Explanation Given: f ( x ) = x 3 + x 2 − 2 x c = 1 Formula used: The derivative of y = f ( x ) at c is given by: f ′ ( c ) = lim x → c f ( x ) − f ( c ) x − c Calculation: Here, f ( x ) = x 3 + x 2 − 2 x and c = 1 . f ( c ) = f ( 1 ) = 1 3 + 1 2 − 2 ( 1 ) = 2 − 2 = 0 Therefore, f ′ ( 1 ) = lim x → 1 f ( x ) − f ( 1 ) x − 1 f ′ ( 1 ) = lim x → 1 ( x 3 + x 2 − 2 x ) ...

10th Edition

ISBN: 8220101460912

Author: Sullivan

Publisher: PEARSON

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Chapter 14.4, Problem 29AYU

To determine

To find: The derivative of $f (x) = x^{3} + x^{2} - 2 x$ at 1.

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Chapter 14.4, Problem 28AYU

Chapter 14.4, Problem 30AYU

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Question 4 Find an equation of (a) The plane through the point (2, 0, 1) and perpendicular to the line x = y=2t, z=3+4t. 3t, (b) The plane through the point (3, −2, 8) and parallel to the plane z = x+y. (c) The plane that contains the line x = parallel to the plane 5x + 2y + z = 1. 1+t, y2t, z = 43t and is (d) The plane that passes through the point (1,2,3) and contains the line x = 3t, y=1+t, and z = 2 – t. (e) The plane that contains the lines L₁ : x = 1 + t, y = 1 − t, z = = L2 x 2s, y = s, z = 2. 2t and

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Chapter 14 Solutions

EBK PRECALCULUS

Ch. 14.1 - Graph f( x )={ 3x2ifx2 3ifx=2 (pp.100-102)Ch. 14.1 - Prob. 2AYU Ch. 14.1 - Prob. 3AYU Ch. 14.1 - Prob. 4AYU Ch. 14.1 - True or False lim xc f( x )=N may be described by...Ch. 14.1 - Prob. 6AYU Ch. 14.1 - lim x2 ( 4 x 3 )Ch. 14.1 - lim x3 ( 2 x 2 +1 )Ch. 14.1 - Prob. 9AYU Ch. 14.1 - Prob. 10AYU

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