Essentials of Statistics for The Behavioral Sciences (MindTap Course List)
9th Edition
ISBN: 9781337098120
Author: Frederick J Gravetter, Larry B. Wallnau, Lori-Ann B. Forzano
Publisher: Cengage Learning
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Chapter 14.3, Problem 1LC
A researcher obtains a strong
- a. Decreasing the amount of violence that the children see on TV will reduce their aggressive behavior.
- b. Increasing the amount of violence that the children see on TV will increase their aggressive behavior.
- c. Children who watch more TV violence tend to exhibit more aggressive behavior
- d. All of the above
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A normal distribution has a mean of 50 and a standard deviation of 4. Solve the following three parts?
1. Compute the probability of a value between 44.0 and 55.0.
(The question requires finding probability value between 44 and 55. Solve it in 3 steps.
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In the second step repeat the first step with the only difference that x=55.
In the third step, subtract the answer of the first part from the answer of the second part.)
2. Compute the probability of a value greater than 55.0.
Use the same formula, x=55 and subtract the answer from 1.
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In the second step repeat the first step with the only difference that x=55.
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The best way to solve this problem is begin by a step by step creating a chart. Clearly mark the range, identifying the…
Client
1
Weight before
diet (pounds)
Weight after
diet (pounds)
128
120
2
131
123
3
140
141
4
178
170
5
121
118
6
136
136
7
118
121
8
136
127
Chapter 14 Solutions
Essentials of Statistics for The Behavioral Sciences (MindTap Course List)
Ch. 14.1 - Which of the following is a justified conclusion...Ch. 14.1 - Which of the following correlations indicates the...Ch. 14.2 - What is the value of SP for a set of n 5 pairs of...Ch. 14.2 - A set of n = 5 pairs of X and Y scores has SSx =...Ch. 14.2 - Prob. 3LCCh. 14.3 - A researcher obtains a strong positive correlation...Ch. 14.3 - A set of n = 10 pairs of X and Y values produces a...Ch. 14.4 - Prob. 1LCCh. 14.4 - The Pearson correlation is calculated for a sample...Ch. 14.5 - Prob. 1LC
Ch. 14.5 - Prob. 2LCCh. 14.5 - Prob. 3LCCh. 14.5 - A researcher would like to measure the...Ch. 14.6 - In the general linear equation Y = bX + a, what is...Ch. 14.6 - A set of n = 25 pairs of X and Y values has Mx =...Ch. 14.6 - Prob. 3LCCh. 14.6 - A researcher computes the regression equation for...Ch. 14 - Calculate SP (the sum of products of deviations)...Ch. 14 - Calculate SP (the sum of products of deviations)...Ch. 14 - For the following scores, X Y 2 7 5 4 4 7 7 5 2 6...Ch. 14 - For the following scores, X Y 0 4 2 9 1 6 1 9 a....Ch. 14 - For the following scores, X Y 4 0 1 5 1 0 4 5 a....Ch. 14 - For the following scores, X Y 3 6 5 5 6 0 6 2 5 2...Ch. 14 - With a small sample, a single point can have a...Ch. 14 - For the following set of scores, X Y 4 5 6 5 3 2 9...Ch. 14 - At the beginning of this chapter we discussed a...Ch. 14 - For a two-tailed test with = .05 use Table B.6 to...Ch. 14 - It appears that there is a significant...Ch. 14 - Sketch a graph showing the line for the equation Y...Ch. 14 - A set of n =18 pairs of scores (X and Y values)...Ch. 14 - A set of n = 15 pairs of scores (X and Y values)...Ch. 14 - Briefly explain what is measured by the standard...Ch. 14 - In general, how is the magnitude of the standard...Ch. 14 - For the following set of data, find the linear...Ch. 14 - For the following data: a. Find the regression...Ch. 14 - For the following scores: X Y 3 8 5 8 2 6 2 3 4 6...Ch. 14 - The regression equation is computed for a set of n...Ch. 14 - Solve the following problems. a. One set of 10...Ch. 14 - Does the regression equation from Problem 20...Ch. 14 - Solve the following problems. a. A researcher...
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- Client 1 Weight before diet (pounds) Weight after diet (pounds) 128 120 2 131 123 3 140 141 4 178 170 5 121 118 6 136 136 7 118 121 8 136 127 a) Determine the mean change in patient weight from before to after the diet (after – before). What is the 95% confidence interval of this mean difference?arrow_forwardIn order to find probability, you can use this formula in Microsoft Excel: The best way to understand and solve these problems is by first drawing a bell curve and marking key points such as x, the mean, and the areas of interest. Once marked on the bell curve, figure out what calculations are needed to find the area of interest. =NORM.DIST(x, Mean, Standard Dev., TRUE). When the question mentions “greater than” you may have to subtract your answer from 1. When the question mentions “between (two values)”, you need to do separate calculation for both values and then subtract their results to get the answer. 1. Compute the probability of a value between 44.0 and 55.0. (The question requires finding probability value between 44 and 55. Solve it in 3 steps. In the first step, use the above formula and x = 44, calculate probability value. In the second step repeat the first step with the only difference that x=55. In the third step, subtract the answer of the first part from the…arrow_forwardIf a uniform distribution is defined over the interval from 6 to 10, then answer the followings: What is the mean of this uniform distribution? Show that the probability of any value between 6 and 10 is equal to 1.0 Find the probability of a value more than 7. Find the probability of a value between 7 and 9. The closing price of Schnur Sporting Goods Inc. common stock is uniformly distributed between $20 and $30 per share. What is the probability that the stock price will be: More than $27? Less than or equal to $24? The April rainfall in Flagstaff, Arizona, follows a uniform distribution between 0.5 and 3.00 inches. What is the mean amount of rainfall for the month? What is the probability of less than an inch of rain for the month? What is the probability of exactly 1.00 inch of rain? What is the probability of more than 1.50 inches of rain for the month? The best way to solve this problem is begin by creating a chart. Clearly mark the range, identifying the lower and upper…arrow_forward
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