Explanation Given: The function given is f ( x ) = 6 x 2 ( 1 − x ) . Approach: Substitute f ( x ) = x and find the equilibrium points. If a function having an equilibrium point then that point is stable if | f ′ ( c ) < 1 | and unstable if | f ′ ( c ) > 1 | . Calculation: Substitute f ( x ) = x to find the equilibrium point of the given function. x = 6 x 2 ( 1 − x ) 6 x 3 − 6 x 2 + x = 0 x ( 6 x 2 − 6 x + 1 ) = 0 x = 0 , 6 ±

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ISBN: 9780321964038

Author: GREENWELL, Raymond N., RITCHEY, Nathan P., Lial, Margaret L.

Publisher: Pearson Addison Wesley,

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Chapter 14.3, Problem 3E

To determine

To find:

The stability of any equilibrium point in the given interval [0,1]

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Chapter 14.3, Problem 2E

Chapter 14.3, Problem 4E

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Ch. 14.1 - YOUR TURN 1 Find the first four terms of the...Ch. 14.1 - Prob. 2YT Ch. 14.1 - Prob. 3YT Ch. 14.1 - Prob. 4YT Ch. 14.1 - Prob. 1E Ch. 14.1 - Prob. 2E Ch. 14.1 - Prob. 3E Ch. 14.1 - Prob. 4E Ch. 14.1 - Prob. 5E Ch. 14.1 - Prob. 6E

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The stability of any equilibrium point in the given interval [ 0 , 1 ]

Solution Summary: The author explains that the given function is unstable at equilibrium point x=0.211,.788.

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To find:

The stability of any equilibrium point in the given interval [0,1]

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Chapter 14 Solutions

The stability of any equilibrium point in the given interval [ 0 , 1 ]

Solution Summary: The author explains that the given function is unstable at equilibrium point x=0.211,.788.

Concept explainers

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To find: The stability of any equilibrium point in the given interval [0,1]

Want to see the full answer?

Chapter 14 Solutions

To find:

The stability of any equilibrium point in the given interval [0,1]