 2 x 2 + 0.50 2 = 97 − 4 x ( 2 x 2 + 0.50 2 ) 2 = ( 97 − 4 x ) 2 [ Square both sides ] 4 ( x 2 + 0.50 2 ) = 9409 − 776 x + 16 x 2 On further simplification, 4 x 2 + 1 = 9409 − 776 x + 16 x 2 12 x 2 − 776 x + 9408 = 0 3 x 2 − 194 x + 2352 = 0 x = − ( − 194 ) ± ( − 194 ) 2 − 4 ( 3 ) ( 2352 ) 2 ( 3 ) On further simplification, x = 194 ± 37636 − 28224 6 x = 97 + 2353 6 or x = 97 − 2353 6 x = 48

Student Solutions Manual For Basic Technical Mathematics And Basic Technical Mathematics With Calculus

11th Edition

ISBN: 9780134434636

Author: Allyn J. Washington, Richard Evans

Publisher: PEARSON

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Chapter 14.4, Problem 48E

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The lengths of the edges of the boxes.

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Chapter 14.4, Problem 47E

Chapter 14.4, Problem 49E

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Chapter 14 Solutions

Student Solutions Manual For Basic Technical Mathematics And Basic Technical Mathematics With Calculus

Ch. 14.1 - In Example 7, determine how many times the rocket...Ch. 14.1 - Prob. 1E Ch. 14.1 - Prob. 2E Ch. 14.1 - Prob. 3E Ch. 14.1 - Prob. 4E Ch. 14.1 - Prob. 5E Ch. 14.1 - Prob. 6E Ch. 14.1 - Prob. 7E Ch. 14.1 - Prob. 8E Ch. 14.1 - Prob. 9E

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